/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 10 A random sample of \(n\) observa... [FREE SOLUTION] | 91Ó°ÊÓ

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A random sample of \(n\) observations is selected from a population with standard deviation \(\sigma=1 .\) Calculate the standard error of the mean \((S E)\) for the values of \(n\). $$ n=9 $$

Short Answer

Expert verified
Answer: The standard error of the mean (SE) for the given sample is \(\frac{1}{3}\).

Step by step solution

01

Identify the SE formula

The formula to calculate the standard error of the mean is: $$ SE = \frac{\sigma}{\sqrt{n}} $$
02

Plug the given values into the formula

The population standard deviation \(\sigma = 1\) and the sample size \(n = 9\). Plugging these values into the formula, we get: $$ SE = \frac{1}{\sqrt{9}} $$
03

Calculate the SE

Now, we'll simplify the expression: $$ SE = \frac{1}{3} $$ The standard error of the mean (SE) for the given sample is \(\frac{1}{3}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Standard Deviation
When we talk about the standard deviation, we are referring to a statistical measure that tells us how spread out the values in a data set are. In simpler terms, it shows how much variation exists from the average (mean) value. A lower standard deviation means that the data points are clustered closely to the mean, indicating less variability. Conversely, a high standard deviation suggests that the data points are spread out over a wider range of values.

Understanding standard deviation is crucial because it provides a context for comparison. For instance, if we know the standard deviation of students' test scores, we can infer how consistent the performances are across the group.
Random Sample
A random sample plays a pivotal role in statistics. It's a subset of individuals chosen from a larger population, where each member of the population has an equal chance of being included in the sample. The beauty of a random sample is that it aims to accurately reflect the characteristics of the larger population.

The random sample is used to draw conclusions or make estimates about the population without needing to survey everyone. This method saves time and resources, and if done correctly, the results can be highly reliable and extrapolated to the broader group.
Population Statistics
Population statistics deal with the numerical data of entire populations. Unlike a sample which is just a part of the population, population statistics describe every member of the group. These statistics can include measures like mean (average), standard deviation, median, and range, among others.

One key aspect of population statistics is that they provide a benchmark for evaluating sample statistics. For example, comparing the standard deviation of a sample to that of the population can help determine how representative the sample is. Understanding the population helps us make predictions and decisions based on the data collected from samples.
Sample Size
In the context of statistics, sample size refers to the number of observations or individuals in a subset of a population, used for statistical analysis. The sample size is critically important because it influences the accuracy of the estimation or predictions made about the population. A larger sample size typically reduces sampling error, making the sample mean a more accurate reflection of the population mean.

When we determine sample sizes, we consider factors like the desired level of accuracy, the population size, and the amount of variability in the data. In our textbook problem, for example, increasing the sample size from 9 would lead to a smaller standard error of the mean, thus giving us a more precise estimate of the population mean.

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Most popular questions from this chapter

A population consists of \(N=5\) items-two of which are considered "successes" \(\left(S,\right.\) and \(\left.S_{2}\right)\) and three of which are considered "failures" \(\left(F_{1}, F_{2},\right.\) and \(\left.F_{3}\right) .\) A random sample of \(n=2\) items is selected, without replacement. Use this information to answer the questions. For each of the samples in Exercise \(10,\) find the proportion of successes in the sample.

The manager of a building supplies company randomly samples incoming lumber to see whether it meets quality specifications. From each shipment, 100 pieces of \(2 \times 4\) lumber are inspected and judged according to whether they are first (acceptable) or second (defective) grade. The proportions of second- grade \(2 \times 4\) s recorded for 30 shipments were as follows: \(\begin{array}{llllllllll}.14 & .21 & .19 & .18 & .23 & .20 & .25 & .19 & .22 & .17 \\ .21 & .15 & .23 & .12 & .19 & .22 & .15 & .26 & .22 & .21 \\ .14 & .20 & .18 & .22 & .21 & .13 & .20 & .23 & .19 & .26\end{array}\) a. Construct a control chart for the proportion of second-grade \(2 \times 4 \mathrm{~s}\) in samples of 100 pieces of lumber. b. Explain how the control chart can be of use to the manager of the building- supplies company.

A USA Today snapshot reports that approximately \(23 \%\) of cell phone owners walked into someone or something while they were talking on their cell phone. \({ }^{12}\) In a random sample of \(n=200\) cell phone owners, what is the probability that the sample proportion of cell phone owners who have walked into someone or something while they were on the phone would be less than \(.15 ?\)

A population consists of \(N=4\) numbers: 10,15,21,22 with a mean of \(\mu=17 .\) A random sample of \(n=2\) is selected in one of two ways: first, without replacement and second, with replacement. Use this information to answer the questions. How many possible random samples are there when sampling without replacement? List the possible samples. Find the sampling distribution for the sample mean \(\bar{x}\) and display it as a table and as a probability histogram.

Is it appropriate to use the normal distribution to approximate the sampling distribution of \(\hat{p}\) for the situations described in Exercises \(4-8 ?\) $$n=75, p=.4$$

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