/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 16 You own 4 pairs of jeans, 12 cle... [FREE SOLUTION] | 91Ó°ÊÓ

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You own 4 pairs of jeans, 12 clean T-shirts, and 4 wearable pairs of sneakers. How many outfits (jeans, T-shirt, and sneakers) can you create?

Short Answer

Expert verified
Answer: 192 different outfits

Step by step solution

01

Count the number of choices for jeans

There are 4 pairs of jeans, so there are 4 choices for jeans.
02

Count the number of choices for T-shirts

There are 12 clean T-shirts, so there are 12 choices for T-shirts.
03

Count the number of choices for sneakers

There are 4 wearable pairs of sneakers, so there are 4 choices for sneakers.
04

Apply the counting principle

The counting principle states that we can multiply the number of choices for each item to find the total number of possible combinations. In this case, we have: Total_outfits = Number_of_jeans * Number_of_T-shirts * Number_of_sneakers
05

Calculate the result

Substitute the values from steps 1, 2, and 3 into the equation to find the total number of outfits: Total_outfits = 4 * 12 * 4 Total_outfits = 192 So there are 192 different outfits that can be created using the given jeans, T-shirts, and sneakers.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Combinations
When we talk about combinations in mathematics, we refer to the selection of items from a larger pool where the order doesn't matter. For example, if you were picking fruit from a basket for a fruit salad, it wouldn't matter if you grabbed an apple first or last; the result would still be a fruit salad. Similarly, when creating an outfit from a selection of jeans, T-shirts, and sneakers, the order in which you choose the items doesn't matter; what matters is which items you choose.

Mathematically, combinations are a basic concept of combinatorics and are denoted as \( C(n, k) \), which represents the number of ways to choose \( k \) elements from a set of \( n \) elements. However, in the context of the exercise, we are not concerned with combinations because the choice of jeans, T-shirts, and sneakers does create a specific combination that defines an outfit, and here, the order of selection is acknowledged implicitly.

Since the context implies a specific selection process, we're talking about distinct outcomes, which is where permutation and the counting principle come into play, not the traditional combination formula.
Probability and Statistics
While this exercise does not explicitly involve probability and statistics, understanding combinations and counting principles lays the foundation for more advanced topics within these fields. In probability, we often calculate the likelihood of a specific combination of events, such as drawing a hand from a deck of cards or getting a certain outcome from rolling dice.

In terms of statistics, combinations help us understand sample spaces or the set of all possible outcomes, which is crucial for predictions and data analysis. For instance, knowing the total number of possible outfits, as calculated in the exercise, might help a clothing retailer forecast sales or manage inventory. While the calculation of the probability would require additional context and data, the counting techniques are integral in establishing the total number of outcomes from which any probability would be calculated.
Basic Counting Techniques
Basic counting techniques are essential tools in understanding how to approach problems involving quantities and possibilities. The most fundamental of these is the counting principle, also known as the fundamental principle of counting or the rule of product. This principle explains how to find the number of possible outcomes when there are multiple choices to be made, and each choice is independent of the others.

In the provided exercise, we see the counting principle at work. It simply states that if one event can occur in \(m\) ways and a second independent event can occur in \(n\) ways, then the total number of ways the two events can occur is \(m \times n\). The same logic applies to multiple events. Thus, we can find the total number of unique outfits by multiplying the number of options for jeans, T-shirts, and sneakers together. This technique simplifies the process of determining the number of possible combinations of items and is a foundational concept for more complex statistical calculations and for understanding probabilities.

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Most popular questions from this chapter

In testing prospective employees for drug use, companies need to remember that the tests are not \(100 \%\) reliable. Suppose a company uses a test that is \(98 \%\) accurate - that is, it correctly identifies a person as a drug user or nonuser with probability \(.98-\) and to reduce the chance of error, each job applicant must take two tests. Assume that the outcomes of the two tests on the same person are independent events, and find the following probabilities: a. A nonuser fails both tests. b. A drug user is detected (i.e., he or she fails at least one test). c. A drug user passes both tests.

Two cold tablets are unintentionally put in a box containing two aspirin tablets, that appear to be identical. One tablet is selected at random from the box and swallowed by the first patient. The second patient selects another tablet at random and swallows it. a. List the simple events in the sample space \(S\). b. Find the probability of event \(A\), that the first patient swallowed a cold tablet. c. Find the probability of event \(B\), that exactly one of the two patients swallowed a cold tablet. d. Find the probability of event \(C,\) that neither patient swallowed a cold tablet.

A group of research proposals was evaluated by a panel of experts to decide whether or not they were worthy of funding. When these same proposals were submitted to a second independent panel of experts, the decision to fund was reversed in \(30 \%\) of the cases. If the probability that a proposal is judged worthy of funding by the first panel is \(.2,\) what are the probabilities that: a. A worthy proposal is approved by both panels. b. A worthy proposal is disapproved by both panels. c. A worthy proposal is approved by one panel.

Suppose that, in a particular city, airport \(A\) handles \(50 \%\) of all airline traffic, and airports \(B\) and \(C\) handle \(30 \%\) and \(20 \%,\) respectively. The detection rates for weapons at the three airports are \(.9, .8,\) and .85, respectively. If a passenger at one of the airports is found to be carrying a weapon through the boarding gate, what is the probability that the passenger is using airport \(A\) ? Airport \(C ?\)

Experiment III A sample space consists of five simple events with \(P\left(E_{1}\right)=P\left(E_{2}\right)=.15, P\left(E_{3}\right)=.4,\) and \(P\left(E_{4}\right)=2 P\left(E_{5}\right) .\) Find the probabilities for simple events \(E_{4}\) and \(E_{5}\).

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