/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 58 A hardwoods manufacturing plant ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A hardwoods manufacturing plant has a production line designed to produce baseball bats weighing 32 ounces. During a period of time when the production process was known to be in statistical control, the average bat weight was found to be 31.7 ounces. The observed data were gathered from 50 samples, each consisting of 5 measurements. The standard deviation of all samples was found to be \(s=.2064\) ounces. Construct an \(\bar{x}\) -chart to monitor the 32 -ounce bat production process.

Short Answer

Expert verified
Answer: The upper control limit (UCL) is 31.8191 ounces, and the lower control limit (LCL) is 31.5809 ounces.

Step by step solution

01

Calculate the average and sample size

The given average of the bat weights is \(\bar{x} = 31.7\) ounces. Given that there are 50 samples with 5 measurements each, the sample size \(n = 5\) and the total number of samples is \(k = 50\).
02

Calculate the standard deviation

The given standard deviation of all samples is \(s = .2064\) ounces.
03

Calculate the control limits

To calculate the control limits, we first need to determine the average of the standard deviations, which can be expressed as \(\bar{s} =.2064\). Then, we need to find the control chart factors \(A_2\) for a sample size of 5. The \(A_2\) value can be found in statistical quality control books or online tables. For a sample size of 5, \(A_2 = 0.577\). Now, we can calculate the control limits for the \(\bar{x}\)-chart: Upper control limit (UCL): \(UCL = \bar{x} + A_2\bar{s} = 31.7 + 0.577(0.2064) = 31.7 + 0.1191 = 31.8191\). Lower control limit (LCL): \(LCL = \bar{x} - A_2\bar{s} = 31.7 - 0.577(0.2064) = 31.7 - 0.1191 = 31.5809\).
04

Construct the \(\bar{x}\)-chart

To construct the \(\bar{x}\)-chart, plot the average bat weight, the upper control limit, and the lower control limit on the vertical axis, and the sample number on the horizontal axis. 1. Mark the average bat weight of 31.7 ounces as a solid horizontal line across the chart. 2. Mark the upper control limit of 31.8191 ounces as a dashed horizontal line above the average. 3. Mark the lower control limit of 31.5809 ounces as a dashed horizontal line below the average. 4. For each of the 50 samples, plot their average bat weight on the chart, connecting the points with lines. The chart should show the average bat weight of each sample and its variation with the control limits. If all points are within the control limits, the production process can be considered stable. Any points outside the control limits indicate an out-of-control process.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Control Chart
A Control Chart is a graphical tool used in statistical quality control to monitor a process over time. It helps to determine if a manufacturing or business process is in a state of statistical control.
The core idea is to visualize variations of a process and identify whether they are within acceptable limits, or if they signify an "out of control" condition.
In the context of the hardwood manufacturing plant, a control chart is used to monitor the production of 32-ounce baseball bats. By plotting the average weight of samples, any variations from the expected performance can be quickly identified.
Control charts typically include:
  • A central line (CL), representing the average or target value of a process.
  • Upper and lower control limits (UCL and LCL) to signify the acceptable range of variations.
  • Data points that show measurements over time, which are plotted and analyzed.
This data visualization is crucial for ongoing quality assurance and can guide the troubleshooting and improvements within a process.
Standard Deviation
Standard Deviation is a measure that quantifies the amount of variation or dispersion in a set of values. In statistical quality control, it's used to determine process variability and monitor consistency.
In the exercise, the standard deviation (\( s = 0.2064 \) ounces) reflects the spread in bat weights around the average weight of 31.7 ounces.
A small standard deviation means the data points tend to be close to the mean, implying more consistency in the process. Conversely, a larger standard deviation indicates more variation which may mean a less stable process.
Understanding standard deviation is essential for setting control limits in a chart. It helps define the typical range of variations within which a process is considered to be "in control."
Sample Size
Sample Size (\( n \)) refers to the number of observations in each sample used to monitor a process. It directly affects the reliability of the control chart's indications.
In the exercise, each sample consists of 5 measurements, and there are 50 such samples. This size is crucial, as it influences the calculation of control limits and the overall sensitivity of the control chart.
A larger sample size generally provides more reliable data, minimizing the effect of variability in individual measurements. However, too large of a sample can be costly and may not provide significantly better insights in some cases. Therefore, selecting an optimal sample size is key to obtaining accurate results efficiently.
Upper Control Limit
The Upper Control Limit (UCL) is the highest value that a process can reach and still be considered "in control." It represents the threshold above which variations in a process' output are deemed unacceptable.
For the bat production line, the UCL was calculated to be 31.8191 ounces. This is determined using the mean weight (\( \bar{x} \)) and a factor of standard deviation (\( A_2 \)) specific to the sample size. It is crucial in monitoring as it helps to determine if the process is drifting upwards, indicating possible issues like overfilling or excess material usage.
By keeping outputs below the UCL, quality control is maintained, ensuring consistent product output.
Lower Control Limit
The Lower Control Limit (LCL) defines the lowest boundary within which process variations are considered "in control." It acts as a guardrail to ensure that the process doesn't produce output too low in value.
In the hardwood baseball bat context, the LCL is set at 31.5809 ounces. Calculated similarly to the UCL but marking the acceptable lower range, it prevents issues like underweight products which may be due to inadequate material usage or processing errors.
Adhering to the LCL ensures that the output consistently meets minimum quality and performance expectations. Ensuring processes run within both the upper and lower limits maintains stability and reliability.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Random samples of size \(n=500\) were selected from a binomial population with \(p=.1\). a. Is it appropriate to use the normal distribution to approximate the sampling distribution of \(\hat{p} ?\) Check to make sure the necessary conditions are met. Using the results of part a, find these probabilities: b. \(\hat{p}>.12\) c. \(\hat{p}<.10\) d. \(\hat{p}\) lies within .02 of \(p\)

Sports that involve a significant amount of running, jumping, or hopping put participants at risk for Achilles tendinopathy (AT), an inflammation and thickening of the Achilles tendon. A study in The American Journal of Sports Medicine looked at the diameter (in \(\mathrm{mm}\) ) of the affected and nonaffected tendons for patients who participated in these types of sports activities. \({ }^{10}\) Suppose that the Achilles tendon diameters in the general population have a mean of 5.97 millimeters (mm) with a standard deviation of \(1.95 \mathrm{~mm}\). a. What is the probability that a randomly selected sample of 31 patients would produce an average diameter of \(6.5 \mathrm{~mm}\) or less for the nonaffected tendon? b. When the diameters of the affected tendon were measured for a sample of 31 patients, the average diameter was \(9.80 .\) If the average tendon diameter in the population of patients with \(\mathrm{AT}\) is no different than the average diameter of the nonaffected tendons \((5.97 \mathrm{~mm}),\) what is the probability of observing an average diameter of 9.80 or higher? c. What conclusions might you draw from the results of part b?

A paper manufacturer requires a minimum strength of 20 pounds per square inch. To check on the quality of the paper, a random sample of 10 pieces of paper is selected each hour from the previous hour's production and a strength measurement is recorded for each. Assume that the strength measurements are normally distributed with a standard deviation \(\sigma=2\) pounds per square inch. a. What is the approximate sampling distribution of the sample mean of \(n=10\) test pieces of paper? b. If the mean of the population of strength measurements is 21 pounds per square inch, what is the approximate probability that, for a random sample of \(n=10\) test pieces of paper, \(\bar{x}<20 ?\) c. What value would you select for the mean paper strength \(\mu\) in order that \(P(\bar{x}<20)\) be equal to \(.001 ?\)

Lists In many states, lists of possible jurors are assembled from voter registration lists and Department of Motor Vehicles records of licensed drivers and car owners. In what ways might this list not cover certain sectors of the population adequately?

In Exercise \(1.67,\) Allen Shoemaker derived a distribution of human body temperatures with a distinct mound shape. \(^{9}\) Suppose we assume that the temperatures of healthy humans are approximately normal with a mean of \(98.6^{\circ}\) and a standard deviation of \(0.8^{\circ} .\) a. If 130 healthy people are selected at random, what is the probability that the average temperature for these people is \(98.25^{\circ}\) or lower? b. Would you consider an average temperature of \(98.25^{\circ}\) to be an unlikely occurrence, given that the true average temperature of healthy people is \(98.6^{\circ} ?\) Explain.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.