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Use the information and Table 5 in Appendix I to find the value of \(\chi^{2}\) with area \(\alpha\) to its right. $$ \alpha=.05, d f=5 $$

Short Answer

Expert verified
Answer: The chi-squared statistic with a right-tail area of 0.05 and 5 degrees of freedom is 11.07.

Step by step solution

01

Identify the given values

We're given the area to the right of the chi-squared value, \(\alpha = 0.05\), and the degrees of freedom, \(df = 5\).
02

Locate the values in Table 5

Using Appendix I's Table 5, locate the row corresponding to our degrees of freedom, \(df = 5\). Then, locate the column corresponding to our area, \(\alpha = 0.05\).
03

Find the chi-squared value

The value at the intersection of the row and column we identified in Step 2 is the chi-squared value we're looking for with our given area and degrees of freedom. In this case, the chi-squared value (\(\chi^2\)) is 11.07.
04

Write down the answer

The value of \(\chi^2\) with a right-tail area of \(\alpha=0.05\) and \(df=5\) is \(\chi^2 = 11.07\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Degrees of Freedom
Understanding the concept of degrees of freedom (df) is essential in the context of statistical analysis. In a chi-squared distribution, the degrees of freedom are the number of values in the final calculation of a statistic that are free to vary. Imagine you have a set of numbers. If you were to calculate their mean, you'd use all of the numbers in your calculation. However, if you then wanted to adjust the numbers to have a particular mean, one of your values would be dependent on the others. This dependency reduces the degrees of freedom by one.

For example, if we have 5 independent observations in a chi-squared test, our degrees of freedom would be 5. These degrees of freedom play a pivotal role in the shape of the chi-squared distribution curve and impact the critical values needed to determine statistical significance. The higher the degrees of freedom, the closer the distribution will resemble a normal distribution.
Right-Tail Area
When dealing with the chi-squared distribution, the 'right-tail area' refers to the probability of observing a value at least as extreme as the test statistic. It is the area under the curve of the distribution to the right of a specified chi-squared value. In our textbook exercise, the right-tail area, denoted by \(\alpha\), is the level of significance, which in this case is 0.05. This signifies that there is a 5% probability of observing a chi-squared value as extreme or more extreme by chance alone if the null hypothesis is true.

This concept is crucial in hypothesis testing. By comparing the computed or observed chi-squared value to the critical value from chi-squared distribution tables, we can decide whether to reject the null hypothesis or not. The smaller the right-tail area, the more extreme the test statistic needs to be for us to reject the null hypothesis.
Statistical Tables
Statistical tables, such as the chi-squared table, are invaluable tools in probability and statistics. They provide critical values for various distributions, which are necessary for carrying out hypothesis tests. A chi-squared table typically has rows labeled with degrees of freedom and columns labeled with the right-tail area, or significance levels. The intersection of a row and column provides the chi-squared value that serves as a threshold for decision-making in hypothesis testing.

To navigate these tables, you first find the row corresponding to your degrees of freedom. Then, move across to the column that represents your right-tail area or significance level. The value where the row and column intersect is the critical value. For example, in our exercise, the critical chi-squared value for 5 degrees of freedom and a significance level of 0.05 is found to be 11.07. If the calculated chi-squared statistic exceeds this value, it suggests that the null hypothesis can be rejected at this level of significance.
Probability and Statistics
The field of probability and statistics underpins much of the decision-making in science, finance, and quality control processes. Probability is the study of chance and is used to predict the likelihood of future events occurring, while statistics helps us to analyze historical data and draw conclusions.

In the realm of hypothesis testing, we use probability to determine how unlikely our sample results are, assuming that the null hypothesis is true. If the probability is low enough (less than our chosen significance level \(\alpha\)), we conclude that the observed data is statistically significant. For instance, an \(\alpha\) of 0.05 means there is a 95% confidence level that the results are not due to random chance. By merging probability with statistical methods, such as the chi-squared test, we are equipped to test hypotheses and make informed decisions based on statistical evidence.

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Most popular questions from this chapter

List the characteristics of a multinomial experiment.

To study the effect of worker participation in managerial decision making, 100 workers were interviewed in each of two separate German manufacturing plants. One plant had active worker participation in managerial decision making; the other did not. Each selected worker was asked whether he or she generally approved of the managerial decisions made within the firm. The results of the interviews are shown in the table: $$ \begin{array}{lcc} \hline & \text { Participation } & \text { No Participation } \\ \hline \text { Generally Approve } & 73 & 51 \\ \text { Do Not Approve } & 27 & 49 \\ \hline \end{array} $$ a. Do the data provide sufficient evidence to indicate that approval or disapproval of management's decisions depends on whether workers participate in decision making? Test by using the \(X^{2}\) test statistic. Use \(\alpha=.05 .\) b. Do these data support the hypothesis that workers in a firm with participative decision making more generally approve of the firm's managerial decisions than those employed by firms without participative decision making? Test by using the \(z\) -test presented in Section \(9.5 .\) This problem requires a one-tailed test. Why?

To determine the effectiveness of a drug for arthritis, a researcher studied two groups of 200 arthritic patients. One group was inoculated with the drug; the other received a placebo (an inoculation that appears to contain the drug but actually is nonactive). After a period of time, each person in the study was asked to state whether his or her arthritic condition had improved. $$ \begin{array}{lcc} \hline & \text { Treated } & \text { Untreated } \\ \hline \text { Improved } & 117 & 74 \\ \text { Not Improved } & 83 & 126 \\ \hline \end{array} $$ You want to know whether these data indicate that the drug was effective in improving the condition of arthritic patients. a. Use the chi-square test of homogeneity to compare the proportions improved in the populations of treated and untreated subjects. Test at the \(5 \%\) level of significance. b. Test the equality of the two binomial proportions using the two-sample \(z\) -test of Section 9.5 . Verify that the squared value of the test statistic \(z^{2}=X^{2}\) from part a. Are your conclusions the same as in part a?

Suppose you wish to test the null hypothesis that three binomial parameters \(p_{A}, p_{B},\) and \(p_{c}\) are equal versus the alternative hypothesis that at least two of the parameters differ. Independent random samples of 100 observations were selected from each of the populations. Use the information in the table to answer the questions in Exercises \(5-7 .\) $$ \begin{array}{lrrrr} \hline & {\text { Population }} & \\ & \text { A } & \text { B } & \text { C } & \text { Total } \\ \hline \text { Successes } & 24 & 19 & 33 & 76 \\ \text { Failures } & 76 & 81 & 67 & 224 \\ \hline \text { Total } & 100 & 100 & 100 & 300 \end{array} $$ Calculate the test statistic and find the approximate \(p\) -value for the test in Exercise 5.

Find the appropriate degrees of freedom for the chisquare test of independence. $$\text { three rows and five columns }$$

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