Check Triangle Inequality
Finally, we need to verify if the given function obeys the triangle inequality. This means checking whether \(蟻(u, v) \leq 蟻(u, w) + 蟻(w, v)\) for all \(u, v, w\) in \(A\). Let's analyse the different cases:
1. If \(u = v\), \(蟻(u, v) = 0 \leq 蟻(u, w) + 蟻(w, v)\) is obviously true, since both 蟻(u, w) and 蟻(w, v) must be non-negative.
2. If \(u = w \neq v\), then \(蟻(u, v) = 1\) and \(蟻(u, w) = 蟻(w, v) = 0\). Therefore, \(蟻(u, v) = 1 \leq 蟻(u, w) + 蟻(w, v) = 0 + 0\) which is not true.
3. If \(u 鈮 v = w\), then \(蟻(u, v) = 蟻(u, w) = 1\). Since 蟻(w, v) = 0, we have \(蟻(u, v) = 1 \leq 蟻(u, w) + 蟻(w, v) = 1 + 0\), which is true.
4. If \(u 鈮 w 鈮 v\), then we have \(蟻(u, v) = 1\). However, we also have \(蟻(u, w) = 蟻(w, v) = 1\). Thus, \(蟻(u, v) = 1 \leq 蟻(u, w) + 蟻(w, v) = 1 + 1\), which is true.
Therefore, the triangle inequality holds for all \(u, v, w\) in the set \(A\).
Since the given function 蟻(u, v) follows all the three properties of a metric, we can conclude that it is a metric on the arbitrary nonempty set A.