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An agricultural experimenter, investigating the effect of the amount of nitrogen \(x\) applied in 100 pounds per acre on the yield of oats \(y\) measured in bushels per acre, collected the following data: $$ \begin{array}{l|llll} x & 1 & 2 & 3 & 4 \\ \hline y & 22 & 38 & 57 & 68 \\ & 19 & 41 & 54 & 65 \end{array} $$ a. Find the least-squares line for the data. b. Construct the ANOVA table. c. Is there sufficient evidence to indicate that the yield of oats is linearly related to the amount of nitrogen applied? Use \(\alpha=.05 .\) d. Predict the expected yield of oats with \(95 \%\) confidence if 250 pounds of nitrogen per acre are applied.e. Estimate the average increase in yield for an increase of 100 pounds of nitrogen per acre with \(99 \%\) confidence. f. Calculate \(r^{2}\) and explain its significance in terms of predicting \(y\), the yield of oats.

Short Answer

Expert verified
Question: Determine the least-squares line equation, perform an F-test to test the linear relationship between the yield of oats and the amount of nitrogen applied, and estimate the expected yield when 250 pounds of nitrogen per acre are applied with a 95% confidence interval.

Step by step solution

01

Computing the Mean of each Variable

Compute the mean of the amount of nitrogen applied (\(\bar{x}\)) and the mean of the yield of oats (\(\bar{y}\)): $$ \bar{x} = \frac{1 + 2 + 3 + 4}{4} = \frac{10}{4} = 2.5 $$ $$ \bar{y} = \frac{22 + 19 + 38 + 41 + 57 + 54 + 68 + 65}{8} = \frac{364}{8} = 45.5 $$
02

Calculating elements to find the Least-Squares Line coefficients

Compute the necessary components to calculate the coefficients \(a\) and \(b\) for the equation of the least-squares line, \(y = a + bx\). $$ \sum x_i = 10, \quad \sum y_i = 364, \quad \sum x_{i}y_{i} = 841, \quad \sum x_{i}^{2} = 30, $$ Where \(N=8\), since 8 data points are given.
03

Finding the coefficients a and b

Use the above calculated elements to find the coefficients. $$ a = \frac{\sum y_i - b \sum x_i}{N} = \frac{\sum y_i - b \sum x_i}{8} $$ $$ b = \frac{N \sum x_i y_i - \sum x_i \sum y_i }{N \sum x_i^2 - (\sum x_i)^2} $$ Solve for \(b\): $$ b = \frac{8 \times 841 - 10 \times 364}{8 \times 30 - 10^2} = \frac{2304}{40} = 57.6 $$ Now use the value of \(b\) to solve for \(a\): $$ a = \frac{364 - 57.6 \times 10}{8} = \frac{-142.4}{8} = -17.8 $$ So, the least-squares line equation is: $$ y = -17.8 + 57.6 x $$
04

Constructing the ANOVA table

To compute the ANOVA table elements, we need the following terms: - Total Sum of Squares (TSS) = \(\sum (y_i - \bar{y})^2\) - Regressional Sum of Squares (RSS) = \(\sum (\hat{y}_i - \bar{y})^2\) - Residual Sum of Squares (ResidSS) = \(\sum (y_i - \hat{y}_i)^2\) Here \(\hat{y}_i\) is the predicted value of \(y\) for a given \(x\) value using the least-squares line equation. The ANOVA table is then constructed with 3 columns: 'Source', 'Degree of Freedom (DF)', 'Sum of Squares' and 'Mean of Sum of Squares'. - Source column: Regression, Residual, Total - Degree of Freedom: 1 (Regression), 6 (Residual), 7 (Total) - Sum of Squares: TSS, RSS, ResidlSS To determine whether there's a sufficient linear relationship, we'll perform an F-test using the F-distribution and the \(\alpha =0.05\) significance level.
05

Predicting the expected yield of oats with 95% confidence

Estimate the expected yield of oats when 250 pounds of nitrogen per acre are applied, using the least-squares line equation. Calculate the confidence interval using the t-distribution and the standard error of prediction.
06

Estimating the average increase in yield for an increase of 100 pounds of nitrogen per acre with 99% confidence

Calculate the increase in expected yield when the nitrogen amount is increased by 100 pounds per acre. Calculate the confidence interval using the t-distribution and the standard error of the slope.
07

Calculating \(r^2\) and explaining its significance

Calculate the coefficient of determination, \(r^2\), which indicates the proportion of the variability in 'y' (oat yield) that can be explained by the linear relationship between 'x' (nitrogen application) and 'y'. This value is calculated using the following formula: $$ r^2 = \frac{RSS}{TSS} = 1 - \frac{ResidSS}{TSS} $$

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

ANOVA table
The ANOVA (Analysis of Variance) table is a crucial component in regression analysis. It helps to analyze the differences between group means and their associated procedures. Here's how we typically set it up for a regression analysis:
  • Regression: This part measures the part of the total variability in the data explained by the regression line, the model we are testing.
  • Residual: This refers to the variability in the data that the model does not explain. It's also known as "error" variability.
  • Total: This is the sum of all variability in the data, including both explained and unexplained parts.
The ANOVA table uses these components to compute several key values, such as the regression sum of squares (SSR), the residual sum of squares (SSE), and the total sum of squares (SST). Another important outcome is the F-statistic, which tests if the group means are significantly different. If the F-statistic is larger than a critical value from the F-distribution, there's evidence that the independent variable has a significant impact on the dependent variable.
Least-Squares Line
The least-squares line is fundamental in regression analysis. It represents the line that best fits a set of data points by minimizing the sum of the squares of the vertical deviations between the observed values and those predicted by the line. The equation of the least-squares line is generally expressed as \( y = a + bx \), where:
  • \( a \) is the y-intercept, meaning where the line crosses the y-axis.
  • \( b \) is the slope of the line, indicating the average change in the dependent variable for each unit change in the independent variable.
To find the least-squares line, we calculate the slope \( b \) using:\[b = \frac{N \sum x_i y_i - \sum x_i \sum y_i }{N \sum x_i^2 - (\sum x_i)^2}\]Next, the y-intercept \( a \) is determined by:\[a = \frac{\sum y_i - b \sum x_i}{N}\]This line helps in predicting the expected value of the dependent variable for a given value of the independent variable. By minimizing errors between the observed values and the straight line, it provides the best estimate of the relationship between variables.
Coefficient of Determination (r²)
In regression analysis, the coefficient of determination, denoted as \( r^2 \), is a key statistic. It describes the proportion of the variance in the dependent variable that is predictable from the independent variable(s). Essentially, \( r^2 \) tells us how much of the data's variability is explained by our model.
  • If \( r^2 = 1 \), it means the regression predictions perfectly fit the data, accounting for all variability.
  • If \( r^2 = 0 \), the model explains none of the data variability around its mean.
We calculate it by dividing the regression sum of squares (SSR) by the total sum of squares (SST), or equivalently:\[r^2 = 1 - \frac{SSE}{SST}\]This value is significant because a higher \( r^2 \) implies a better fit of the model to the data. In the context of this exercise, it would indicate how well the amount of nitrogen explains changes in the yield of oats.
Confidence Interval
The confidence interval in regression analysis provides a range of values that likely contain the true value of an unknown population parameter. For example, we might estimate the future yield of oats based on past data. The confidence interval would give us an idea of how much error is associated with this prediction. When constructing a confidence interval, we first estimate the parameter (like the mean yield or the slope in the regression model) and then place intervals around it using the error variance and the critical value from a t-distribution. It typically takes the form:\[\text{Estimate} \pm (\text{Critical Value}) \times (\text{Standard Error})\]The wider the interval, the more uncertainty there is about the estimate. At a 95% confidence level, which is common, we expect that the interval will capture the true parameter in 95% of similar samples. This is key in making predictions, such as estimating the expected yield with a specific amount of nitrogen.

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Most popular questions from this chapter

A marketing research experiment was conducted to study the relationship between the length of time necessary for a buyer to reach a decision and the number of alternative package designs of a product presented. Brand names were eliminated from the packages to reduce the effects of brand preferences. The buyers made their selections using the manufacturer's product descriptions on the packages as the only buying guide. The length of time necessary to reach a decision was recorded for 15 participants in the marketing research study. $$ \begin{array}{l|l|l|l} \begin{array}{l} \text { Length of Decision } \\ \text { Time, } y(\mathrm{sec}) \end{array} & 5,8,8,7,9 & 7,9,8,9,10 & 10,11,10,12,9 \\ \hline \text { Number of } & & & \\ \text { Alternatives, } x & 2 & 3 & 4 \end{array} $$ a. Find the least-squares line appropriate for these data. b. Plot the points and graph the line as a check on your calculations. c. Calculate \(s^{2}\). d. Do the data present sufficient evidence to indicate that the length of decision time is linearly related to the number of alternative package designs? (Test at the \(\alpha=.05\) level of significance.) e. Find the approximate \(p\) -value for the test and interpret its value. f. If they are available, examine the diagnostic plots to check the validity of the regression assumptions. g. Estimate the average length of time necessary to reach a decision when three alternatives are presented, using a \(95 \%\) confidence interval.

Six points have these coordinates: $$ \begin{array}{l|llllll} x & 1 & 2 & 3 & 4 & 5 & 6 \\ \hline y & 5.6 & 4.6 & 4.5 & 3.7 & 3.2 & 2.7 \end{array} $$ a. Find the least-squares line for the data. b. Plot the six points and graph the line. Does the line appear to provide a good fit to the data points? c. Use the least-squares line to predict the value of \(y\) when \(x=3.5\) d. Fill in the missing entries in the MINITAB analysis of variance table. (Table)

An experiment was conducted to investigate the effect of a training program on the length of time for a typical male college student to complete the 100 -yard dash. Nine students were placed in the program. The reduction \(y\) in time to complete the 100 -yard dash was measured for three students at the end of 2 weeks, for three at the end of 4 weeks, and for three at the end of 6 weeks of training. The data are given in the table. $$ \begin{array}{l|l|l|l} \text { Reduction in Time, } y(\mathrm{sec}) & 1.6, .8,1.0 & 2.1,1.6,2.5 & 3.8,2.7,3.1 \\ \hline \text { Length of Training, } x(\mathrm{wk}) & 2 & 4 & 6 \end{array} $$ Use an appropriate computer software package to analyze these data. State any conclusions you can draw.

How is the cost of a plane flight related to the length of the trip? The table shows the average round-trip coach airfare paid by customers of American Airlines on each of 18 heavily traveled U.S. air routes. $$ \begin{array}{lrr} & \text { Distance } & \\ \text { Route } & \text { (miles) } & \text { Cost } \\ \hline \text { Dallas-Austin } & 178 & \$ 125 \\ \text { Houston-Dallas } & 232 & 123 \\ \text { Chicago-Detroit } & 238 & 148 \\ \text { Chicago-St. Louis } & 262 & 136 \\ \text { Chicago-Cleveland } & 301 & 129 \\ \text { Chicago-Atlanta } & 593 & 162 \\ \text { New York-Miami } & 1092 & 224 \\ \text { New York-San Juan } & 1608 & 264 \\ \text { New York-Chicago } & 714 & 287 \\ \text { Chicago-Denver } & 901 & 256 \\ \text { Dallas-Salt Lake } & 1005 & 365 \\ \text { New York-Dallas } & 1374 & 459 \\ \text { Chicago-Seattle } & 1736 & 424 \\ \text { Los Angeles-Chicago } & 1757 & 361 \\ \text { Los Angeles-Atlanta } & 1946 & 309 \\ \text { New York-Los Angeles } & 2463 & 444 \\ \text { Los Angeles-Honolulu } & 2556 & 323 \\ \text { New York-San Francisco } & 2574 & 513 \end{array} $$ a. If you want to estimate the cost of a flight based on the distance traveled, which variable is the response variable and which is the independent predictor variable? b. Assume that there is a linear relationship between cost and distance. Calculate the least-squares regression line describing cost as a linear function of distance. c. Plot the data points and the regression line. Does it appear that the line fits the data? d. Use the appropriate statistical tests and measures to explain the usefulness of the regression model for predicting cost.

Does a team's batting average depend in any way on the number of home runs hit by the team? The data in the table show the number of team home runs and the overall team batting average for eight selected major league teams for the 2006 season. \(^{14}\) $$ \begin{array}{lcc} \text { Team } & \text { Total Home Runs } & \text { Team Batting Average } \\\ \hline \text { Atlanta Braves } & 222 & .270 \\ \text { Baltimore Orioles } & 164 & .227 \\ \text { Boston Red Sox } & 192 & .269 \\ \text { Chicago White Sox } & 236 & .280 \\ \text { Houston Astros } & 174 & .255 \\ \text { Philadelphia Phillies } & 216 & .267 \\ \text { New York Giants } & 163 & .259 \\ \text { Seattle Mariners } & 172 & .272 \end{array} $$ a. Plot the points using a scatterplot. Does it appear that there is any relationship between total home runs and team batting average? b. Is there a significant positive correlation between total home runs and team batting average? Test at the \(5 \%\) level of significance. c. Do you think that the relationship between these two variables would be different if we had looked at the entire set of major league franchises?

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