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A jar contains four coins: a nickel, a dime, a quarter, and a half-dollar. Three coins are randomly selected from the jar. a. List the simple events in \(S\). b. What is the probability that the selection will contain the half-dollar? c. What is the probability that the total amount drawn will equal \(60 \phi\) or more?

Short Answer

Expert verified
Answer: The probability is 0.75.

Step by step solution

01

List the possible outcomes

To list the simple events in the sample space S, we will write down all the possible ways of selecting three coins from the jar. They are: 1. Nickel, Dime, Quarter (NDQ) 2. Nickel, Dime, Half-Dollar (NDH) 3. Nickel, Quarter, Half-Dollar (NQH) 4. Dime, Quarter, Half-Dollar (DQH)
02

Calculate the total number of outcomes

Since there are only four possible outcomes for this problem, the total number of outcomes is 4.
03

Find the favorable outcomes for selecting the half-dollar

To find the probability that the selection will contain the half-dollar, count the number of outcomes from Step 1 in which the half-dollar is present. We have: 1. Nickel, Dime, Half-Dollar (NDH) 2. Nickel, Quarter, Half-Dollar (NQH) 3. Dime, Quarter, Half-Dollar (DQH) There are 3 favorable outcomes.
04

Calculate the probability of selecting the half-dollar

Now, divide the number of favorable outcomes by the total number of outcomes to get the probability: \(P\)(Half-Dollar) = \(\frac{3}{4}\) = 0.75
05

Find the favorable outcomes for selecting a total amount equal to or greater than 60 cents

To find the probability that the total amount drawn will equal to or greater than 60 cents, count the number of outcomes from Step 1 with a total value of at least 60 cents. We have: 1. Nickel, Dime, Half-Dollar (NDH): 5 + 10 + 50 = 65 cents 2. Nickel, Quarter, Half-Dollar (NQH): 5 + 25 + 50 = 80 cents 3. Dime, Quarter, Half-Dollar (DQH): 10 + 25 + 50 = 85 cents There are 3 favorable outcomes.
06

Calculate the probability of selecting a total amount equal to or greater than 60 cents

Divide the number of favorable outcomes by the total number of outcomes to get the probability: \(P\)(Total amount \(\geq\) 60 cents) = \(\frac{3}{4}\) = 0.75 In conclusion: a) The simple events in the sample space S are {NDQ, NDH, NQH, DQH}. b) The probability that the selection will contain the half-dollar is 0.75. c) The probability that the total amount drawn will equal 60 cents or more is 0.75.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sample Space
In probability, the concept of a sample space refers to the set of all possible outcomes of a particular experiment or random process. Think of it as the complete list of every event that could happen when performing an activity. In our exercise, the sample space is determined by the act of selecting three coins from a jar containing a nickel, a dime, a quarter, and a half-dollar.
To find the sample space, you list all permutations of the activity. For the exercise at hand, the problem involves selecting coins. By examining the different combinations, we find the following simple events or outcomes in the sample space:
  • Nickel, Dime, Quarter (NDQ)
  • Nickel, Dime, Half-Dollar (NDH)
  • Nickel, Quarter, Half-Dollar (NQH)
  • Dime, Quarter, Half-Dollar (DQH)
These four outcomes represent the complete sample space, as they cover all potential groupings of three coins picked from the jar.
Favorable Outcomes
Favorable outcomes are the particular outcomes from the sample space that satisfy a given condition or event. In the context of our exercise, we see this in step three where we focus on selecting a half-dollar among the three coins.
To determine which outcomes involve the half-dollar, review the list of possible events:
  • Nickel, Dime, Half-Dollar (NDH)
  • Nickel, Quarter, Half-Dollar (NQH)
  • Dime, Quarter, Half-Dollar (DQH)
Here, three of the four possible events include the half-dollar, making them our favorable outcomes. Whether figuring out if something specific is included (like the half-dollar), or achieving a particular condition (such as reaching a specific total value), favorable outcomes help narrow down and identify what fits within these criteria.
Probability Calculation
Probability calculation is the method of determining how likely it is for a particular outcome to occur. It is calculated by dividing the number of favorable outcomes by the total number of possible outcomes.
From our sample space and favorable outcomes, let's calculate the probability of selecting the half-dollar: The total number of outcomes is four, and the number of favorable outcomes where the selection includes the half-dollar is three. So, the probability is calculated as follows:\[P(\text{Half-Dollar}) = \frac{3}{4} = 0.75\]Thus, the probability of drawing a selection that includes the half-dollar from the jar of coins is 0.75, or 75%.In addition to merely selecting coins, probability calculation is also applied to situations where certain conditions must be met. For instance, finding the probability that the total value of selected coins is at least 60 cents follows similar steps: with the same number of favorable outcomes as before, we again use:\[P(\text{Total amount} \geq 60 \text{ cents}) = \frac{3}{4} = 0.75\]
Simple Events
Simple events represent the most basic possible outcomes of a probability experiment. They occur when a single event is considered without any additional conditions or combinations.
In our coin selection scenario, each combination of three selected coins forms a simple event. These simple events are specific and cannot be broken down into smaller outcomes. For instance:
  • NDQ: Nickel, Dime, Quarter
  • NDH: Nickel, Dime, Half-Dollar
  • NQH: Nickel, Quarter, Half-Dollar
  • DQH: Dime, Quarter, Half-Dollar
Understanding simple events helps in identifying the foundational outcomes within a sample space which, when combined, form more complex events or help in easily calculating probabilities by focusing on individual outcomes.

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Most popular questions from this chapter

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