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A fair coin is tossed 100 times. The expected number of heads is 50 , and the standard deviation for the number of heads is \((100 \cdot 1 / 2 \cdot 1 / 2)^{1 / 2}=5 .\) What does Chebyshev's Inequality tell you about the probability that the number of heads that turn up deviates from the expected number 50 by three or more standard deviations (i.e., by at least 15\() ?\)

Short Answer

Expert verified
There is at most an 11.1% chance that the number of heads will deviate by at least 15 from 50.

Step by step solution

01

Understanding Chebyshev's Inequality

Chebyshev's Inequality provides a way to estimate probabilities for distributions where normality is not assumed. It states that for any integer \( k > 0 \), the probability that the value deviates from the mean by more than \( k \) standard deviations is at most \( \frac{1}{k^2} \). Here, we need to calculate the probability of a deviation of at least three standard deviations from the mean number of heads, which is 50.
02

Determine the Standard Deviation and Mean

From the problem statement, the mean number of heads is 50, and the standard deviation is 5. We are focusing on the deviation from the mean by three standard deviations, which calculates to \( 3 \times 5 = 15 \). Thus, we are interested in the probability that the number of heads deviates from 50 by at least 15.
03

Applying Chebyshev's Inequality

Using Chebyshev's Inequality with \( k = 3 \), the inequality can be expressed as:\[ P(|X - 50| \geq 15) \leq \frac{1}{3^2} = \frac{1}{9} \]. This tells us that the probability that the number of heads deviates from the mean by at least 15 is at most \( \frac{1}{9} \).
04

Result Interpretation

With Chebyshev's Inequality calculated, it assures us that the likelihood of the deviation being 15 or more heads (either more or fewer than 50) is no greater than \( \frac{1}{9} \), which approximates to about 0.111 or 11.1%.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability Theory
Probability theory forms the backbone of statistics and is used to model randomness and uncertainty. This theory helps in understanding and predicting the likelihood of different outcomes. In the context of flipping a fair coin 100 times, every flip is independent of others and has a probability of 0.5 for landing heads or tails. This independence and binary outcome make the analysis more straightforward yet profoundly fascinating. Probability theory works with important concepts such as events (like getting heads when you flip the coin) and their probabilities (how likely an event is to happen). By understanding these, we can make informed statements about what to expect in real-life scenarios. For example, by using the principles of probability, we can calculate that even if only 50 heads are expected on average, there might still be variations each time you perform the experiment.
  • Events: Possible outcomes of a random process, e.g., getting heads when tossing a coin.
  • Independence: Past coin flips do not affect the outcome of the next flip.
  • Probability: The numerical measure of how likely an event is to occur.
Standard Deviation
Standard deviation is a key concept in statistics that measures the amount of variation or dispersion in a set of values. When flipping a coin, it helps understand how much the number of heads might vary from the expected average of 50 heads.In this exercise, the standard deviation was derived as 5, indicating that although on average 50 heads are expected, the number could often stray by about 5 heads from this mean. This measure provides insight into the spread of the outcomes around the mean and is crucial for applying Chebyshev's Inequality.
  • Understanding Variability: Standard deviation quantifies how much a set of numbers differs from the mean.
  • Application in Chebyshev's Inequality: Informs how likely it is for a result to fall within a number of deviations from the mean.
  • Simple Calculation: For a fair coin tossed 100 times, \( \sigma = \sqrt{100 \cdot 0.5 \cdot 0.5} = 5 \).
Expected Value
Expected value is a fundamental concept in probability and statistics which is the average outcome you would anticipate if you could repeat an experiment over and over. In probability theory related to the flip of a coin, the expected number of heads in 100 tosses is easily calculated by multiplying the number of trials by the probability of getting heads (0.5). Thus, the expected number of heads is 50.Think of expected value like your best guess of what will happen over the long term or in repeated trials. Even if in one set of 100 coin flips the actual number of heads varies, the expected value provides a benchmark.
  • Relation to Mean: The expected value often corresponds closely to the mean of the distribution of results in large samples.
  • Calculation Example: For 100 flips, \( E(X) = 100 \times 0.5 = 50 \).
  • Significance: Helps in planning and understanding potential outcomes and their frequencies.

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Most popular questions from this chapter

Let \(X\) by any random variable which takes on values \(0,1,2, \ldots, n\) and has \(E(X)=V(X)=1\). Show that, for any positive integer \(k\) $$ P(X \geq k+1) \leq \frac{1}{k^{2}} $$

Write a program to toss a coin 10,000 times. Let \(S_{n}\) be the number of heads in the first \(n\) tosses. Have your program print out, after every 1000 tosses, \(S_{n}-n / 2 .\) On the basis of this simulation, is it correct to say that you can expect heads about half of the time when you toss a coin a large number of times?

The Pilsdorff beer company runs a fleet of trucks along the 100 mile road from Hangtown to Dry Gulch, and maintains a garage halfway in between. Each of the trucks is apt to break down at a point \(X\) miles from Hangtown, where \(X\) is a random variable uniformly distributed over [0,100] (a) Find a lower bound for the probability \(P(|X-50| \leq 10)\). (b) Suppose that in one bad week, 20 trucks break down. Find a lower bound for the probability \(P\left(\left|A_{20}-50\right| \leq 10\right),\) where \(A_{20}\) is the average of the distances from Hangtown at the time of breakdown.

Let \(Z=X / Y\) where \(X\) and \(Y\) have normal densities with mean 0 and standard deviation \(1 .\) Then it can be shown that \(Z\) has a Cauchy density. (a) Write a program to illustrate this result by plotting a bar graph of 1000 samples obtained by forming the ratio of two standard normal outcomes. Compare your bar graph with the graph of the Cauchy density. Depending upon which computer language you use, you may or may not need to tell the computer how to simulate a normal random variable. A method for doing this was described in Section 5.2 .

A fair coin is tossed a large number of times. Does the Law of Large Numbers assure us that, if \(n\) is large enough, with probability \(>.99\) the number of heads that turn up will not deviate from \(n / 2\) by more than \(100 ?\)

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