The iterated logarithms are defined by \(L_{0}(x)=x\) and
$$
L_{n}(x)=\log \left(L_{n-1}(x)\right), \quad x>a_{n}, \quad n \geq 1
$$
where \(a_{1}=0\) and \(a_{n}=e^{a_{n-1}}, n \geq 1 .\) Show that
(a) \(L_{n}(x)=L_{n-1}(\log x), \quad x>a_{n}, \quad n \geq 1\)
(b) \(L_{n-1}\left(a_{n}+\right)=0\) and \(L_{n}\left(a_{n}+\right)=-\infty\).
(c) \(\lim _{x \rightarrow a_{n}+}\left(L_{n-1}(x)\right)^{\alpha} L_{n}(x)=0\)
if \(\alpha>0\) and \(n \geq 1 .\)
(d) \(\lim _{x \rightarrow \infty}\left(L_{n}(x)\right)^{\alpha} /
L_{n-1}(x)=0\) if \(\alpha\) is arbitrary and \(n \geq 1\).