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To test the effect of alcohol in increasing the reaction time to respond to a given stimulus, the reaction times of seven people were measured both before and after drinking 90 milliliters of \(40 \%\) alcohol. Do the following data indicate that the mean reaction time after consuming alcohol was greater than the mean reaction time before consuming alcohol? Use \(\alpha=.05 .\) $$\begin{array}{llllllll}\hline \text { Person } & 1 & 2 & 3 & 4 & 5 & 6 & 7 \\\\\hline \text { Before } & 4 & 5 & 5 & 4 & 3 & 6 & 2 \\\\\text { After } & 7 & 8 & 3 & 5 & 4 & 5 & 5 \\\\\hline\end{array}$$

Short Answer

Expert verified
Answer: No, there is not enough evidence to indicate that the mean reaction time after consuming alcohol is greater than the mean reaction time before consuming alcohol, as the t-test statistic (1.21) is less than the critical t-value (1.94).

Step by step solution

01

Calculate the differences in reaction times

For each person, subtract the reaction time before consuming alcohol from the reaction time after consuming alcohol. $$\begin{array}{llllllll}\hline \text { Person } & 1 & 2 & 3 & 4 & 5 & 6 & 7 \\\\\hline \text { Before } & 4 & 5 & 5 & 4 & 3 & 6 & 2 \\\\\text { After } & 7 & 8 & 3 & 5 & 4 & 5 & 5 \\\\\hline \text { Difference } & 3 & 3 & -2 & 1 & 1 & -1 & 3 \\\\\hline\end{array}$$
02

Compute the mean and standard deviation of the differences

Calculate the mean (\(\bar{d}\)) and standard deviation (\(s_d\)) of the differences. $$\bar{d} = \frac{3+3-2+1+1-1+3}{7} = \frac{8}{7} \approx 1.143$$ $$s_d = \sqrt{\frac{(3-1.143)^2+(3-1.143)^2+(-2-1.143)^2+(1-1.143)^2+(1-1.143)^2+(-1-1.143)^2+(3-1.143)^2}{6}} \approx 1.89$$
03

Compute the t-test statistic

Calculate the t-test statistic using the following formula: $$t = \frac{\bar{d}}{s_d / \sqrt{n}}$$ where \(n\) is the number of paired samples. $$t = \frac{1.143}{1.89 / \sqrt{7}} \approx 1.21$$
04

Find the critical t-value

Look up the critical t-value for a paired t-test using the significance level (\(\alpha=0.05\)) and degrees of freedom (\(n-1=6\)). The critical t-value is approximately 1.94.
05

Compare t-test statistic to critical t-value

Compare the t-test statistic (1.21) to the critical t-value (1.94). Since 1.21 is less than 1.94, we fail to reject the null hypothesis that the mean reaction times before and after consuming alcohol are the same. In conclusion, the data does not provide enough evidence to indicate that the mean reaction time after consuming alcohol is greater than the mean reaction time before consuming alcohol at the 0.05 significance level.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Measuring Mean Reaction Time in Experiments
Understanding mean reaction time is essential for various experiments, particularly in fields like psychology and medicine. But let's break it down; what exactly is 'mean reaction time'? It refers to the average amount of time it takes for a subject to respond to a stimulus. In our context, it's the average time taken by a group of individuals to react before and after consuming alcohol.
Mean reaction time is pivotal because it acts as a quantifiable measure of cognitive or physical responses under different conditions. For instance, when scientists want to assess the impact of a substance, like alcohol, on human faculties, they measure the reaction times as a proxy for impairment or enhancement. The 'Before' and 'After' columns in our data provide the raw data, but only by calculating the mean of these data can we make an evidence-based conclusion about the alcohol's effect.
To enrich our investigation, tracking changes for individual participants rather than general averages offers a more accurate reflection of the effect on reaction time. This personalized approach caters to the variability among human responses and is one of the bedrocks of the paired t-test method used in our exercise.
Understanding Hypothesis Testing: The Foundation of Paired T-Tests
Hypothesis testing is a fundamental concept in statistics used to make inferences about populations based on sample data. This process starts with two contrasting hypotheses: the null hypothesis (\(H_0\)), which is a statement of no effect, and the alternative hypothesis (\(H_a\)), which proposes an anticipated effect or difference. Our exercise involving reaction times is a prime example where these two hypotheses clash.
For our paired t-test, the null hypothesis would suggest that the mean reaction time does not change after alcohol consumption, while the alternative hypothesis would suggest that there is an increase. The paired t-test is specifically designed for situations where we measure the same subjects under two conditions, thereby controlling for intersubject variability. It's essentially a method we use to provide statistical evidence for or against our null hypothesis.
As it turns out in this instance, our calculated t-statistic did not reach the critical value necessary to reject the null hypothesis. This result means, with the level of confidence we have chosen (95% confidence corresponding to \(\alpha=0.05\)), we do not have enough evidence to claim a significant increase in reaction time after consuming alcohol. It's important to note that not rejecting \(H_0\) does not prove it true—it merely indicates that based on our sample and the chosen significance level, we didn't find strong enough evidence to conclude an effect.

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