/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 33 The data that follow are observa... [FREE SOLUTION] | 91Ó°ÊÓ

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The data that follow are observations collected from an experiment that compared four treatments, \(\mathrm{A}, \mathrm{B}, \mathrm{C},\) and \(\mathrm{D},\) within each of three blocks, using a randomized block design. $$ \begin{array}{lrrrrrr} &&&{\text { Treatment }} \\ \hline \text { Block } & \text { A } & \text { B } & \text { C } & \text { D } & \text { Total } \\ \hline 1 & 6 & 10 & 8 & 9 & 33 \\ 2 & 4 & 9 & 5 & 7 & 25 \\ 3 & 12 & 15 & 14 & 14 & 55 \\ \hline \text { Total } & 22 & 34 & 27 & 30 & 113 \end{array} $$ a. Do the data present sufficient evidence to indicate differences among the treatment means? Test using $$ \alpha=.05 . $$ b. Do the data present sufficient evidence to indicate differences among the block means? Test using \(\alpha=.05 .\) c. Rank the four treatment means using Tukey's method of paired comparisons with \(\alpha=.01\) d. Find a \(95 \%\) confidence interval for the difference in means for treatments \(\mathrm{A}\) and \(\mathrm{B}\). e. Does it appear that the use of a randomized block design for this experiment was justified? Explain.

Short Answer

Expert verified
Answer: The answer to this question cannot be determined without the specific data from the experiment. The ANOVA tests for treatments (step 5) would provide the p-value needed to determine if there are significant differences among treatment means. Similarly, the ANOVA tests for blocks would provide the p-value needed to determine if there are significant differences among the block means.

Step by step solution

01

Calculate row and column means

Compute the means for each row (block) and column (treatment) by dividing their respective totals by the number of elements in the row or column. For rows, Block 1: \(\frac{33}{4} = 8.25\) Block 2: \(\frac{25}{4} = 6.25\) Block 3: \(\frac{55}{4} = 13.75\) For columns, Treatment A: \(\frac{22}{3} = 7.33\) Treatment B: \(\frac{34}{3} = 11.33\) Treatment C: \(\frac{27}{3} = 9\) Treatment D: \(\frac{30}{3} = 10\)
02

Calculate the grand mean

Calculate the overall mean of the observations by dividing the total sum by the total number of elements: Grand mean: \(\frac{113}{12} = 9.42\)
03

Calculate the Sum of Squares Total (SST), Treatment (SSTreat), and Block (SSBlock)

Calculate the Sum of Squares Total (SST) by subtracting the grand mean from each observation, squaring the result, and adding up the squared differences. To calculate the Sum of Squares Treatment (SSTreat), multiply the squared difference between each treatment mean and the grand mean by the number of blocks, and add up these products. Similarly, to calculate the Sum of Squares Block (SSBlock), multiply the squared difference between each block mean and the grand mean by the number of treatments, and add up these products.
04

Calculate the Sum of Squares Error (SSE)

Calculate the Sum of Squares Error (SSE) by subtracting the sum of the SSTreat and SSBlock from the SST: SSE = SST - SSTreat - SSBlock
05

Conduct ANOVA tests for treatments and blocks

Use the calculated SSTreat, SSBlock, and SSE to perform ANOVA tests with a significance level of 0.05 for both treatments and blocks. If the p-value is less than 0.05 for treatments, then the data presents sufficient evidence to indicate differences among the treatment means. If the p-value is less than 0.05 for blocks, then the data presents sufficient evidence to indicate differences among the block means.
06

Rank the treatment means using Tukey's method

Compare the treatment means using Tukey's method of pairwise comparisons with a significance level of 0.01.
07

Calculate the 95% confidence interval for the difference in means for treatments A and B

Compute the confidence interval for the difference in means for treatments A and B using the calculated means, standard deviations, and number of samples in each treatment group.
08

Assess the use of a randomized block design

Evaluate if the use of a randomized block design for this experiment was justified by considering the results from the ANOVA tests conducted for treatments and blocks, as well as any patterns observed in the data.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

ANOVA
Analysis of variance (ANOVA) is a statistical procedure used to compare means of different groups to determine if at least one of the means is significantly different from the others. In the context of the exercise, ANOVA helps identify whether the treatments A, B, C, and D have significantly different effects.

The ANOVA test examines the variance within each group (due to random error) and the variance between the groups (due to the treatments). If the between-group variance is significantly larger than the within-group variance, we can conclude that at least one treatment mean is different. We calculate various sums of squares (SS) to determine these variances and use them to compute the F-statistic, which is then compared against a critical value from the F-distribution to assess significance.
Tukey's method
Tukey's method, also known as the Tukey's Honestly Significant Difference (HSD) test, is used to perform multiple pairwise comparisons between group means after an ANOVA. It's a post-hoc analysis to determine exactly which means are different. In the given exercise, we apply Tukey's method to rank the four treatment means.

This method controls for the type I error rate and is particularly useful when the number of comparisons is relatively large. The HSD uses a critical value to calculate a range for differences that are considered significant. If the absolute difference between any two group means is greater than the Tukey critical value, these means are significantly different.
Confidence interval
A confidence interval is a range of values that is likely to contain a population parameter, such as a mean difference, with a certain level of confidence. It offers an estimated range of values which is supposed to contain the parameter of interest with a stated probability, like 95%.

In our exercise, we are asked to find a 95% confidence interval for the difference between the means of treatments A and B. This interval will give us a range in which the true mean difference between these treatments lies, with 95% certainty. The wider the interval, the less precise is our estimate, which is influenced by the variability of the data and the size of the sample.
Sum of squares
Sum of squares (SS) is a statistical tool used to measure the variance or deviation within a data set. In an ANOVA, we calculate different types of SS to evaluate the variation due to specific factors and the variation occurring by chance.

In the exercise, we calculate the sum of squares total (SST), which quantifies the overall variation in the dataset, sum of squares treatment (SSTreat), which assesses the variation due to the differences in treatment means, and the sum of squares block (SSBlock), which gauges the variation between blocks. Subtracting SSTreat and SSBlock from SST gives us the sum of squares error (SSE), representing the variation not explained by the treatments or blocks.
Experimental design
Experimental design refers to how a statistical experiment is set up to test a hypothesis. The randomized block design used in the provided exercise is a method that groups similar experimental units into blocks and then randomly assigns treatments within each block. This design controls for block-to-block variability.

Using a randomized block design increases the precision of the experiment by reducing the influence of confounding variables. That way, it becomes easier to detect the difference among treatments. At the end of the experiment, as we look at the results from the ANOVA, we can assess whether the block design was an effective choice for the current study.

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Most popular questions from this chapter

Refer to Exercise \(11.46 .\) The means of two of the factor-level combinations- say, \(\mathrm{A}_{1} \mathrm{~B}_{1}\) and \(\mathrm{A}_{2} \mathrm{~B}_{1}-\) are \(\bar{x}_{1}=8.3\) and \(\bar{x}_{2}=6.3,\) respectively. Find a \(95 \%\) confidence interval for the difference between the two corresponding population means.

The partially completed ANOVA table for a randomized block design is presented here: $$ \begin{array}{lcl} \text { Source } & d f & \text { SS } & \text { MS } \quad F \\ \hline \text { Treatments } & 4 & 14.2 & \\ \text { Blocks } & & 18.9 & \\ \text { Error } & 24 & & \\ \hline \text { Total } & 34 & 41.9 & \end{array} $$ a. How many blocks are involved in the design? b. How many observations are in each treatment total? c. How many observations are in each block total? d. Fill in the blanks in the ANOVA table. e. Do the data present sufficient evidence to indicate differences among the treatment means? Test using \(\alpha=.05\) f. Do the data present sufficient evidence to indicate differences among the block means? Test using \(\alpha=.05\)

A nationa home builder wants to compare the prices per 1,000 board feet of standard or better grade Douglas fir framing lumber. He randomly selects five suppliers in each of the four states where the builder is planning to begin construction. The prices are given in the table. $$ \begin{array}{rrrr} && {\text { State }} \\ \hline 1 & 2 & 3 & 4 \\ \hline \$ 241 & \$ 216 & \$ 230 & \$ 245 \\ 235 & 220 & 225 & 250 \\ 238 & 205 & 235 & 238 \\ 247 & 213 & 228 & 255 \\ 250 & 220 & 240 & 255 \end{array} $$ a. What type of experimental design has been used? b. Construct the analysis of variance table for this data. c. Do the data provide sufficient evidence to indicate that the average price per 1000 board feet of Douglas fir differs among the four states? Test using \(\alpha=.05\)

Exercise 10.40 examined an advertisement for Albertsons, a supermarket chain in the western United States. The advertiser claims that Albertsons has consistently had lower prices than four other full-service supermarkets. As part of a survey conducted by an "independent market basket price-checking company," the average weekly total based on the prices of approximately 95 items is given for five different supermarket chains recorded during 4 consecutive weeks. $$ \begin{array}{llrlll} & \text { Albertsons } & \text { Ralphs } & \text { Vons } & \text { Alpha Beta } & \text { Lucky } \\ \hline \text { Week 1 } & \$ 254.26 & \$ 256.03 & \$ 267.92 & \$ 260.71 & \$ 258.84 \\ \text { Week 2 } & 240.62 & 255.65 & 251.55 & 251.80 & 242.14 \\ \text { Week 3 } & 231.90 & 255.12 & 245.89 & 246.77 & 246.80 \\ \text { Week 4 } & 234.13 & 261.18 & 254.12 & 249.45 & 248.99 \end{array} $$ a. What type of design has been used in this experiment? b. Conduct an analysis of variance for the data. c. Is there sufficient evidence to indicate that there is a difference in the average weekly totals for the five supermarkets? Use \(\alpha=.05\) d. Use Tukey's method for paired comparisons to determine which of the means are significantly different from each other. Use \(\alpha=.05 .\)

An article in Archaeometry involved an analysis of 26 samples of Romano- British pottery, found at four different kiln sites in the United Kingdom. \(^{9}\) Since one site only yielded two samples, consider the samples found at the other three sites. The samples were analyzed to determine their chemical composition and the percentage of iron oxide is shown below. a. What type of experimental design is this? b. Use an analysis of variance to determine if there is a difference in the average percentage of iron oxide at the three sites. Use \(\alpha=.01\). c. If you have access to a computer program, generate the diagnostic plots for this experiment. Does it appear that any of the analysis of variance assumptions have been violated? Explain.

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