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Suppose again that \(Z=X+Y\). Find \(f_{Z}\) if $$ \begin{aligned} f_{X}(x) &=\frac{1}{\sqrt{2 \pi} \sigma_{1}} e^{-\left(x-\mu_{1}\right)^{2} / 2 \sigma_{1}^{2}} \\ f_{Y}(x) &=\frac{1}{\sqrt{2 \pi} \sigma_{2}} e^{-\left(x-\mu_{2}\right)^{2} / 2 \sigma_{2}^{2}} \end{aligned} $$.

Short Answer

Expert verified
\(f_Z(z) = \frac{1}{\sqrt{2\pi(\sigma_1^2 + \sigma_2^2)}} e^{-\frac{(z - (\mu_1 + \mu_2))^2}{2(\sigma_1^2 + \sigma_2^2)}}\).

Step by step solution

01

Identify Given Distributions

Recognize that both \(X\) and \(Y\) are normally distributed. \(X\) has mean \(\mu_1\) and standard deviation \(\sigma_1\), while \(Y\) has mean \(\mu_2\) and standard deviation \(\sigma_2\). Therefore, \(X \sim N(\mu_1, \sigma_1^2)\) and \(Y \sim N(\mu_2, \sigma_2^2)\).
02

Determine Distribution of Sum

When two independent normal random variables are added together, their sum is also normally distributed. For \(Z = X + Y\), the mean is \(\mu_Z = \mu_1 + \mu_2\) and the variance is \(\sigma_Z^2 = \sigma_1^2 + \sigma_2^2\). Thus \(Z \sim N(\mu_1 + \mu_2, \sigma_1^2 + \sigma_2^2)\).
03

Write the PDF of Sum

The probability density function \(f_Z(z)\) is given by the normal distribution formula: \[f_Z(z) = \frac{1}{\sqrt{2\pi \sigma_Z^2}} e^{-\frac{(z - \mu_Z)^2}{2\sigma_Z^2}}\]Substitute \(\mu_Z = \mu_1 + \mu_2\) and \(\sigma_Z^2 = \sigma_1^2 + \sigma_2^2\) to get:\[f_Z(z) = \frac{1}{\sqrt{2\pi(\sigma_1^2 + \sigma_2^2)}} e^{-\frac{(z - (\mu_1 + \mu_2))^2}{2(\sigma_1^2 + \sigma_2^2)}}\]
04

Conclusion

The probability density function \(f_Z(z)\) for the sum of two independent normal random variables \(X\) and \(Y\) is normal with parameters calculated previously. Therefore, the final expression for \(f_Z(z)\) is complete.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Normal Distribution
The normal distribution, often called the bell curve due to its iconic shape, is a fundamental concept in statistics and probability. It describes data that tend to cluster around a mean or average value. When plotted on a graph, it forms a symmetrical curve with a peak at its mean and tails that taper off equally on either side.

Key characteristics of a normal distribution include:
  • It is symmetric around the mean, meaning that the left and right sides of the curve are mirror images.
  • The mean, median, and mode of a normally distributed data set are equal.
  • The empirical rule, which states that about 68% of data falls within one standard deviation of the mean, 95% within two, and 99.7% within three.
The standard normal distribution is a special case where the mean is zero and the standard deviation is one. This is denoted as \(N(0, 1)\). A common application of normal distributions is in determining probabilities and understanding the spread of data around a central value.

In the problem from the textbook, the variables \(X\) and \(Y\) are both normally distributed. This is important, as it allows us to utilize the properties of the normal distribution when calculating the probability distribution of their sum, \(Z = X + Y\).
Random Variables
A random variable is a numerical outcomes of a random phenomenon. It assigns numbers to each outcome of a random process, and can be classified as either discrete or continuous.

  • Discrete random variables take on a countable number of distinct values, like the roll of a dice.
  • Continuous random variables, like the ones in this problem, can take on an infinite number of possible values within a given range.
In the context of the exercise, both \(X\) and \(Y\) are continuous random variables drawn from normal distributions, implying they can take any real value. Because they are independent, the probabilities concerning \(X\) do not affect those concerning \(Y\).

Therefore, to find the probability distribution of their sum \(Z = X + Y\), we leverage the property that the sum of two independent normally distributed random variables is also normally distributed. Knowing this is fundamental in dealing with problems of statistical sums like the one given in the textbook.
Probability Density Function
A probability density function (PDF) defines the likelihood of a random variable to take on a particular value. For continuous random variables, such as those considered in this exercise, the PDF is vital for determining probabilities over intervals.

Unlike probabilities for discrete random variables, the probability of a continuous random variable taking on an exact value is always zero. Instead, we find probabilities for continuous variables across intervals by calculating the area under the PDF curve.

For a normal distribution, the PDF has a distinct mathematical form:
  • It is written as \(f(x) = \frac{1}{\sqrt{2 \pi \sigma^2}} e^{-\frac{(x - \mu)^2}{2 \sigma^2}}\).
  • The parameters \(\mu\) and \(\sigma\) represent the mean and standard deviation, respectively.
In the textbook problem, the sum \(Z = X + Y\) is a random variable with its PDF \(f_Z(z) = \frac{1}{\sqrt{2\pi(\sigma_1^2 + \sigma_2^2)}} e^{-\frac{(z - (\mu_1 + \mu_2))^2}{2(\sigma_1^2 + \sigma_2^2)}}\). This describes the probability distribution of \(Z\), using the properties of the PDF of normal distributions and the results obtained by summing independent random variables.

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Most popular questions from this chapter

Assume that you are playing craps with dice that are loaded in the following way: faces two, three, four, and five all come up with the same probability \((1 / 6)+r\). Faces one and six come up with probability \((1 / 6)-2 r,\) with \(0<\) \(r<.02\). Write a computer program to find the probability of winning at craps with these dice, and using your program find which values of \(r\) make craps a favorable game for the player with these dice.

People arrive at a queue according to the following scheme: During each minute of time either 0 or 1 person arrives. The probability that 1 person arrives is \(p\) and that no person arrives is \(q=1-p .\) Let \(C_{r}\) be the number of customers arriving in the first \(r\) minutes. Consider a Bernoulli trials process with a success if a person arrives in a unit time and failure if no person arrives in a unit time. Let \(T_{r}\) be the number of failures before the \(r\) th success. (a) What is the distribution for \(T_{r} ?\) (b) What is the distribution for \(C_{r} ?\) (c) Find the mean and variance for the number of customers arriving in the first \(r\) minutes.

Consider the following two experiments: the first has outcome \(X\) taking on the values \(0,1,\) and 2 with equal probabilities; the second results in an (independent) outcome \(Y\) taking on the value 3 with probability \(1 / 4\) and 4 with probability \(3 / 4\). Find the distribution of (a) \(Y+X\) (b) \(Y-X\).

(a) A die is rolled three times with outcomes \(X_{1}, X_{2},\) and \(X_{3} .\) Let \(Y_{3}\) be the maximum of the values obtained. Show that $$ P\left(Y_{3} \leq j\right)=P\left(X_{1} \leq j\right)^{3} $$ Use this to find the distribution of \(Y_{3} .\) Does \(Y_{3}\) have a bell-shaped distribution? (b) Now let \(Y_{n}\) be the maximum value when \(n\) dice are rolled. Find the distribution of \(Y_{n} .\) Is this distribution bell-shaped for large values of \(n ?\)

Let \(X_{1}, X_{2}, \ldots, X_{n}\) be \(n\) independent random variables each of which has an exponential density with mean \(\mu\). Let \(M\) be the minimum value of the \(X_{j} .\) Show that the density for \(M\) is exponential with mean \(\mu / n .\) Hint: Use cumulative distribution functions.

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