/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 59 Under what conditions would you ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Under what conditions would you use the hypergeometric probability distribution to evaluate the probability of \(x\) successes in \(n\) trials?

Short Answer

Expert verified
Question: Explain the conditions and criteria that must be met in order to use the hypergeometric probability distribution to evaluate the probability of \(x\) successes in \(n\) trials from a finite population. Answer: To use the hypergeometric probability distribution, the following conditions must be met: a finite population of size \(N\) exists with \(M\) success objects and \(N-M\) failure objects; the number of trials (\(n\)) is fixed; trials are performed without replacement; and the probability of success and failure varies across trials. The criteria for evaluating the probability of \(x\) successes in \(n\) trials include: meeting the conditions for using the hypergeometric distribution; ensuring \(n \leq N\); ensuring \(0 \leq x \leq M\); and ensuring \(0 \leq n-x \leq N-M\).

Step by step solution

01

1. Understand hypergeometric distribution

The hypergeometric distribution is a discrete probability distribution that describes the probability of \(x\) successes in \(n\) trials, without replacement, from a finite population of size \(N\), where there are \(M\) success objects and \(N-M\) failure objects.
02

2. Conditions for using the hypergeometric distribution

To use the hypergeometric probability distribution, the following conditions must be met: a) A finite population of size \(N\) exists, containing \(M\) success objects and \(N-M\) failure objects. b) The number of trials (\(n\)) is fixed. c) Each trial is performed without replacement, meaning that once an object is selected, it is not put back into the population. d) The probability of success and failure is not constant across trials, as they depend on the remaining population after each trial.
03

3. Criteria for evaluating the probability of \(x\) successes in \(n\) trials

To evaluate the probability of \(x\) successes in \(n\) trials using the hypergeometric probability distribution, the following criteria must be fulfilled: a) The conditions for using the hypergeometric distribution are met (explained in step 2). b) \(n \leq N\) (the number of trials cannot be greater than the population size). c) \(0 \leq x \leq M\) (the number of successes cannot be negative or greater than the number of success objects in the population). d) \(0 \leq n-x \leq N-M\) (the number of failures cannot be negative or greater than the number of failure objects in the population). Once these conditions and criteria are met, the hypergeometric probability distribution can be used to evaluate the probability of \(x\) successes in \(n\) trials from a population with \(M\) success objects and \(N-M\) failure objects.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

5.74 Plant Density One model for plant competition assumes that there is a zone of resource depletion around each plant seedling. Depending on the size of the zones and the density of the plants, the zones of resource depletion may overlap with those of other seedlings in the vicinity. When the seeds are randomly dispersed over a wide area, the number of neighbors that a seedling may have usually follows a Poisson distribution with a mean equal to the density of seedlings per unit area. Suppose that the density of seedlings is four per square meter \(\left(\mathrm{m}^{2}\right)\). a. What is the probability that a given seedling has no neighbors within \(1 \mathrm{~m}^{2}\) ? b. What is the probability that a seedling has at most three neighbors per \(\mathrm{m}^{2}\) ? c. What is the probability that a seedling has five or more neighbors per \(\mathrm{m}^{2}\) ? d. Use the fact that the mean and variance of a Poisson random variable are equal to find the proportion of neighbors that would fall into the interval \(\mu \pm 2 \sigma .\) Comment on this result.

A candy dish contains five blue and three red candies. A child reaches up and selects three candies without looking. a. What is the probability that there are two blue and one red candies in the selection? b. What is the probability that the candies are all red? c. What is the probability that the candies are all blue?

How do you survive when there's no time to eat-fast food, no food, a protein bar, candy? A Snapshot in USA Today indicates that \(36 \%\) of women aged \(25-55\) say that, when they are too busy to eat, they get fast food from a drive-thru. \({ }^{14} \mathrm{~A}\) random sample of 100 women aged \(25-55\) is selected. a. What is the average number of women who say they eat fast food when they're too busy to eat? b. What is the standard deviation for the number of women who say they eat fast food when they're too busy to eat? c. If 49 of the women in the sample said they eat fast food when they're too busy to eat, would this be an unusual occurrence? Explain.

Use the applet to find the following: a. \(P(x<6)\) for \(n=22, p=.65\) b. \(P(x=8)\) for \(n=12, p=.4\) c. \(P(x>14)\) for \(n=20, p=.5\) d. \(P(2

\(\mathbf{5 . 9 8}\) Engine Failure Suppose the four engines of a commercial aircraft are arranged to operate independently and that the probability of in- flight failure of a single engine is .01. What is the probability of the following events on a given flight? a. No failures are observed. b. No more than one failure is observed.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.