/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 37 A woman brought a complaint of g... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A woman brought a complaint of gender discrimination to an eight-member human relations advisory board. The board, composed of five women and three men, voted \(5-3\) in favor of the plaintiff, the five women voting for the plaintiff and the three men against. Has the board been affected by gender bias? That is, if the vote in favor of the plaintiff was \(5-3\) and the board members were not biased by gender, what is the probability that the vote would split along gender lines (five women for, three men against)?

Short Answer

Expert verified
Answer: The probability is \(\frac{7}{32}\).

Step by step solution

01

Determine the size of the sample space

Since there are 8 members on the board, each with 2 options (vote for or against), there are 2^8 possible vote combinations.
02

Define a vote combination

A vote combination is defined as the number of ways the board could vote for the plaintiff. For example, the given vote combination is 5 votes in favor (five women) and 3 votes against (three men).
03

Calculate the binomial coefficient for the given vote combination

We can use the binomial coefficient formula to find the number of ways the given vote combination of 5 votes in favor (from a total of 8 members) can occur: Number of Ways = \(\binom{8}{5}\) = \(\frac{8!}{5!(8-5)!}\) = 56 ways
04

Determine the probability of the given vote combination

Now we need to find the probability of the given vote combination happening if the members were not biased by gender. Since we assume that each member can either vote in favor or against with equal probability (not biased), the probability of the given vote combination would be the number of ways that combination can happen divided by the total number of possible vote combinations: Probability of given vote combination = \(\frac{Number\:of\:Ways}{Total\:number\:of\:possible\:vote\:combinations}\) = \(\frac{56}{2^8}\) = \(\frac{56}{256}\) = \(\frac{7}{32}\) The probability that the vote would split along gender lines (five women for, three men against) if the board members were not biased by gender is \(\frac{7}{32}\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Binomial Coefficient
The binomial coefficient is a mathematical tool used to count how many ways you can choose items from a larger pool without caring about the order of those items. In our exercise, the coefficient helps determine how many different ways five people can vote in favor from a total of eight members, which forms part of our analysis for a possible bias.

The formula to find a binomial coefficient is represented as \( \binom{n}{k} \) and is equal to \( \frac{n!}{k!(n-k)!} \), where \( n \) is the total number of items to choose from, \( k \) is the number of items chosen, and \( ! \) denotes factorial, meaning the product of all positive integers up to that number.

In the exercise, using \( \binom{8}{5} \), you calculate the number of ways the board could have voted 5-3. After applying the formula, you find there are 56 ways of forming this particular voting combination. The binomial coefficient, thus, is crucial in establishing the number of possible unbiased vote outcomes.
Sample Space
The sample space in probability theory refers to all possible outcomes of an experiment or event. In our case, the "experiment" is the board members casting their votes, each having a choice to vote either for or against.

For this scenario with eight board members and two voting options for each ("for" or "against"), the sample space is vast. It includes all possible combinations of votes, totaling \( 2^8 \) or 256 unique possibilities. This comprehensive set of outcomes is essential as it represents the benchmark from which probabilities are derived.

Understanding the sample space allows us to appreciate the probability of any one specific voting outcome occurring, like a 5-3 split. This clarity is key to determining how likely it is that votes would naturally align along genders without bias.
Gender Bias
Gender bias occurs when an outcome is influenced by gender, rather than being a result of independent decision-making. Within the context of the exercise, we are questioning if the board's decision, with females favoring the plaintiff and males against, is due to gender bias.

To investigate this, we calculate the probability of the 5-3 vote split occurring naturally without bias. If the probability is particularly low, it might suggest bias; however, further analysis and context are necessary before reaching any conclusions. Calculating this probability aims to provide statistical evidence for or against the presence of gender bias in the board's decision-making process.

Interpreting these probabilities requires comprehensive understanding, as numerical results can highlight potential bias but do not confirm causation. Other factors could influence the decision beyond gender alignment.
Voting Probability
Voting probability examines the chance of various outcomes in a given voting situation, especially when assuming unbiased conditions. In the given exercise, calculating the probability of the 5-3 split without gender influence is central.

With objective factors considered, such as each member having an independent and equal likelihood of voting either way, the calculated probability of the 5-3 gender-aligned split is \( \frac{7}{32} \) or approximately 21.875%.

This percentage demonstrates a certain likelihood of this outcome occurring under the assumption of impartial voting. It serves as a benchmark to compare against potential bias indicators and understand the fairness of the voting process. Understanding voting probability allows analysts to differentiate between expected statistical outcomes and outliers that might suggest underlying biases or other influential factors.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Five cards are selected from a 52-card deck for a poker hand. a. How many simple events are in the sample space? b. A royal flush is a hand that contains the \(\mathrm{A}, \mathrm{K}, \mathrm{Q}, \mathrm{J},\) and 10 , all in the same suit. How many ways are there to get a royal flush? c. What is the probability of being dealt a royal flush?

A quality-control plan calls for accepting a large lot of crankshaft bearings if a sample of seven is drawn and none are defective. What is the probability of accepting the lot if none in the lot are defective? If \(1 / 10\) are defective? If \(1 / 2\) are defective?

You have \(t\) wo groups of distinctly different items, 10 in the first group and 8 in the second. If you select one item from each group, how many different pairs can you form?

Although there is legal protection for "whistle blowers" - employees who report illegal or unethical activities in the workplace- it has been reported that approximately \(23 \%\) of those who reported fraud suffered reprisals such as demotion or poor performance ratings. Suppose the probability that an employee will fail to report a case of fraud is .69. Find the probability that an employee who observes a case of fraud will report it and will subsequently suffer some form of reprisal.

A man takes either a bus or the subway to work with probabilities .3 and \(.7,\) respectively. When he takes the bus, he is late \(30 \%\) of the days. When he takes the subway, he is late \(20 \%\) of the days. If the man is late for work on a particular day, what is the probability that he took the bus?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.