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Find the following probabilities for the standard normal random variable \(z\): a. \(P(-1.431.34)\) e. \(P(z<-4.32)\)

Short Answer

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b. What is the probability of z being between 0.58 and 1.74? c. What is the probability of z being between -1.55 and -0.44? d. What is the probability of z being greater than 1.34? e. What is the probability of z being less than -4.32?

Step by step solution

01

Understand how to use the z-table

A z-table shows the probabilities/areas under the standard normal distribution curve corresponding to each z-score. To find the probability between two z-scores, we need to find the area between those two z-scores.
02

Find the probabilities for each part

a. \(P(-1.431.34)\): Look up the area corresponding to \(z = 1.34\). Since the table gives us the area to the left of the z-score, we need to find the area to the right (1 - the area to the left): \(P(z>1.34) = 1 - P(z<1.34)\) After looking up the values, we get: \(P(z>1.34) = 1 - 0.9099 = 0.0901\) e. \(P(z<-4.32)\): Look up the area corresponding to \(z = -4.32\). Since the z-table typically goes up to only \(z = -3.99\), the area corresponding to \(z<-4.32\) is very close to 0: \(P(z<-4.32) \approx 0\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Z-Table
One of the key tools in statistics for understanding the standard normal distribution is the z-table. This table is an invaluable resource for finding the probability that a standard normal variable falls within a specific range.

The z-table lists z-scores on one axis and the corresponding probability on the other. These probabilities represent the area under the standard normal curve to the left of the given z-score, effectively telling us the likelihood that a randomly chosen value from the distribution is less than or equal to that z-score.

How to Use the Z-Table

If we want to find the probability of a z-score falling between two values, we take the difference between the probabilities associated with each z-score. For instance, to find the probability that a z-score is greater than a particular value, we subtract the z-score's associated probability from 1. It's essential to remember that the z-table gives cumulative probabilities up to the z-score value.
Standard Normal Curve
The standard normal distribution, often symbolized as the bell curve due to its shape, is a probability distribution that has a mean of 0 and a standard deviation of 1. Since it's standardized, we can compare different data sets with various means and standard deviations on the same scale.

The curve represents the distribution of many natural phenomena and is foundational in statistics. The area under the curve corresponds to probabilities. In fact, the total area under the curve is equal to 1, which means with certainty, a standard normal variable falls somewhere under the curve.

Features of the Standard Normal Curve

It is symmetrical, with half the area to the left of the mean and half to the right. Its shape allows us to see that values closer to the mean are more probable than values far from the mean. This distribution is also important in inferential statistics where we use z-scores to determine probabilities and make predictions.
Z-Score
A z-score is a statistical measurement that describes a value's relationship to the mean of a group of values, measured in terms of standard deviations from the mean. It shows how many standard deviations an element is from the mean.

A z-score of 0 indicates that the data point's score is identical to the mean score. A z-score can also be positive or negative, indicating whether it's above or below the mean, respectively.

Calculating a Z-Score

To calculate a z-score, you subtract the mean from the data point and then divide the result by the standard deviation. This process effectively standardizes different data sets, allowing for easy comparison and understanding of where a particular value stands within its dataset and in relation to other datasets.
Probability Calculation
The process of probability calculation in the context of a standard normal distribution involves finding the likelihood that a random variable falls within a certain range. This is essential in many fields, including finance, social sciences, and risk management, to make informed decisions based on the likelihood of various outcomes.

To calculate this probability, one could use a z-table, integrate the normal distribution function, or use software designed for statistical analysis. An understanding of probability calculation allows for the interpretation of data and prediction of trends.

Working with Cumulative Probabilities

Since the z-table provides cumulative probabilities, determining the probability that a z-score falls between two values requires you to find the probability to the left of both z-scores and then subtract. This process is generally straightforward but can become challenging with extreme values. For instance, if a z-score does not appear on the table because it is excessively high or low, approximations may be used.

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Most popular questions from this chapter

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Suppose that you must establish regulations concerning the maximum number of people who can occupy an elevator. A study of elevator occupancies indicates that if eight people occupy the elevator, the probability distribution of the total weight of the eight people has a mean equal to 1200 pounds and a standard deviation of 99 pounds. What is the probability that the total weight of eight people exceeds 1300 pounds? 1500 pounds? (Assume that the probability distribution is approximately normal.)

A researcher notes that senior corporation executives are not very accurate forecasters of their own annual earnings. He states that his studies of a large number of company executive forecasts "showed that the average estimate missed the mark by \(15 \%\)." a. Suppose the distribution of these forecast errors has a mean of \(15 \%\) and a standard deviation of \(10 \%\). Is it likely that the distribution of forecast errors is approximately normal? b. Suppose the probability is .5 that a corporate executive's forecast error exceeds \(15 \% .\) If you were to sample the forecasts of 100 corporate executives, what is the probability that more than 60 would be in error by more than \(15 \% ?\)

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