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Refer to Exercise \(14.54 .\) The researcher wants to see if there is a difference in the color distributions for compact/sports cars versus full/intermediate cars. Another random sample of 250 full/intermediate cars was taken and the color of the vehicles was recorded. The table below shows the results for both compact/sports and full/intermediate cars. Do the data indicate that there is a difference in the color distributions depending on the type of vehicle? Use \(\alpha=.05 .\) (HINT: Remember to include a column called "Other" for cars that do not fall into one of the six categories shown in the table.)

Short Answer

Expert verified
Answer: __________ (Reject the null hypothesis and conclude that there is a significant difference in the color distributions for compact/sports cars and full/intermediate cars OR Fail to reject the null hypothesis and conclude that there is insufficient evidence to show a significant difference in the color distributions.)

Step by step solution

01

Formulate the hypotheses

The null hypothesis (H0) states that there is no significant difference between the color distributions for compact/sports cars and full/intermediate cars, while the alternative hypothesis (H1) states that there is a significant difference between the color distributions. H0: The color distributions are the same for compact/sports cars and full/intermediate cars. H1: The color distributions are different for compact/sports cars and full/intermediate cars.
02

Define the test statistic and significance level

We will use the chi-square test for independence as our test statistic, with a significance level (alpha) of 0.05.
03

Calculate the expected frequencies

Create a contingency table with the observed frequencies, and calculate the expected frequencies for each cell. The expected frequencies can be calculated using the formula: Expected frequency = (Row total * Column total) / Grand total
04

Calculate the chi-square test statistic

After calculating the expected frequencies, compute the chi-square test statistic using the following formula: Chi-square = Σ[(Observed frequency - Expected frequency)^2 / Expected frequency]
05

Determine the critical value and decision rule

Consult the chi-square distribution table with degrees of freedom (df) equal to (number of rows - 1) * (number of columns - 1) at a significance level of 0.05 to find the critical value. If the calculated chi-square test statistic is greater than the critical value, reject the null hypothesis. Otherwise, we fail to reject the null hypothesis.
06

Compare the calculated test statistic to the critical value

Compare the calculated chi-square test statistic from Step 4 to the critical value determined in Step 5. If the calculated test statistic is greater than the critical value, reject the null hypothesis. Otherwise, fail to reject the null hypothesis.
07

Draw the conclusion

Based on the comparison in Step 6, either reject the null hypothesis (H0) and conclude that there is a significant difference in the color distributions for compact/sports cars and full/intermediate cars, or fail to reject the null hypothesis and conclude that there is insufficient evidence to show a significant difference in the color distributions. Remember to include the "Other" category for cars that are not included in the six categories shown in the table.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Statistical Hypothesis Testing
Statistical hypothesis testing is a method used to determine if there is enough evidence to reject a null hypothesis. In the chi-square test for independence, which is often applied in these scenarios, we are trying to see if there's a significant relationship between two categorical variables.
Think of it as a way to analyze how likely it is that any observed difference between the data sets could simply be due to random chance, rather than a specific cause. This testing helps in making decisions by evaluating evidence collected in the form of sample data.
If the evidence strongly contradicts the null hypothesis, we reject it and accept the alternative. Otherwise, we fail to reject the null hypothesis if there is not enough evidence to support the claim of the alternative hypothesis.
Null and Alternative Hypotheses
In hypothesis testing, we begin with two rival hypotheses: the null and the alternative.
The **null hypothesis (H0)** serves as a default statement that there is no effect or no difference. In our exercise, it states that color distributions are the same for both vehicle types, compact/sports and full/intermediate.
The **alternative hypothesis (H1)** is what we aim to provide evidence for. According to our exercise, it posits that there is a difference in color distributions between the two vehicle categories.
Through hypothesis testing, we assess these positions via collected data, and make a decision whether to support or reject the null based on the evidence at hand.
Contingency Tables
Contingency tables are powerful tools used in statistics to display the frequency distribution of variables.
In the context of the chi-square test, we use a contingency table to present observed frequencies for different categories. For example, in our exercise, the table includes the frequency of different colors for each car type.
The constructed table helps us visually isolate the relationship between the two categories that are being studied (car type and color).
To conduct the chi-square test, we also calculate the expected frequency for each cell in the table using the formula: Expected frequency = (Row total * Column total) / Grand total.
This expected value serves as a comparison point for each observed frequency in our test.
Significance Level
The significance level, denoted as \(\alpha\) in hypothesis testing, is the threshold for determining whether to reject the null hypothesis.
It represents the probability of rejecting the null hypothesis when it is actually true, also known as the Type I error.
Common values for \(\alpha\) are 0.05, 0.01, or 0.10, with 0.05 being widely used, as seen in our exercise.
By setting \(\alpha = 0.05\), we're saying that we accept a 5% chance of incorrectly rejecting the null hypothesis.
When we calculate our chi-square test statistic, we compare it to a critical value from the chi-square distribution table, which is determined by this alpha level.
If the test statistic exceeds the critical value, we reject the null hypothesis, indicating a statistically significant difference at the chosen alpha level.

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Most popular questions from this chapter

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