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A manufacturing process is designed to produce an electronic component for use in small portable television sets. The components are all of standard size and need not conform to any measurable characteristic, but are sometimes inoperable when emerging from the manufacturing process. Fifteen samples were selected from the process at times when the process was known to be in statistical control. Fifty components were observed within each sample, and the number of inoperable components was recorded. $$6,7,3,5,6,8,4,5,7,3,1,6,5,4,5$$ Construct a \(p\) chart to monitor the manufacturing process.

Short Answer

Expert verified
Based on the step-by-step solution provided: Question: Calculate the proportion of inoperable components in a sample of 50 electronic components, given that 6 components are inoperable. Answer: To calculate the proportion of inoperable components, divide the inoperable components by the total number of components in the sample. In this case, there are 6 inoperable components out of 50: Proportion of inoperable components = (6 / 50) = 0.12

Step by step solution

01

Calculate the average proportion of inoperable components (\(\bar{p}\))

To calculate the average proportion of inoperable components, we need to first find the total number of inoperable components and divide it by the total number of components observed. Given the number of inoperable components in each of the 15 samples: 6, 7, 3, 5, 6, 8, 4, 5, 7, 3, 1, 6, 5, 4, 5. Total number of inoperable components (sum of the above): 70 Total number of components observed is 50 components per sample * 15 samples: 750 So, \(\bar{p} = \frac{70}{750} = 0.0933\).
02

Calculate the StandardDeviation, Upper Control Limit(UCL) and Lower Control Limit(LCL)

To calculate the standard deviation, we need to use the following formula: \(SD = \sqrt{\frac{\bar{p}(1-\bar{p})}{n}}\), where \(n\) is the number of components in each sample. In our case, \(\bar{p} = 0.0933\) and \(n = 50\). Therefore, $$SD = \sqrt{\frac{0.0933(1-0.0933)}{50}} = 0.0427$$ Now, we can calculate the Upper Control Limit (UCL) and Lower Control Limit (LCL) using the following formulas: $$UCL = \bar{p} + 3 \cdot SD = 0.0933 + 3 \cdot 0.0427 = 0.2214$$ $$LCL = \bar{p} - 3 \cdot SD = 0.0933 - 3 \cdot 0.0427 = -0.0348$$ Since the LCL is negative (which cannot happen in this case), we set the LCL to zero. So the final control limits are: UCL = 0.2214 LCL = 0
03

Plot the p-chart

To create the p-chart, we will follow these steps: 1. Create a chart with the sample numbers (1 to 15) on the x-axis, and the proportion of inoperable components on the y-axis. 2. For each sample, calculate the proportion of inoperable components and plot the points on the graph. 3. Draw the average proportion line at \(\bar{p} = 0.0933\). 4. Draw the Upper Control Limit (UCL) line at 0.2214 and Lower Control Limit (LCL) line at 0. 5. Examine the chart to check if any of the points fall outside the control limits, as this would indicate that the process is not in control. After constructing the p-chart based on the given data and calculated control limits, you'll have a visual representation of the manufacturing process quality, which can help identify if the process is in statistical control or not.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Control Limits
Control limits are a pivotal concept in quality control charts, like the \(p \) chart, used to gauge whether a manufacturing process is under control. They are the thresholds marked on a control chart to which the plotted values of a sample statistic are compared.

The Upper Control Limit (UCL) and Lower Control Limit (LCL) are calculated using statistical methods to determine the variability inherent in the process. In our exercise, we calculated \(UCL = 0.2214 \) and set \(LCL = 0 \) because the initial calculation yielded a negative number, which is not feasible for a count of defects. This adjustment to zero means any sample having a higher defect rate than the UCL or lower than the LCL could signal an atypical event or fluctuation.

Control limits help to differentiate between common cause variations, inherent in any process, and special cause variations, which indicate a significant shift or error. By monitoring these limits, quality teams can determine if a process adjustment or investigation is needed, effectively maintaining the desired level of quality.
Statistical Process Control
Statistical Process Control (SPC) is a method of monitoring and controlling a process through statistical analysis. SPC aims to ensure that the process operates at its fullest potential while minimizing variability and preventing defects.

In SPC, control charts are essential tools that play a critical role. They help in identifying trends, shifts, or any unusual patterns, all of which could suggest a potential problem. By continuously monitoring the process performance, businesses can respond proactively to variations, thus avoiding errors and improving efficiency.

\(p\) charts, as seen in the problem, fall under the category of attribute control charts. They are specifically used to monitor the proportion of defective items in a process. This emphasis on defects or failures makes \(p\) charts especially valuable for manufacturing processes where outputs are pass/fail decisions, enabling timely identification and rectification of issues.
Manufacturing Quality Control
Manufacturing quality control is about ensuring that the manufactured product adheres to a defined set of quality criteria or meets the requirements of the customer. It involves various processes and techniques like SPC to monitor and improve quality.

In our exercise involving a \(p\) chart, quality control was focused on detecting inoperable electronic components. By sampling 15 times and recording the defect rates, quality controllers collected significant data to determine if the process remained under control while maintaining acceptable production variance.

Effective quality control means conducting regular checks, implementing control charts, and responding to variations swiftly. It ensures products consistently meet quality standards, which is vital in competitive markets where non-conformance can lead to wastage, increased costs, or customer dissatisfaction. Therefore, mastering tools like \(p\) charts is crucial in maintaining a robust manufacturing quality control system.
  • Continual process assessment
  • Defect and waste reduction
  • Customer satisfaction assurance

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Most popular questions from this chapter

The proportion of individuals with an Rh-positive blood type is \(85 \%\). You have a random sample of \(n=500\) individuals. a. What are the mean and standard deviation of \(\hat{p}\), the sample proportion with Rh-positive blood type? b. Is the distribution of \(\hat{p}\) approximately normal? Justify your answer. c. What is the probability that the sample proportion \(\hat{p}\) exceeds \(82 \% ?\) d. What is the probability that the sample proportion lies between \(83 \%\) and \(88 \% ?\) e. \(99 \%\) of the time, the sample proportion would lie between what two limits?

The battle for consumer preference continues between Pepsi and Coke. How can you make your preferences known? There is a web page where you can vote for one of these colas if you click on the link that says PAY CASH for your opinion. Explain why the respondents do not represent a random sample of the opinions of purchasers or drinkers of these drinks. Explain the types of distortions that could creep into an Internet opinion poll.

Random samples of size \(n=500\) were selected from a binomial population with \(p=.1\). a. Is it appropriate to use the normal distribution to approximate the sampling distribution of \(\hat{p} ?\) Check to make sure the necessary conditions are met. Using the results of part a, find these probabilities: b. \(\hat{p}>.12\) c. \(\hat{p}<.10\) d. \(\hat{p}\) lies within .02 of \(p\)

Samples of \(n=100\) items were selected hourly over a 100 -hour period, and the sample proportion of defectives was calculated each hour. The mean of the 100 sample proportions was .035 a. Use the data to find the upper and lower control limits for a \(p\) chart. b. Construct a \(p\) chart for the process and explain how it can be used.

A random sample of public opinion in a small town was obtained by selecting every 10th person who passed by the busiest corner in the downtown area. Will this sample have the characteristics of a random sample selected from the town's citizens? Explain.

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