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Suppose that one out of every 10 homeowners in the state of California has invested in earthquake insurance. If 15 homeowners are randomly chosen to be interviewed, a. What is the probability that at least one had earthquake insurance? b. What is the probability that four or more have earthquake insurance? c. Within what limits would you expect the number of homeowners insured against earthquakes to fall?

Short Answer

Expert verified
Short Answer: A. The probability of at least one homeowner having earthquake insurance, P(X >= 1), is 1 - (0.9)^15. B. The probability of four or more homeowners having earthquake insurance, P(X >= 4), is 1 - P(X <= 3), where P(X <= 3) is the sum of the binomial probabilities for k = 0, 1, 2, and 3. C. Using the empirical rule for binomial distribution, we calculate the mean as (15 * 0.1) and the standard deviation as sqrt(15 * 0.1 * (1-0.1)). The limits for the number of homeowners insured against earthquakes can be found by adding and subtracting the standard deviation from the mean and rounding to whole numbers.

Step by step solution

01

Calculate the probability of no homeowner having earthquake insurance

We can find the probability of no homeowner having earthquake insurance first. That would be when all 15 homeowners, in our sample of 15, do not have insurance: P(X = 0) = C(15, 0) * (0.1)^0 * (0.9)^15 Note that C(n, 0) is always 1 and a^0 is always 1, so we can simplify this to: P(X = 0) = (0.9)^15
02

Subtract the probability from 1

Since we're looking for the probability of at least one homeowner having insurance, we can subtract the probability of no homeowner having insurance from 1: P(X >= 1) = 1 - P(X = 0) = 1 - (0.9)^15 #a. Probability of four or more homeowners having earthquake insurance#
03

Calculate the probability of 0, 1, 2, and 3 homeowners having earthquake insurance

Calculate the probabilities for each individual case and sum them up: P(X <= 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) Apply the binomial probability formula for each value of k = 0, 1, 2, and 3: P(X <= 3) = C(15, 0) * (0.1)^0 * (0.9)^15 + C(15, 1) * (0.1)^1 * (0.9)^14 + C(15, 2) * (0.1)^2 * (0.9)^13 + C(15, 3) * (0.1)^3 * (0.9)^12
04

Subtract the probability from 1

Since we're looking for the probability of four or more homeowners having insurance, we can subtract the probability of three or fewer from 1: P(X >= 4) = 1 - P(X <= 3) #c. Limits for the number of homeowners insured against earthquakes#
05

Calculate the mean and standard deviation

The mean and standard deviation for a binomial distribution with parameters n and p are given by: mean = n * p standard deviation = sqrt(n * p * (1-p)) Calculate the mean and standard deviation for our problem with n = 15 and p = 0.1: mean = 15 * 0.1 standard deviation = sqrt(15 * 0.1 * (1-0.1))
06

Calculate the limits

We can find the limits for the number of homeowners insured against earthquakes by applying the empirical rule, which states that about 68% of data lies within one standard deviation of the mean. Lower limit = mean - standard deviation Upper limit = mean + standard deviation We should round the limits to whole numbers since we're dealing with a discrete variable (the number of homeowners).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability Calculations
Probability calculations involve determining the likelihood of a particular event occurring among a set of possibilities. In our exercise about earthquake insurance for homeowners, we used the binomial distribution model. This model is well-suited for scenarios where there are only two outcomes: either an event occurs or it does not. Each trial is independent and has the same probability of success.

Here's a quick breakdown of the key probability calculations from the exercise:
  • P(X = 0): The probability of no homeowners having insurance is calculated with the formula: \[ P(X = 0) = (0.9)^{15} \] because each homeowner not having insurance has a probability of 0.9, repeated 15 times.
  • P(X \geq 1): To calculate the probability of at least one homeowner having insurance, subtract the probability of none being insured from 1:
  • \[ P(X \geq 1) = 1 - (0.9)^{15} \]
  • P(X \geq 4): To find this, first compute the total probability for 0, 1, 2, and 3 having insurance. Then, subtract this result from 1 to find the probability of 4 or more:
  • \[ P(X \geq 4) = 1 - (P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)) \]
Understanding these calculations helps us predict and prepare for different outcomes effectively.
Insurance Statistics
In the world of insurance, statistics play a crucial role, particularly when assessing risks and determining premiums. Insurance companies often employ statistical models, such as the binomial distribution, to evaluate the probability of potential claims. In our scenario, the focus was on homeowners who have or have not invested in earthquake insurance.

There are several reasons why statistical analysis is vital in insurance:
  • Risk Assessment: By analyzing historical data about insured and uninsured homeowners, insurers can predict future trends and potential risks effectively. This helps in making informed decisions about coverage.
  • Premium Calculation: Insurers use statistical data to assess the likelihood of an event, such as an earthquake, which influences the premium charged. More frequent or likely events often result in higher premiums.
  • Decision-making: Statistical models aid in understanding the distribution of insured homeowners, assisting companies in determining whether they need to adjust their strategies or offer incentives for homeowners to get insured.
Thus, insurance statistics are not only about numbers but are pivotal for managing risk and pricing effectively.
Empirical Rule
The empirical rule, also known as the 68-95-99.7 rule, is a handy concept in statistics that applies primarily to normal distributions. However, it can also give insights in other settings. It states that for a normal distribution:
  • 68% of values fall within one standard deviation of the mean,
  • 95% lie within two standard deviations, and
  • 99.7% are within three standard deviations.
Although the binomial distribution may not perfectly align with a normal distribution, the empirical rule provides a rough guideline for where most data points will lie.

For example, with our exercise on homeowners and earthquake insurance, calculating the mean and standard deviation allows us to estimate the typical number of insured homeowners: \[\text{mean} = n \times p = 15 \times 0.1 = 1.5 \]\[\text{standard deviation} = \sqrt{n \times p \times (1-p)} = \sqrt{15 \times 0.1 \times 0.9}\]Using these, we could expect that about 68% of the time, the number of insured homeowners will fall between:
  • Lower limit: mean - standard deviation
  • Upper limit: mean + standard deviation
This gives an intuitive sense of variation in the data. Despite the discrete nature of our problem, the empirical rule provides a useful approximation for understanding statistical dispersion.

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Most popular questions from this chapter

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