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Who Votes? About three-fourths of voting age Americans are registered to vote, but many do not bother to vote on Election Day. Only \(64 \%\) voted in \(1992,\) and \(60 \%\) in \(2000,\) but turnout in off-year elections is even lower. An article in Time stated that \(35 \%\) of adult Americans are registered voters who always vote. \({ }^{10}\) To test this claim, a random sample of \(n=300\) adult Americans was selected and \(x=123\) were registered regular voters who always voted. Does this sample provide sufficient evidence to indicate that the percentage of adults who say that they always vote is different from the percentage reported in Time? Test using \(\alpha=.01\)

Short Answer

Expert verified
Answer: No, there is not enough evidence to conclude that the percentage of adult Americans who say they always vote is different from the 35% reported in Time.

Step by step solution

01

State the null and alternative hypotheses

The null hypothesis (\(H_0\)) is that there is no difference between the percentage of adult Americans who say they always vote and the percentage reported in Time (\(35 \%\)). The alternative hypothesis (\(H_a\)) is that there is a difference between these percentages. In mathematical terms: \(H_0: p = 0.35\) \(H_a: p \neq 0.35\)
02

Calculate the test statistic

For this test, we'll use the z-test for proportions. The test statistic is given by the formula: \(z = \frac{(\hat{p} - p_0)}{\sqrt{\frac{p_0(1-p_0)}{n}}}\) where \(\hat{p}\) is the sample proportion, \(p_0\) is the proportion under the null hypothesis, and \(n\) is the sample size. In our case, \(\hat{p} = \frac{x}{n} = \frac{123}{300}\), \(p_0 = 0.35\), and \(n = 300\). Plugging in these values, we get: \(z = \frac{(\frac{123}{300} - 0.35)}{\sqrt{\frac{0.35(1-0.35)}{300}}}\) Calculating the z-score gives: \(z \approx -1.96\)
03

Find the critical value and make a decision

Since we're doing a two-tailed test with a significance level of \(\alpha = 0.01\), we first find the critical values in a standard normal distribution that give us the rejection regions. In a two-tailed test, we split the \(\alpha\) equally in both tails. Using a standard normal distribution table or calculator, we find the critical values: \(Z_{\alpha/2} = \pm 2.576\) Now we compare our test statistic to our critical values. If our z-score is less than \(-2.576\) or greater than \(2.576\), we reject the null hypothesis. In our case, our z-score is approximately \(-1.96\). Since \(-1.96\) is not less than \(-2.576\) or greater than \(2.576\), we fail to reject the null hypothesis.
04

Conclusion

We fail to reject the null hypothesis at a significance level of \(\alpha = 0.01\). This means that we do not have enough evidence to conclude that the percentage of adult Americans who say they always vote is different from the percentage reported in Time (35%).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

z-test for proportions
The **z-test for proportions** is a statistical tool used to compare observed sample proportions to a known population proportion. In other words, it's a way to determine if there is a significant difference between a sample proportion and a specific known value. This test is applicable when you have a binary outcome, such as yes or no, vote or not vote.

In the exercise, a z-test for proportions is used to check if the proportion of adult Americans who always vote, as claimed by Time magazine (35%), matches with our sample data. To do this:
  • First, calculate the sample proportion (\(\hat{p}\)), which is the number of successes (in our exercise, the number of people who always vote) divided by the total sample size.
  • The z-score then measures how many standard deviations the observed sample proportion is away from the hypothesized population proportion, using:\[z = \frac{(\hat{p} - p_0)}{\sqrt{\frac{p_0(1-p_0)}{n}}}\]
A significant z-score indicates a difference between the sample proportion and the claimed population proportion.
null and alternative hypotheses
When conducting a hypothesis test, you start by stating the **null and alternative hypotheses**. These hypotheses are statements about a population parameter (typically a proportion or a mean) that you want to test. The null hypothesis (\(H_0\)) is a statement that there is no effect or no difference, while the alternative hypothesis (\(H_a\)) represents what you want to prove or the presence of an effect.

For the problem at hand, the null hypothesis is that the proportion of adult Americans who always vote is equal to 35%, as reported by Time. In symbol form, it's:\[H_0: p = 0.35\]The alternative hypothesis is that the actual proportion is different from this reported value. This two-tailed hypothesis is expressed as:\[H_a: p eq 0.35\]Choosing between these hypotheses involves statistical testing to see if there is enough evidence to support the alternative over the null. In hypothesis testing, failing to reject the null does not confirm it, but rather indicates insufficient evidence to support the alternative.
significance level
The **significance level** in hypothesis testing, denoted by \(\alpha\), is the threshold used to determine whether the null hypothesis should be rejected. It is a pre-determined probability of making a Type I error - rejecting a true null hypothesis.

In practice, it indicates how willing we are to risk being wrong if we claim there is an effect or a difference when there isn't one. Common significance levels are 0.05, 0.01, and 0.10. In this exercise, the significance level is set at 0.01, meaning there's a 1% risk we wrongly reject the null hypothesis.

When using this significance level in a two-tailed z-test, as in the exercise, you identify the critical z-values that frame the rejection region. For \(\alpha = 0.01\), these critical values in a standard normal distribution would be \(Z_{\alpha/2} = \pm 2.576\). These cutoffs indicate the points beyond which the null hypothesis is rejected if the test statistic falls outside this range.

Setting up a proper significance level helps make informed decisions based on your hypothesis test outcomes.

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Most popular questions from this chapter

A random sample of \(n=1000\) observations from a binomial population produced \(x=279 .\) a. If your research hypothesis is that \(p\) is less than .3 , what should you choose for your alternative hypothesis? Your null hypothesis? b. What is the critical value that determines the rejection region for your test with \(\alpha=.05 ?\) c. Do the data provide sufficient evidence to indicate that \(p\) is less than .3 ? Use a \(5 \%\) significance level.

Find the appropriate rejection regions for the large-sample test statistic \(z\) in these cases: a. A right-tailed test with \(\alpha=.01\) b. A two-tailed test at the \(5 \%\) significance level c. A left-tailed test at the \(1 \%\) significance level d. A two-tailed test with \(\alpha=01\)

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Put on the Brakes The braking ability was compared for two 2012 automobile models. Random samples of 64 automobiles were tested for each type. The recorded measurement was the distance (in feet) required to stop when the brakes were applied at 50 miles per hour. These are the computed sample means and variances: Do the data provide sufficient evidence to indicate a difference between the mean stopping distances for the two models?

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