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Evidence shows that the probability that a driver will be involved in a serious automobile accident during a given year is .01. A particular corporation employs 100 full-time traveling sales reps. Based on this evidence, use the Poisson approximation to the binomial distribution to find the probability that exactly two of the sales reps will be involved in a serious automobile accident during the coming year.

Short Answer

Expert verified
Answer: The probability that exactly two sales reps will have a serious automobile accident in the coming year is approximately 0.18394 or 18.39%.

Step by step solution

01

Write down the Poisson distribution formula

Recall the Poisson distribution formula: P(X = k) = (e^(-λ) * (λ^k)) / k! where λ is the mean number of accidents, k is the number of accidents we want to find the probability for, and e is the base of the natural logarithm.
02

Plug in the values

For this problem, λ = 1 (mean number of accidents), k = 2 (number of accidents we want the probability for), and e ≈ 2.71828. Plug the values into the formula: P(X = 2) = (e^(-1) * (1^2)) / 2!
03

Calculate the probability

Perform the calculations: P(X = 2) = (2.71828^(-1) * (1^2)) / 2 P(X = 2) ≈ (0.36788 * 1) / 2 P(X = 2) ≈ 0.18394 So, the probability that exactly two sales reps will be involved in a serious automobile accident during the coming year is approximately 0.18394 or 18.39%.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding the Binomial Distribution
The binomial distribution is a common way to model situations where there are only two possible outcomes: success or failure. It's especially useful in scenarios where you're conducting an experiment several times, and each time the likelihood of success is constant.
In the original exercise, the scenario involves drivers who may or may not be involved in a car accident, and it can be seen as a binomial distribution. However, when dealing with a large number of trials (in this case, 100 sales reps) and a small probability of success (0.01, where success refers to having an accident), it becomes more efficient to use a different approach. This is where the Poisson distribution can approximate the binomial distribution very well.
  • This approximation is valid when the number of trials is large, and the probability of success is small.
  • The Poisson distribution helps simplify calculations that might otherwise be complex with the binomial distribution.
Understanding when and why to use these distributions is vital for solving real-world statistical problems efficiently.
Exploring Probability in the Context
Probability is the field of mathematics that deals with the likelihood or chance of different outcomes occurring. In the context of the Poisson approximation to the binomial distribution, it's all about estimating how often an event will occur in a given period.
For our exercise, the main task was to calculate the probability of exactly two sales reps being involved in a serious accident in one year, using the Poisson distribution.
  • This involves knowing two key parameters: the mean number of events (accidents, in this case) that occur, represented as \( \lambda \), and the set number of events we want to calculate the probability for.
  • Probability is a crucial component that enables accurate forecasting and decision-making in various fields.
By refining and understanding these probabilities, businesses and governments can make informed choices about resource allocation and risk management.
Mean Number of Events: Why It Matters
The term \( \lambda \) in the Poisson formula represents the mean number of events expected to occur in a fixed interval of time or space. It's essential because it simplifies how we calculate probabilities for rare events happening a given number of times.
In the example provided, the mean number of sales reps expected to be involved in serious car accidents is calculated by multiplying the total number of sales reps (100) by the probability of each being involved in an accident (0.01), thus \( \lambda = 100 \times 0.01 = 1.0 \).
  • This mean number forms the backbone of the Poisson calculation, allowing us to plug in values and compute probabilities with ease.
  • Understanding \( \lambda \) fully helps in anticipating the behavior of rare events across broader time frames and situations.
Effectively, it offers a lens through which statisticians and analysts can predict frequencies of occurrences efficiently, influencing how safety measures and preventive actions are considered.

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Most popular questions from this chapter

The National Hockey League (NHL) has \(80 \%\) of its players born outside the United States, and of those born outside the United States, \(50 \%\) are born in Canada. \(^{2}\) Suppose that \(n=12\) NHL players were selected at random. Let \(x\) be the number of players in the sample who were born outside of the United States so that \(p=.8\). Find the following probabilities: a. At least five or more of the sampled players were born outside the United States. b. Exactly seven of the players were born outside the United States. c. Fewer than six were born outside the United States.

A new surgical procedure is said to be successful \(80 \%\) of the time. Suppose the operation is performed five times and the results are assumed to be independent of one another. What are the probabilities of these events? a. All five operations are successful. b. Exactly four are successful. c. Less than two are successful.

Suppose that \(10 \%\) of the fields in a given agricultural area are infested with the sweet potato whitefly. One hundred fields in this area are randomly selected and checked for whitefly. a. What is the average number of fields sampled that are infested with whitefly? b. Within what limits would you expect to find the number of infested fields, with probability approximately \(95 \% ?\) c. What might you conclude if you found that \(x=25\) fields were infested? Is it possible that one of the characteristics of a binomial experiment is not satisfied in this experiment? Explain.

Under what conditions would you use the hypergeometric probability distribution to evaluate the probability of \(x\) successes in \(n\) trials?

One model for plant competition assumes that there is a zone of resource depletion around each plant seedling. Depending on the size of the zones and the density of the plants, the zones of resource depletion may overlap with those of other seedlings in the vicinity. When the seeds are randomly dispersed over a wide area, the number of neighbors that a seedling may have usually follows a Poisson distribution with a mean equal to the density of seedlings per unit area. Suppose that the density of seedlings is four per square meter \(\left(\mathrm{m}^{2}\right)\). a. What is the probability that a given seedling has no neighbors within \(1 \mathrm{~m}^{2} ?\) b. What is the probability that a seedling has at most three neighbors per \(\mathrm{m}^{2}\) ? c. What is the probability that a seedling has five or more neighbors per \(\mathrm{m}^{2} ?\) d. Use the fact that the mean and variance of a Poisson random variable are equal to find the proportion of neighbors that would fall into the interval \(\mu \pm 2 \sigma .\) Comment on this result.

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