/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 1 Why use paired observations to e... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Why use paired observations to estimate the difference between two population means rather than estimation based on independent random samples selected from the two populations? Is a paired experiment always preferable? Explain.

Short Answer

Expert verified
Answer: Paired observations are used to estimate the difference between two population means because they control for lurking variables, reduce variability, and provide a more precise estimate. However, a paired experiment is not always preferable, as it may not be suitable or possible in some situations, and independent random samples can be more appropriate.

Step by step solution

01

Advantages of Paired Observations

Paired observations are used when the two samples have a natural pairing, which can help control for lurking variables that could affect the data. This pairing allows us to focus on the differences between the observations in each pair directly and minimize the effects of other factors. By using paired observations, we are able to reduce the variability and therefore obtain a more precise estimate of the difference between the population means.
02

Independent Random Samples

In contrast, when using independent random samples selected from the two populations, there may be more variance in the data due to the lack of control for lurking variables. This approach may result in a less precise estimation of the difference between the means, and it may require a larger sample size to achieve the same level of confidence.
03

Paired Experiment Preference

A paired experiment is not always preferable. If there is no natural pairing in the data or the lurking variables have minimal impact, using independent random samples may be more appropriate. Additionally, if it is not possible to collect paired data due to logistical or ethical reasons, conducting a study with independent random samples would be the only option. In conclusion, paired observations can be beneficial when there is a natural pairing in the data, as they can provide a more precise estimate of the difference between population means by controlling for lurking variables. However, paired experiments may not always be preferable or possible, and in such cases, independent random samples can be used.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Population Means Estimation
When statisticians aim to estimate the difference between two population means, they can employ various methods. Paired observations constitute one approach that happens to have distinctive advantages. This technique is particularly useful when each subject in one sample can be logically paired with a subject in another sample, maximizing the relevance of comparisons drawn.

One major merit of using paired observations lies in its ability to control for individual variability. For instance, if you want to measure the effect of a new teaching method on math scores, you could compare the same group's scores before and after the method is applied. Here, the 'pair' consists of the pre- and post-intervention scores for each student. The natural pairing reduces extraneous variability, because you are controlling for each individual's learning ability and foundational knowledge.

Furthermore, paired comparisons often require a smaller sample size to achieve significant results, as they can more effectively control for variations that might obscure the true effect of the variable being studied. This can make experiments more economical and feasible. However, it's critical to ensure that the pairs are correctly matched to avoid biased results. When pairs are mismatched, the conclusions drawn about the population means may be flawed.
Lurking Variables
Lurking variables can be pesky confounders that negatively impact the validity of a study. These are factors that the researcher has not accounted for, which could influence both the independent and dependent variables. In the realm of statistics, controlling for lurking variables is vital to draw accurate conclusions.

Imagine you're investigating the relationship between exercise and weight loss. If you neglect to consider the participants' dietary habits—a lurking variable—you might erroneously attribute all weight differences to exercise alone. Paired observations can assist in controlling lurking variables because the pairing often neutralizes such unseen factors; each pair has the same value of the lurking variable, or the variable's impact is evenly distributed across pairs.

Nonetheless, identifying all possible lurking variables can be a herculean task, and there's always a risk that some may remain unidentified. When conducting experiments or observational studies, it is crucial to thoroughly consider potential lurking variables and design the study to mitigate their influence. Failure to do so can lead to misleading results that incorrectly estimate population means or suggest false causation.
Independent Random Samples
For studies where natural pairing isn't feasible, another robust method is to rely on independent random samples. These are samples selected in such a way that each member of the population has an equal chance of being chosen, and the selection of one individual does not influence the selection of another.

Using independent random samples helps ensure that the results are representative of the larger population, making it possible to generalize findings with greater confidence. An esteemed benefit of this method over paired observations is its broad applicability—it can be used irrespective of any inherent pairing in the population. This approach shines in terms of diversity and is less prone to the bias that can occur with incorrect pairing.

However, when comparing means between two independent samples, larger sample sizes are generally needed to achieve the same precision as with paired observations. Greater sample sizes can mitigate the influence of outliers and variability not attributed to the experimental manipulation. In practice, the choice between paired observations and independent random samples should be informed by the nature of the data, the study's goal, and practical constraints, as both methods have scenarios where they excel.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

An experiment was conducted involving 10 healthy runners and 10 healthy cyclists to determine if there are significant differences in pressure measurements within the anterior muscle compartment. \({ }^{8}\) The data - compartment pressure, in millimeters of mercury \((\mathrm{Hg})\) - are reproduced here: $$ \begin{array}{lcccc} &{2}{c} {\text { Runners }} & \text { Cyclists } \\ { 2 - 5 } \text { Condition } & \text { Mean }& \text { Standard } & & \text { Standard } \\\\\hline \text { Rest } & 14.5 & 3.92 & 11.1 & 3.98 \\\80 \% \text { maximal } & & & & \\\\\mathrm{O}_{2} \text { consumption } & 12.2 & 3.49 & 11.5 & 4.95 \\ \text { Maximal } & & & & \\\\\mathrm{O}_{2} \text { consumption } & 19.1 & 16.9 & 12.2 & 4.47\end{array} $$ For each of the three variables measured in this experiment, test to see whether there is a significant difference in the variances for runners versus cyclists. Find the approximate \(p\) -values for each of these tests. Will a two-sample \(t\) -test with a pooled estimate of \(\sigma^{2}\) be appropriate for all three of these variables? Explain.

Cerebral blood flow (CBF) in the brains of healthy people is normally distributed with a mean of 74 . A random sample of 25 stroke patients resulted in an average \(\mathrm{CBF}\) of 69.7 with a standard deviation of \(16.0 .\) a. Test the hypothesis that the standard deviation of CBF measurements for stroke patients is greater than \(\sigma=10\) at the \(\alpha=.05\) level of significance. b. Find bounds on the \(p\) -value for the test. Does this support your conclusion in part a? c. Find a \(95 \%\) confidence interval for \(\sigma^{2}\). Does it include the value \(\sigma^{2}=100 ?\) Does this validate your conclusion in part a?

The number of passes completed and the total number of passing yards recorded for the Los Angeles Chargers quarterback, Philip Rivers for each of the 15 regular season games that he played in the fall of \(2017^{13}\) were used to calculate the average number of yards per pass for each game. $$ \begin{array}{ccc|ccc} \hline & &{\text { Yards per }} & & &\text { Yards per } \\ \text { Week } & \text { Completions } & \text { Pass } & \text { Week } & \text { Completions } & \text { Pass } \\ \hline 1 & 28 & 13.8 & 9 & 17 & 12.5 \\ 2 & 22 & 13.2 & 11 & 15 & 12.2 \\ 3 & 20 & 11.4 & 12 & 25 & 10.7 \\ 4 & 18 & 17.7 & 13 & 21 & 12.3 \\ 5 & 31 & 11.1 & 14 & 22 & 15.8 \\ 6 & 27 & 16.1 & 15 & 20 & 11.8 \\ 7 & 20 & 12.6 & 16 & 31 & 10.7 \\ 8 & 21 & 17.2 & 17 & 22 & 8.7 \\ \hline \end{array} $$ a. Calculate the mean and standard deviation of the number of completions and the number of yards per pass. b. Find a \(95 \%\) confidence interval estimate for the variance of the number of completions. Why would you prefer a small variability in the number of completed passes? c. Find a \(95 \%\) confidence interval for \(\sigma^{2}\), the variance of the yards per pass. Use these results to find a \(95 \%\) confidence interval for \(\sigma,\) the standard deviation of the yards per pass. d. Test whether the standard deviation of the yards per pass for this quarterback differs from \(\sigma=4\) with \(\alpha=.05\)

The cost of auto insurance in California is dependent on many variables, such as the city you live in, the number of cars you insure, and your insurance company. The website www.insurance.ca.gov reports the annual 2017 standard premium for a male, licensed for \(6-8\) years, who drives a Honda Accord 20,000 to 24,000 kilometers per year and has no violations or accidents. \({ }^{12}\) $$\begin{array}{lll}\hline \text { City } & \text { Allstate } & \text { 21st Century } \\\\\hline \text { Long Beach } & \$ 3447 & \$ 3156 \\\\\text { Pomona } & 3572 & 3108 \\\\\text { San Bernardino } & 3393 & 3110 \\\\\text { Moreno Valley } & 3492 & 3300 \\\\\hline\end{array}$$ a. Why would you expect these pairs of observations to be dependent? b. Do the data provide sufficient evidence to indicate that there is a difference in the average annual premiums between Allstate and 21 st Century insurance? Test using \(\alpha=.01\) c. Find the approximate \(p\) -value for the test and interpret its value. d. Find a \(99 \%\) confidence interval for the difference in the average annual premiums for Allstate and 21 st Century insurance. e. Can we use the information in the table to make valid comparisons between Allstate and 21 st Century insurance throughout the United States? Why or why not?

Use the data given in Exercises \(12-13\) to test the given alternative hypothesis. Find the p-value for the test. Construct a \(95 \%\) confidence interval for \(\sigma_{1}^{2} / \sigma_{2}^{2}\) $$\begin{array}{ccc}\hline \text { Sample Size } & \text { Sample Variance } & H_{\mathrm{a}} \\\\\hline 13 & 18.3 & \sigma_{1}^{2}>\sigma_{2}^{2} \\\13 & 7.9 & \\\\\hline\end{array}$$

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.