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91Ó°ÊÓ

What assumptions are made about the populations from which random samples are obtained when the \(t\) distribution is used in making small-sample inferences concerning the difference in population means?

Short Answer

Expert verified
The main assumptions are: 1. Independent random samples: Both samples are randomly and independently selected from their respective populations. 2. Normality assumption: Both populations follow a normal distribution. However, as the sample size increases, the Central Limit Theorem can help to alleviate the need for strict normality assumptions. 3. Equality of variances (homoscedasticity): Both populations have equal variances, which allows using the pooled t-test. 4. Small sample size: The t-distribution is used for small sample sizes, typically when the number of observations in each group is less than 30.

Step by step solution

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1. Independent Random Samples

The first assumption is that the two samples are randomly and independently selected from their respective populations. This means that each individual within the sample is equally likely to be chosen for the study.
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2. Normality Assumption

The second assumption is that both populations follow a normal distribution. While strict normality is not always required, the t-distribution is more robust with a closer approximation to normality. If the sample size is large enough, the Central Limit Theorem can help to alleviate the need for strict normality assumptions, but with small samples, a closer approximation to normality is necessary.
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3. Equality of Variances (Homoscedasticity)

The third assumption is that both populations have equal variances. This is also known as homoscedasticity. When the assumption of equal variances is met, we can use the pooled t-test, which combines the variances of both samples into a single estimate.
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4. Small Sample Size

The t-distribution is used for small sample sizes, typically when the number of observations is less than 30 for each group. As the sample size increases, the t-distribution approaches the standard normal distribution, which can be used for larger sample sizes instead. In conclusion, when using the t-distribution for small-sample inferences about the difference in population means, it is assumed that the samples are independently and randomly selected, both populations are normally distributed, have equal variances, and have small sample sizes (typically less than 30 observations each).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Independent Random Samples
When working with the t-distribution, one critical assumption is that the samples involved are independent random samples. What does this mean? Essentially, it means that the choice of one sample has no effect on the choice of another sample. Each sample is selected entirely by chance from its underlying population, ensuring no patterns or relationships that could bias results.
For example, if you're conducting a study with two different groups, each member should be selected independently to ensure everyone has an equal opportunity to be chosen. This randomness guarantees that our statistical conclusion about the population mean difference is both valid and reliable.
Remember, the integrity of statistical analysis heavily depends on this assumption, as any dependency between samples can lead to incorrect inferences.
Normality Assumption
Another pivotal assumption for the t-distribution is the normality of the populations involved. What this means is that each population from which a sample is drawn should ideally follow a normal distribution shape.
The t-distribution is particularly adaptable to deviations from normality when sample sizes are large enough. However, in the context of small samples, this assumption becomes crucial because the data may not adequately represent its population, making the analysis less reliable.
If the population is not strictly normal but can approximate normality, the t-distribution can still be effectively used. If the samples are large, the Central Limit Theorem helps as it implies that the sampling distribution of the sample means will approach normality. Nonetheless, for smaller samples, deviations from normal distribution can lead to biased results.
Equality of Variances
In statistical terms, having equal variances between two populations means that the spread or dispersion of scores is the same in both groups. This assumption is often referred to as homoscedasticity.
Why is this important? When the variances are equal, statistical methods like the pooled t-test allow for a more efficient estimate of the population mean difference, as it integrates the variance estimate from both groups.
If the variances are unequal, different statistical techniques might need to be used, such as Welch's t-test, which does not assume equal variances. That's why testing for the equality of variances is a common step before proceeding with a t-test; ensuring adequate homoscedasticity can significantly enhance the validity of the conclusions drawn from the analysis.
Small Sample Size
The necessity for a t-distribution often arises with small sample sizes, typically defined as having fewer than 30 observations per group. This size restriction is pivotal since smaller samples do not sufficiently capture the population's properties, necessitating a distribution model like the t-distribution that smoothly handles this limitation with a thicker tail.
As sample sizes grow, the t-distribution begins to mirror the standard normal distribution. The precision and reliability of the t-distribution embolden researchers to make valid statistical inferences despite limited data.
Choosing the correct distribution based on sample size ensures that the conclusions are consistent and have reduced variability, safeguarding against erroneous interpretations. Thus, small sample size is not a setback but a guiding criterion for employing the t-distribution effectively in hypothesis testing.

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Most popular questions from this chapter

Although there are many treatments for bulimia nervosa, some subjects fail to benefit from treatment. In a study to determine which factors predict who will benefit from treatment, an article in the British Journal of Clinical Psychology indicates that self-esteem was one of these important predictors. The table gives the mean and standard deviation of self-esteem scores prior to treatment, at post treatment, and during a follow-up: $$ \begin{array}{lccc} & \text { Pretreatment } & \text { Posttreatment } & \text { Follow-up } \\ \hline \text { Sample Mean } \bar{x} & 20.3 & 26.6 & 27.7 \\ \text { Standard Deviation } s & 5.0 & 7.4 & 8.2 \\ \text { Sample Size } n & 21 & 21 & 20 \end{array} $$ a. Use a test of hypothesis to determine whether there is sufficient evidence to conclude that the true pretreatment mean is less than 25 . b. Construct a \(95 \%\) confidence interval for the true posttreatment mean. c. In Section 10.4 , we will introduce small-sample techniques for making inferences about the difference between two population means. Without the formality of a statistical test, what are you willing to conclude about the differences among the three sampled population means represented by the results in the table?

A random sample of \(n=15\) observations was selected from a normal population. The sample mean and variance were \(\bar{x}=3.91\) and \(s^{2}=.3214 .\) Find a \(90 \%\) confidence interval for the population variance \(\sigma^{2}\).

In an effort to compare the average swimming times for two swimmers, each swimmer was asked to swim freestyle for a distance of 100 yards at randomly selected times. The swimmers were thoroughly rested between laps and did not race against each other, so that each sample of times was an independent random sample. The times for each of 10 trials are shown for the two swimmers. \begin{tabular}{ll|ll} \multicolumn{2}{l|} { Swimmer 1} & \multicolumn{2}{c} { Swimmer 2 } \\ \hline 59.62 & 59.74 & 59.81 & 59.41 \\ 59.48 & 59.43 & 59.32 & 59.63 \\ 59.65 & 59.72 & 59.76 & 59.50 \\ 59.50 & 59.63 & 59.64 & 59.83 \\\ 60.01 & 59.68 & 59.86 & 59.51 \end{tabular} Suppose that swimmer 2 was last year's winner when the two swimmers raced. Does it appear that the average time for swimmer 2 is still faster than the average time for swimmer 1 in the 100 -yard freestyle? Find the approximate \(p\) -value for the test and interpret the results.

Jan Lindhe conducted a study on the effect of an oral anti plaque rinse on plaque buildup on teeth. \(^{6}\) Fourteen people whose teeth were thoroughly cleaned and polished were randomly assigned to two groups of seven subjects each. Both groups were assigned to use oral rinses (no brushing) for a 2 -week period. Group 1 used a rinse that contained an anti plaque agent. Group \(2,\) the control group, received a similar rinse except that, unknown to the subjects, the rinse contained no anti plaque agent. A plaque index \(x,\) a measure of plaque buildup, was recorded at \(4,7,\) and 14 days. The mean and standard deviation for the 14 -day plaque measurements are shown in the table for the two groups. Control Group Anti plaque Group Sample Size Sample Size Mean Standard Deviation a. State the null and alternative hypotheses that should be used to test the effectiveness of the anti plaque oral rinse. b. Do the data provide sufficient evidence to indicate that the oral anti plaque rinse is effective? Test using \(\alpha=.05\) c. Find the approximate \(p\) -value for the test.

An experiment was conducted to compare the mean lengths of time required for the bodily absorption of two drugs \(\mathrm{A}\) and \(\mathrm{B}\). Ten people were randomly selected and assigned to receive one of the drugs. The length of time (in minutes) for the drug to reach a specified level in the blood was recorded, and the data summary is given in the table: Drug A Drug B \(\bar{x}_{1}=27.2 \quad \bar{x}_{2}=33.5\) \(s_{1}^{2}=16.36 \quad s_{2}^{2}=18.92\) a. Do the data provide sufficient evidence to indicate a difference in mean times to absorption for the two drugs? Test using \(\alpha=.05 .\) b. Find the approximate \(p\) -value for the test. Does this value confirm your conclusions? c. Find a \(95 \%\) confidence interval for the difference in mean times to absorption. Does the interval confirm your conclusions in part a?

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