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Find the \(p\) -values for the z-tests and determine the significance of the results. A two-tailed test with observed \(z=-2.78\)

Short Answer

Expert verified
Answer: The p-value for a two-tailed z-test with an observed z-score of -2.78 is 0.0055. Since the p-value (0.0055) is less than the significance level (0.05), we can conclude that the result is statistically significant.

Step by step solution

01

Understand the two-tailed test

In a two-tailed test, since the alternative hypothesis states that the parameter is simply different from the specified value, we want to look at both tails of the distribution. The z-table will give us the probability up to a certain value, so we will calculate the probability of obtaining a z-score more extreme than our observed z-score in either tail of the distribution.
02

Find the area in the left tail

Using the z-score of \(-2.78\), we can find the area in the left tail of the distribution. To do this, look up the z-score in a standard normal distribution table. For a z-score of \(-2.78\), the corresponding value in the table is \(0.00275\). This value represents the proportion of the distribution to the left of our observed z-score.
03

Find the area in the right tail

Since the standard normal distribution is symmetric, the area in the right tail of the distribution corresponding to \(+2.78\) will be the same as the area in the left tail of the distribution corresponding to \(-2.78\). So, the area in the right tail will also be \(0.00275\).
04

Calculate the p-value

To calculate the p-value for the two-tailed test, we add the areas in both tails of the distribution. \(p-value = 0.00275 + 0.00275 = 0.0055\)
05

Determine the significance of the result

If the p-value is less than a predetermined significance level (usually \(\alpha = 0.05\)), we reject the null hypothesis in favor of the alternative hypothesis. Comparing the calculated p-value to the significance level: \(p-value = 0.0055 < \alpha = 0.05\) Since the p-value is less than the significance level, we reject the null hypothesis, and we can conclude that there is a statistically significant difference between the parameter and the specified value.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Two-tailed test
When we talk about a two-tailed test in statistics, we are referring to a hypothesis testing method that considers both directions of the effect. This means the test checks for the significance of a deviation from a null hypothesis in both positive and negative directions of the outcome.

In a two-tailed test, the alternative hypothesis suggests a difference from a certain value but doesn't specify the direction of this difference. Therefore, it looks at the extreme ends (tails) of both sides of the probability distribution. When you receive a z-score from your data, you'll need to check both tails to calculate the total p-value. This type of test is usually appropriate when you have no specific prediction about which direction the results will go or when you want to check for any significant difference regardless of direction.
Z-score
The z-score is a statistical measurement that describes a value's relationship to the mean of a group of values, measured in terms of standard deviations from the mean. Essentially, it quantifies how many standard deviations above or below the mean a data point is.

To calculate a z-score, the formula is \( z = \frac{(X - \mu)}{\sigma} \) where \(X\) is the value in question, \(\mu\) is the mean of the population, and \(\sigma\) is the standard deviation of the population. Z-scores are a key part of z-tests, where they serve as a tool for assuming how far off a sample statistic is from the null hypothesis.
Standard normal distribution
The standard normal distribution is a specific probability distribution that is symmetric about the mean, representing data that conforms to a bell-shaped curve. In the context of a z-test, the standard normal distribution is used as the reference to determine the probability of obtaining test statistics as extreme as the z-score.

All z-scores can be plotted on the standard normal distribution, often referred to as the z-table. This table provides the areas under the curve to the left of any given z-score, which translates to the probability of a value occurring by chance alone. Because of its symmetry, the probability to the right of a positive z-score is the same as the probability to the left of its negative counterpart.
Significance level
The significance level, denoted as \(\alpha\), is a threshold that determines the margin for which the p-value will indicate a significant result in hypothesis testing. Commonly set at 0.05 (5%), the significance level essentially draws a line in the sand that states how unlikely a result must be, if the null hypothesis were true, to be considered significant.

When the p-value is less than the chosen significance level, the null hypothesis is rejected, implying the results are not due to random chance alone. Deciding upon the significance level before conducting a test is crucial as it impacts the conclusions drawn from the statistical analysis.
Null hypothesis
In statistical hypothesis testing, the null hypothesis \(H_0\) is a statement of no effect or no difference, serving as a default or starting assumption. The null hypothesis is what you try to disprove or discredit through your test.

For example, if you're testing a new drug, the null hypothesis might be that it has no effect on patients. Evidence against the null hypothesis is sought, and if found, the null hypothesis can be rejected in favor of the alternative hypothesis (denoted as \(H_1\) or \(H_a\)), which suggests that there is indeed an effect or a difference. The outcome of the statistical test, measured by the p-value, determines whether or not we can reject the null hypothesis.

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Most popular questions from this chapter

Suppose a scheduled airline flight must average at least \(60 \%\) occupancy in order to be profitable. Occupancy rates were recorded daily for a regularly scheduled flight on each of 120 days, showing a mean occupancy per flight of \(58 \%\) and a standard deviation of \(11 \%\). a. If \(\mu\) is the mean occupancy per flight and if the company wishes to determine whether or not this scheduled flight is unprofitable, give the alternative and the null hypotheses for the test. b. Does the alternative hypothesis in part a imply a oneor two-tailed test? Explain. c. Do the occupancy data for the 120 flights suggest that this scheduled flight is unprofitable? Test using \(\alpha=.05\)

What is the power of a test and how is it related to \(\beta ?\)

An experiment was planned to compare the mean time (in days) to recover from a common cold for people given a daily dose of 4 milligrams (mg) of vitamin C versus those who were not. Suppose that 35 adults were randomly selected for each treatment category and that the mean recovery times and standard deviations for the two groups were as follows: $$ \begin{array}{lcc} \hline & \begin{array}{l} \text { No Vitamin } \\ \text { Supplement } \end{array} & \begin{array}{c} 4 \mathrm{mg} \\ \text { Vitamin C } \end{array} \\ \hline \text { Sample Size } & 35 & 35 \\ \text { Sample Mean } & 6.9 & 5.8 \\ \text { Sample Standard Deviation } & 2.9 & 1.2 \end{array} $$ a. If you want to show that the use of vitamin \(\mathrm{C}\) reduces the mean time to recover from a common cold, give the null and alternative hypotheses for the test. Is this a one- or a two-tailed test? b. Conduct the statistical test of the null hypothesis in part a and state your conclusion. Test using \(\alpha=.05\)

For a fixed sample size \(n\), what is the effect on \(\beta\) when \(\alpha\) is decreased?

Does a baby's sleeping position affect the development of motor skills? A study in the Archives of Pediatric Adolescent Medicine examined 343 full-term infants at their 4 -month checkups for various milestones, such as rolling over, grasping a rattle, reaching for an object, and so on. \({ }^{21}\) The baby's favored sleep position - either on the stomach or on the back or side- was reported by the parents of 320 of the children, with the sample results shown here. $$ \begin{array}{lcc} \hline & \text { Stomach } & \text { Back or Side } \\ \hline \text { Number of Infants } & 121 & 199 \\ \text { Number That Roll Over } & 93 & 119 \\ \hline \end{array} $$ The researcher reported that infants who slept in the side or back position were less likely to roll over at the 4 -month checkup than infants who slept primarily in the stomach position \((P<.001) .\) Use a large-sample test of hypothesis to confirm or refute the researcher's conclusion.

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