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True/False: You are more likely to get a pattern of HTHHHTHTTH than HHHHHHHHTT when you flip a coin 10 times.

Short Answer

Expert verified
False, both sequences have equal probability of occurring.

Step by step solution

01

Understand the Problem

When flipping a coin 10 times, we are looking at the probability of getting specific sequences (HTHHHTHTTH and HHHHHHHHTT), which means counting the ways each sequence can occur.
02

Recognize Each Flip's Probability

Each flip of a fair coin has two possible outcomes: Heads (H) or Tails (T). Thus, the probability of any specific sequence of outcomes occurring in a series of flips is determined by the individual probabilities of each flip.
03

Calculate Probability of Any 10-Flip Sequence

The probability of obtaining any specific sequence of 10 coin flips is \[\left(\frac{1}{2}\right)^{10} = \frac{1}{1024}.\]This is because each coin flip is independent, and there are two possible outcomes per flip.
04

Conclude Equivalence of Sequences

Both sequences HTHHHTHTTH and HHHHHHHHTT are specific sequences of 10 flips. Therefore, each has a probability of \(\frac{1}{1024}\) of occurring. Thus, neither sequence is more likely than the other.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Independent Events
When we refer to independent events in probability, we mean that the outcome of one event does not affect the outcome of another. This is a crucial concept to understand when dealing with coin flips. Each time you flip a coin, the result—either heads (H) or tails (T)—does not influence the next flip. This independence implies that each flip has no memory and cannot predict or affect the future flips.

In the problem of flipping a coin 10 times, each flip is an independent event. Whether the first flip comes out heads or tails has no bearing on whether the second flip will do the same. This characteristic of coin flips ensures that each sequence of flips, such as HTHHHTHTTH or HHHHHHHHTT, is equally probable. Recognizing the independence of each flip simplifies the calculation of probabilities for sequences of outcomes.
Coin Flip
Flipping a coin is one of the most basic examples of a random experiment, commonly used in probability theory. A coin flip typically has two possible outcomes: heads (H) or tails (T). The probability of getting heads in a single coin flip is \( rac{1}{2}\), and similarly, the probability of getting tails is also \( rac{1}{2}\). This makes a fair coin flip a perfect model for understanding randomness and probability.

When you flip a coin multiple times, the outcomes of each flip accumulate to form a sequence. For example, a sequence of 10 flips could yield outcomes like HTHHHTHTTH or HHHHHHHHTT. Understanding the fundamental 50/50 chance for each flip aids in calculating the likelihood of any specific sequence of outcomes over a series of flips. Each specific sequence occurs with a probability of \( rac{1}{1024}\), highlighting the concept of extremely low odds when exact repetitions are demanded.
Specific Sequences
Specific sequences in the context of coin flips refer to predetermined sets of outcomes stemming from multiple flips. Let's say you want an exact sequence of heads and tails, like HTHHHTHTTH. Each individual flip's outcome is independent and follows a simple probability rule, but when looking to achieve a specific sequence, the complexity seems to increase.

Yet, despite this perceived complexity, the real probability associated with any specific sequence in a set of 10 coin flips remains straightforward. Since each flip is independent and comes with a \( rac{1}{2}\) chance, the probability for any sequence of 10 flips becomes \(\left(\frac{1}{2}\right)^{10} = \frac{1}{1024}\). This logic holds true regardless of whether the sequence looks random like HTHHHTHTTH or regular like HHHHHHHHTT. Therefore, every specific combination has the same chance of appearing in a random batch of flips, demonstrating the inherent fairness and unpredictability of chance events.

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Most popular questions from this chapter

The following questions are from ARTIST (reproduced with permission) If Tahnee flips a coin 10 times, and records the results (Heads or Tails), which outcome below is more likely to occur, A or B? Explain your choice. $$ \begin{array}{|c|c|c|c|c|c|c|c|c|c|c|} \hline \text { Throw Number } & \mathbf{1} & \mathbf{2} & \mathbf{3} & \mathbf{4} & \mathbf{5} & \mathbf{6} & \mathbf{7} & \mathbf{8} & \mathbf{9} & \mathbf{1 0} \\ \hline \mathbf{A} & \mathrm{H} & \mathrm{T} & \mathrm{T} & \mathrm{H} & \mathrm{T} & \mathrm{H} & \mathrm{H} & \mathrm{T} & \mathrm{T} & \mathrm{T} \\\ \hline \mathbf{B} & \mathrm{H} & \mathrm{T} & \mathrm{H} & \mathrm{T} & \mathrm{H} & \mathrm{T} & \mathrm{H} & \mathrm{T} & \mathrm{H} & \mathrm{T} \\\ \hline \end{array} $$

A jar contains 10 blue marbles, 5 red marbles, 4 green marbles, and 1 yellow marble. Two marbles are chosen (without replacement). (a) What is the probability that one will be green and the other red? (b) What is the probability that one will be blue and the other yellow?

The following questions are from ARTIST (reproduced with permission) An insurance company writes policies for a large number of newly-licensed drivers each year. Suppose \(40 \%\) of these are low-risk drivers, \(40 \%\) are moderate risk, and \(20 \%\) are high risk. The company has no way to know which group any individual driver falls in when it writes the policies. None of the low-risk drivers will have an at-fault accident in the next year, but \(10 \%\) of the moderate-risk and \(20 \%\) of the high-risk drivers will have such an accident. If a driver has an at-fault accident in the next year, what is the probability that he or she is high-risk?

The following questions are from ARTIST (reproduced with permission) A refrigerator contains 6 apples, 5 oranges, 10 bananas, 3 pears, 7 peaches, 11 plums, and 2 mangos. a. Imagine you stick your hand in this refrigerator and pull out a piece of fruit at random. What is the probability that you will pull out a pear? b. Imagine now that you put your hand in the refrigerator and pull out a piece of fruit. You decide you do not want to eat that fruit so you put it back into the refrigerator and pull out another piece of fruit. What is the probability that the first piece of fruit you pull out is a banana and the second piece you pull out is an apple? c. What is the probability that you stick your hand in the refrigerator one time and pull out a mango or an orange?

The following questions are from ARTIST (reproduced with permission) A bowl has 100 wrapped hard candies in it. 20 are yellow, 50 are red, and 30 are blue. They are well mixed up in the bowl. Jenny pulls out a handful of 10 candies, counts the number of reds, and tells her teacher. The teacher writes the number of red candies on a list. Then, Jenny puts the candies back into the bowl, and mixes them all up again. Four of Jenny's classmates, Jack, Julie, Jason, and Jerry do the same thing. They each pick ten candies, count the reds, and the teacher writes down the number of reds. Then they put the candies back and mix them up again each time. The teacher's list for the number of reds is most likely to be (please select one): a. 8,9,7,10,9 b. 3,7,5,8,5 c. 5,5,5,5,5 d. 2,4,3,4,3 e. 3,0,9,2,8

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