/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 23 Altman and Bland report the surv... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Altman and Bland report the survival times for patients with active hepatitis, half treated with prednisone and half receiving no treatment. \({ }^{12}\) The survival times (in months) are adapted from their data for those treated with prednisone. $$ \begin{array}{rrrr} 8 & 87 & 127 & 147 \\ 11 & 93 & 133 & 148 \\ 52 & 97 & 139 & 157 \\ 57 & 109 & 142 & 162 \\ 65 & 120 & 144 & 165 \end{array} $$ a. Can you tell by looking at the data whether it is roughly symmetric? Or is it skewed? b. Calculate the mean and the median. Use these measures to decide whether or not the data are symmetric or skewed. c. Draw a box plot to describe the data. Explain why the box plot confirms your conclusions in part b.

Short Answer

Expert verified
Based on the analysis, we can conclude that the survival times of patients treated with prednisone for hepatitis are roughly symmetric and not significantly skewed. This is evident from the similar mean and median values (107.8 and 103, respectively) and the symmetric nature of the box plot. The box plot shows a median line in the center of the box, and the whiskers have similar lengths, further supporting a symmetric distribution for this data.

Step by step solution

01

a. Visual analysis of symmetry and skewness

Observe the data and try to determine whether the data is symmetric or skewed. There is no straightforward method to do this, but look for similarity in values on either side of the middle value.
02

b. Calculate mean and median

Mean is calculated by summing all the values and dividing by the total number of values present. To find the median, you'll need to sort the data in ascending order and find the middle value. In this case, the data is small, so we can sort it manually: $$ \begin{array}{rrrr} 8 & 11 & 52 & 57\\ 65 & 87 & 93 & 97\\ 109 & 120 & 127 & 133\\ 139 & 142 & 144 & 147\\ 148 & 157 & 162 & 165 \end{array} $$ Mean: $$ \frac{8+11+52+57+65+87+93+97+109+120+127+133+139+142+144+147+148+157+162+165}{20} = 107.8 $$ Median: The middle value will be the average of the values at positions 10 and 11 (97 and 109). $$ \frac{97+109}{2} = 103 $$ Since the mean and median are very similar, we can conclude that the data is roughly symmetric, with no significant skewness.
03

c. Box plot construction and analysis

Construct a box plot of the data. The box plot consists of a box (containing the middle 50% of the data) and whiskers extending from the ends of the box to the minimum and maximum values. 1. Calculate the first quartile (Q1), which represents the 25th percentile of the data: The position of Q1 is at \(0.25 \cdot (20+1) = 5.25\). It's between the 5th value (65) and 6th value (87). $$ Q1 = \frac{65+87}{2} = 76 $$ 2. Calculate the third quartile (Q3), which represents the 75th percentile of the data: The position of Q3 is at \(0.75 \cdot (20+1) = 15.75\). It's between the 15th value (144) and the 16th (147). $$ Q3 = \frac{144+147}{2} = 145.5 $$ 3. Calculate the interquartile range (IQR): $$ IQR = Q3 - Q1 = 145.5 - 76 = 69.5 $$ 4. Draw the box plot: - Draw a horizontal scale from the minimum value (8) to the maximum value (165). - Draw a box from Q1 (76) to Q3 (145.5). - Draw a line inside the box at the median (103). - Draw whiskers from the ends of the box to the minimum value (8) and the maximum value (165). The box plot is symmetric, with the median line in the center of the box, and the whiskers have similar lengths. This confirms our conclusions from part b that the data is roughly symmetric and not significantly skewed.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mean Calculation
Calculating the mean provides a single value that represents the central point of a data set. To find the mean, we sum up all the data points and then divide by the number of data points. Here’s a simple way to do it:
- Add up all the values.- Count the number of values.- Divide the sum by the count.
In our example, the survival times for patients treated with prednisone were totaled as follows: 8 + 11 + 52 + 57 + 65 + 87 + 93 + 97 + 109 + 120 + 127 + 133 + 139 + 142 + 144 + 147 + 148 + 157 + 162 + 165, which equals 2,156.
With 20 data points, dividing the total gives a mean of:\[\text{Mean} = \frac{2156}{20} = 107.8\]This mean value is crucial as it gives us a quick snapshot of data's central tendency. However, it's important to look at it alongside the median to fully understand the symmetry of the data.
Median Calculation
The median is another way to measure the center of a data set. Unlike the mean, it is not affected by extremely high or low values. To find the median:
  • Sort the data from smallest to largest.
  • Identify the middle value. If there is an odd number of data points, it is just the middle one. If even, average the two middle values.
For the prednisone data:\[8, 11, 52, 57, 65, 87, 93, 97, 109, 120, 127, 133, 139, 142, 144, 147, 148, 157, 162, 165\]There are 20 values, so the median is the average of the 10th (97) and 11th (109) values:\[\text{Median} = \frac{97 + 109}{2} = 103\]Seeing how close the mean (107.8) and median (103) are provides insight into the data's distribution. If they were further apart, significant skewness might be present. Here, they're close, suggesting symmetry.
Box Plot Construction
Box plots, or box-and-whisker plots, provide a visual representation of the distribution of the data. This simple graph shows five key data points:
  • Minimum
  • First quartile (Q1)
  • Median
  • Third quartile (Q3)
  • Maximum
To construct a box plot:1. Identify the smallest value (minimum) and the largest value (maximum).2. Calculate the first quartile (Q1), which is the median of the lower half of the data. For our data, it is between the 5th and 6th elements.\[Q1 = \frac{65 + 87}{2} = 76\]3. Find the third quartile (Q3), the midpoint of the upper half of the data, between the 15th and 16th elements.\[Q3 = \frac{144 + 147}{2} = 145.5\]4. The interquartile range (IQR) is Q3 minus Q1.\[IQR = 145.5 - 76 = 69.5\]5. Draw a box from Q1 to Q3 and a line at the median value, 103.6. Extend "whiskers" from the box to the minimum and maximum values, 8 and 165, respectively.
In the plot, a symmetric appearance with balanced whiskers and the median line in the box’s center reaffirms our symmetry conclusion, as derived from the mean and median.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A group of laboratory animals is infected with a particular form of bacteria. Their survival times are found to average 32 days, with a standard deviation of 36 days. a. Think about the distribution of survival times. Do you think that the distribution is relatively moundshaped, skewed right, or skewed left? Explain. b. Within what limits would you expect at least \(3 / 4\) of the measurements to lie?

Here are the ages of 50 pennies, calculated as \(A G E=\) CURRENT YEAR - YEAR ON PENNY. The data have been sorted from smallest to largest. $$ \begin{array}{rrrrrrrrrr} 0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 & 0 \\ 0 & 0 & 1 & 1 & 1 & 1 & 1 & 1 & 2 & 2 \\ 2 & 3 & 3 & 3 & 4 & 4 & 5 & 5 & 5 & 5 \\ 6 & 8 & 9 & 9 & 10 & 16 & 17 & 17 & 19 & 19 \\ 19 & 20 & 20 & 21 & 22 & 23 & 25 & 25 & 28 & 36 \end{array} $$ a. What is the average age of the pennies? b. What is the median age of the pennies? c. Based on the results of parts a and b, how would you describe the age distribution of these 50 pennies? d. Draw a box plot for the data set. Are there any outliers? Does the box plot confirm your description of the distribution's shape?

Use the range to approximate the value of \(s\). Then calculate the actual value of \(s .\) Is the actual value close to the estimate? $$ n=10 \text { measurements: } 5,2,3,6,1,2,4,5,1,3 $$

Searching online for the price of an item you would like to buy can save you quite a bit of money. A search for the best price for a white KitchenAid 5-speed hand mixer using yroo.com lists 16 sellers with various prices found in the following table. $$\begin{array}{lclc}\hline \text { Seller } & \text { Price (\$) } & \text { Seller } & \text { Price (\$) } \\\\\hline \text { Best Buy } & 39.99 & \text { Sears } & 39.99 \\\\\text { Blain's Farm \& Fleet } & 39.99 & \text { Boston Store } & 39.99 \\\\\text { Bergners } & 39.99 & \text { Home Depot } & 41.46 \\\\\text { Wayfair } & 42.46 & \text { Buydig.com } & 43.99 \\\\\text { Target } & 46.49 & \text { Shopko } & 47.49 \\\\\text { Jet.com } & 47.90 & \text { Amazon } & 47.19 \\\\\text { Walmart } & 51.97 & \text { Office Depot } & 54.99 \\\\\text { Houzz } & 59.99 & \text { True Value } & 59.99 \\\\\hline\end{array}$$ a. What is the average price of this hand mixer for these 16 sellers? b. What is the median price for these 16 sellers? c. As a consumer would you be interested in the average price of the hand mixer? The median price? What other descriptive measures would be important to you?

Find the range, the sample variance and the sample standard deviation. In a psychology experiment, 10 subjects were given 5 minutes to complete a task. Their time on task (in seconds) is recorded. $$ \begin{array}{lllll} 175 & 190 & 250 & 230 & 240 \\ 200 & 185 & 190 & 225 & 265 \end{array} $$

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.