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A piece of electronic equipment contains six computer chips, two of which are defective. Three chips are selected at random, removed from the piece of equipment, and inspected. Let \(x\) equal the number of defectives observed, where \(x=0,1,\) or 2 . Find the probability distribution for \(x\). Express the results graphically as a probability histogram.

Short Answer

Expert verified
Answer: The probabilities of observing 0, 1, and 2 defective chips are 1/5, 3/5, and 1/5, respectively.

Step by step solution

01

Define the sample space and events

There are 6 computer chips, 2 of which are defective. We are selecting 3 chips at random (without replacement) and let x be the number of defective chips observed. Therefore, the sample space can be represented as {(N,N,N),(N,N,D),(N,D,N),(D,N,N),(N,D,D),(D,N,D),(D,D,N),(D,D,D)} where N represents a non-defective chip and D represents a defective one. The events for the random variable x are: 0 defective chips (x = 0), 1 defective chip (x = 1), and 2 defective chips (x = 2).
02

Calculate combinations and probabilities

We will use the combination formula to calculate the number of ways we can select the chips for each event: Total number of chips = 6 Number of non-defective chips = 4 (6 - 2) Number of defective chips = 2 Event 1 (x=0): 0 defective chips Combinations for non-defective chips: C(4,3) = \frac{4!}{3!(4-3)!} = 4 Combinations for defective chips: C(2,0) = \frac{2!}{0!(2-0)!} = 1 Number of combinations for x=0: 4 * 1 = 4 Event 2 (x=1): 1 defective chip Combinations for non-defective chips: C(4,2) = \frac{4!}{2!(4-2)!} = 6 Combinations for defective chips: C(2,1) = \frac{2!}{1!(2-1)!} = 2 Number of combinations for x=1: 6 * 2 = 12 Event 3 (x=2): 2 defective chips Combinations for non-defective chips: C(4,1) = \frac{4!}{1!(4-1)!} = 4 Combinations for defective chips: C(2,2) = \frac{2!}{2!(2-2)!} = 1 Number of combinations for x=2: 4 * 1 = 4 Now, we calculate the probabilities for each event using the total number of combinations: Total combinations: C(6,3) = \frac{6!}{3!(6-3)!} = 20 P(x=0) = 4/20 = 1/5 P(x=1) = 12/20 = 3/5 P(x=2) = 4/20 = 1/5
03

Represent the probabilities graphically

To represent the probabilities graphically as a probability histogram, create a histogram with the number of defective chips (x-values) on the horizontal axis and the probabilities (P(x)) on the vertical axis. Plot the bars as follows: For x=0 (1 defective chip): height of the bar = 1/5 For x=1 (2 defective chips): height of the bar = 3/5 For x=2 (3 defective chips): height of the bar = 1/5 The probability histogram should show three bars representing the probabilities of observing 0, 1, and 2 defective chips. The heights of the bars should correspond to the calculated probabilities, i.e., 1/5, 3/5, and 1/5.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Combinatorics Fundamentals
Combinatorics is a field of mathematics that deals with the counting, arrangement, and combination of objects. It lays the foundation for calculating probabilities in complex scenarios. When faced with a problem that involves selecting items from a group, such as computer chips from a piece of equipment, combinatorics provides tools like the combination formula, denoted as C(n, k), which calculates the number of ways k items can be chosen from a set of n distinct items. This is essential for solving probability problems because it helps us count the possible outcomes without having to list them all exhaustively.

In our exercise, the combination formula C(n, k) = \(\frac{n!}{k!(n-k)!}\) is used to determine the number of non-defective and defective chip selections possible. The factorial symbol '!' represents the product of all positive integers up to that number, which is a crucial element in combinatorial calculations. Combinatorics is not just about finding single numbers; it’s often about understanding the structure and distribution of all possible outcomes, which is critical for finding probabilities.
Understanding Probability Histograms
A probability histogram is a type of graph that represents the distribution of a discrete random variable's probabilities. Unlike continuous distributions, discrete distributions have distinct or separate values. This graph is composed of bars, where each bar's height corresponds to the probability of a particular outcome. To construct a probability histogram, we plot the outcomes of the random variable on the horizontal axis, and the probabilities of these outcomes on the vertical axis.

In the provided exercise, we have a discrete random variable that counts the number of defective chips. After calculating the probabilities for each possible outcome (0, 1, or 2 defective chips), a probability histogram is used to visually display the likelihood of each scenario. This graphical representation makes it easier to understand the distribution of probabilities and is a powerful tool for quickly assessing the chances of different outcomes. A well-constructed histogram can provide insight into the most likely events and the variability or stability of the results.
The Binomial Distribution Revealed
The binomial distribution is a discrete probability distribution that arises in experiments with two possible outcomes, often labeled as 'success' and 'failure'. It is defined by two parameters: the number of trials (n) and the probability of success (p) in each trial. A core principle of the binomial distribution is independence, meaning the outcome of one trial does not affect another. Moreover, each trial has the same probability of success.

In our scenario, if we denote a defective chip as a 'success', the exercise aligns with the conditions of a binomial distribution – however, it's essential to note that the trials are without replacement, which technically means our example isn't a true binomial scenario since the probability changes with each draw. Regardless, the binomial distribution is still a relevant concept, as it provides an approximation that can be quite useful. The formulas for the probabilities in a binomial distribution are P(x) = C(n, x) * p^x * (1-p)^(n-x), where P(x) is the probability of x successes in n trials. Understanding this concept is crucial in many fields, including quality control, research analysis, and predictive modeling.

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Most popular questions from this chapter

"Whistle blowers" is the name given to employees who report corporate fraud, theft, or other unethical and perhaps criminal activities by fellow employees or by their employer. Although there is legal protection for whistle blowers, it has been reported that approximately \(23 \%\) of those who reported fraud suffered reprisals such as demotion or poor performance ratings. Suppose the probability that an employee will fail to report a case of fraud is .69. Find the probability that a worker who observes a case of fraud will report it and will subsequently suffer some form of reprisal.

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