Chapter 8: Problem 2
What are two characteristics of the best point estimator for a population parameter?
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none}
Learning Materials
Features
Discover
Chapter 8: Problem 2
What are two characteristics of the best point estimator for a population parameter?
These are the key concepts you need to understand to accurately answer the question.
All the tools & learning materials you need for study success - in one app.
Get started for free
A quality-control engineer wants to estimate the fraction of defectives in a large lot of printer ink cartridges. From previous experience, he feels that the actual fraction of defectives should be somewhere around .05. How large a sample should he take if he wants to estimate the true fraction to within .01, using a \(95 \%\) confidence interval?
State the Central Limit Theorem. Of what value is the Central Limit Theorem in large-sample statistical estimation?
One of the most famous large fractures (cracks) in the earth's crust is the San Andreas fault in California. A geologist attempting to study the movement of the earth's crust at a particular location found many fractures in the local rock structure. In an attempt to determine the mean angle of the breaks, she sampled \(n=50\) fractures and found the sample mean and standard deviation to be \(39.8^{\circ}\) and \(17.2^{\circ},\) respectively. Estimate the mean angular direction of the fractures and find the margin of error for your estimate.
A random sample of \(n=64\) observations has a mean \(\bar{x}=29.1\) and a standard deviation \(s=3.9 .\) a. Give the point estimate of the population mean \(\mu\) and find the margin of error for your estimate. b. Find a \(90 \%\) confidence interval for \(\mu\). What does "90\% confident" mean? c. Find a \(90 \%\) lower confidence bound for the population mean \(\mu\). Why is this bound different from the lower confidence limit in part b? d. How many observations do you need to estimate \(\mu\) to within .5, with probability equal to \(.95 ?\)
A sampling of political candidates- 200 randomly chosen from the West and 200 from the East-was classified according to whether the candidate received backing by a national labor union and whether the candidate won. In the West, 120 winners had union backing, and in the East, 142 winners were backed by a national union. Find a \(95 \%\) confidence interval for the difference between the proportions of union-backed winners in the West versus the East. Interpret this interval.
What do you think about this solution?
We value your feedback to improve our textbook solutions.