/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 38 The International Baccalaureate ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

The International Baccalaureate (IB) program is an accelerated academic program offered at a growing number of high schools throughout the country. Students enrolled in this program are placed in accelerated or advanced courses and must take IB examinations in each of six subject areas at the end of their junior or senior year. Students are scored on a scale of \(1-7,\) with \(1-2\) being poor, 3 mediocre, 4 average, and \(5-7\) excellent. During its first year of operation at John \(\mathrm{W}\). North High School in Riverside, California, 17 juniors attempted the IB economics exam, with these results: $$ \begin{array}{cc} \text { Exam Grade } & \text { Number of Students } \\ \hline 7 & 1 \\ 6 & 4 \\ 5 & 4 \\ 4 & 4 \\ 3 & 4 \end{array} $$ Calculate the mean and standard deviation for these scores.

Short Answer

Expert verified
Answer: The mean is approximately 4.647, and the standard deviation is approximately 1.217.

Step by step solution

01

Calculate the total sum of the scores and the number of students.

We can use the given table to calculate the total sum of the scores and the number of students. Note that we have 17 students in total. Total sum of scores = (7*1)+(6*4)+(5*4)+(4*4)+(3*4) = 7+24+20+16+12 = 79 Total number of students = 1 + 4 + 4 + 4 + 4 = 17
02

Calculate the mean

To find the mean, we divide the total sum of the scores by the total number of students: Mean = Total sum of scores / Total number of students Mean = 79 / 17 = 4.647
03

Calculate the differences between scores and the mean

Now, we need to find the difference between each student's score and the mean. We'll use the table to calculate the sum of squared differences. Sum of squared differences = (7-4.647)^2 * 1 + (6-4.647)^2 * 4 + (5-4.647)^2 * 4 + (4-4.647)^2 * 4 + (3-4.647)^2 * 4 = 5.499 + 7.233 + 0.499 + 1.767 + 10.183 = 25.181
04

Calculate the average of the squared differences

Divide the sum of squared differences by the total number of students to find the average: Average of squared differences = Sum of squared differences / Total number of students Average of squared differences = 25.181 / 17 = 1.481
05

Calculate the standard deviation

Finally, take the square root of the average of squared differences to find the standard deviation: Standard deviation = √(Average of squared differences) Standard deviation = √(1.481) ≈ 1.217 Hence, the mean and standard deviation for these scores are approximately 4.647 and 1.217, respectively.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mean Calculation
The mean, often referred to as the average, is a measure that represents the central or typical value in a set of data. In the context of the IB economics exam scores at John W. North High School, the mean is computed by adding up all of the exam scores and then dividing by the number of students who took the exam.

To ensure clarity in calculating the mean, let's consider an everyday scenario: imagine you and four friends have some apples. You have 2 apples, and each friend has 3, 5, 7, and 4 apples respectively. To find out the average number of apples each person has, you'd add up all the apples: 2 + 3 + 5 + 7 + 4 = 21 apples. Then divide by the number of people, which is 5. So, on average, each person has 21 divided by 5, which is 4.2 apples.

Now, applying this principle to the IB economics exam statistics, we sum the products of each exam grade and the corresponding number of students who scored that grade. Finally, we divide this total by the overall number of students. This calculation provides the mean score of the group, giving us an insight into the overall performance level of the students on the exam.
Standard Deviation Calculation
Standard deviation is a statistic that measures the dispersion or spread of a set of data points relative to its mean. A lower standard deviation indicates that the scores are close to the mean, whereas a higher standard deviation signifies that the scores are spread out over a larger range of values.

Imagine if a friend of yours is throwing darts. If they're a good player, most of their darts will cluster tightly around the bullseye; this tight cluster has a low standard deviation. However, if their darts are scattered all around the dartboard, they would have a high standard deviation. In the context of exam scores, a lower standard deviation would mean that most students scored similarly, while a higher standard deviation would indicate varied performance.

To calculate standard deviation, we start by finding the mean, then for each score, we calculate the difference between that score and the mean and square the result (to eliminate negative values). Multiplying these squared differences by the number of students who scored each grade, we get a total that we then divide by the number of students to find the average squared difference. The square root of this average gives us the standard deviation, representing how much the students' scores deviate, on average, from the mean score.
Probability and Statistics
Probability and statistics are branches of mathematics that deal with data collection, analysis, interpretation, and presentation. Probability is about measuring the likelihood of various outcomes, while statistics involves summarizing and making sense of collected data.

In the realm of education, especially in courses like the IB economics exam, understanding these concepts is crucial for interpreting test results. For instance, with the provided exam scores, we can calculate the probability of a student achieving a certain grade based on past performances. If 4 out of 17 students scored a 6, we can say the probability of a student scoring a 6 is roughly 23.5%.

Moreover, statistics such as the mean and standard deviation give us a quantitative insight into the performance variability among students. This can be particularly helpful for educators looking to improve their teaching strategies or identify topics where students may need additional support. Always remember that the goal is not just to compute these values but to understand what they say about the student's learning and the effectiveness of instruction.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The number of raisins in each of 14 miniboxes (1/2-ounce size) was counted for a generic brand and for Sunmaid brand raisins. The two data sets are shown here: $$ \begin{array}{llll|llll} &&&{\text { Generic Brand }} &&&& \ {\text { Sunmaid }} \\ \hline 25 & 26 & 25 & 28 & 25 & 29 & 24 & 24 \\ 26 & 28 & 28 & 27 & 28 & 24 & 28 & 22 \\ 26 & 27 & 24 & 25 & 25 & 28 & 30 & 27 \\ 26 & 26 & & & 28 & 24 & & \end{array} $$ a. What are the mean and standard deviation for the generic brand? b. What are the mean and standard deviation for the Sunmaid brand? c. Compare the centers and variabilities of the two brands using the results of parts a and b.

A company interested in lumbering rights for a certain tract of slash pine trees is told that the mean diameter of these trees is 14 inches with a standard deviation of 2.8 inches. Assume the distribution of diameters is roughly mound-shaped. a. What fraction of the trees will have diameters between 8.4 and 22.4 inches? b. What fraction of the trees will have diameters greater than 16.8 inches?

The mean duration of television commercials on a given network is 75 seconds, with a standard deviation of 20 seconds. Assume that durations are approximately normally distributed. a. What is the approximate probability that a commercial will last less than 35 seconds? b. What is the approximate probability that a commercial will last longer than 55 seconds?

Environmental scientists are increasingly concerned with the accumulation of toxic elements in marine mammals and the transfer of such elements to the animals' offspring. The striped dolphin (Stenella coeruleoalba), considered to be the top predator in the marine food chain, was the subject of one such study. The mercury concentrations (micrograms/gram) in the livers of 28 male striped dolphins were as follows: \begin{array}{rrrr} 1.70 & 183.00 & 221.00 & 286.00 \\ 1.72 & 168.00 & 406.00 & 315.00 \\ 8.80 & 218.00 & 252.00 & 241.00 \\ 5.90 & 180.00 & 329.00 & 397.00 \\ 101.00 & 264.00 & 316.00 & 209.00 \\ 85.40 & 481.00 & 445.00 & 314.00 \\ 118.00 & 485.00 & 278.00 & 318.00 \end{array} a. Calculate the five-number summary for the data. b. Construct a box plot for the data. c. Are there any outliers? d. If you knew that the first four dolphins were all less than 3 years old, while all the others were more than 8 years old, would this information help explain the difference in the magnitude of those four observations? Explain.

A strain of longstemmed roses has an approximate normal distribution with a mean stem length of 15 inches and standard deviation of 2.5 inches. a. If one accepts as "long-stemmed roses" only those roses with a stem length greater than 12.5 inches, what percentage of such roses would be unacceptable? b. What percentage of these roses would have a stem length between 12.5 and 20 inches?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.