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Let \(X\) be a continuous random variable with density function \(f_{X}(x) .\) Show that if $$\int_{-\infty}^{+\infty} x^{2} f_{X}(x) d x<\infty$$ then $$\int_{-\infty}^{+\infty}|x| f_{X}(x) d x<\infty$$

Short Answer

Expert verified
If \(\int x^2 f_X(x) \, dx < \infty\), then \(\int |x| f_X(x) \, dx < \infty\).

Step by step solution

01

Understand the Statement

We need to show that if the integral of \(x^2 f_X(x)\) over the entire real line is finite, then the integral of \(|x| f_X(x)\) over the real line is also finite. This essentially means that ensuring the second moment of the distribution is finite implies that the first absolute moment is also finite.
02

Analyze the Function Behaviors

Consider the relationship between \(x^2\) and \(|x|\). Notice that \(x^2 \geq |x|\) for all real numbers \(x\). This will be crucial for our comparison of the integrals.
03

Compare the Integrals

Since \(x^2 \geq |x|\) for all \(x\), it follows that \(x^2 f_X(x) \geq |x| f_X(x)\). If the integral of \(x^2 f_X(x)\) is finite, it suggests that the potentially "larger" function integrates to be finite, which implies that the integral of the "smaller" function \(|x| f_X(x)\) is also finite.
04

Formalize with Dominated Convergence

Use the fact that if a function \(g(x)\) bounds \(h(x)\) from above (i.e., \(g(x) \geq h(x)\) for all \(x\)), and \(\int g(x) \, dx\) is finite, then \(\int h(x) \, dx\) is also finite. In our case, \(g(x) = x^2 f_X(x)\) and \(h(x) = |x| f_X(x)\). Thus, \(\int_{-\infty}^{+\infty} |x| f_X(x) \, dx < \infty\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Density Function
A density function, often represented as \( f_X(x) \), is fundamental to understanding continuous random variables. It helps describe the probability distribution of these variables. Unlike probability mass functions used for discrete random variables, the density function gives you a way to calculate the likelihood of a random variable falling within a particular range of values. However, the value of the density function itself doesn't represent a probability.

Probabilities in the context of density functions are derived from the area under the curve of the function for a particular interval. This is done using integral calculus. The total area under the density curve over the entire space must equal 1, representing the certainty that the random variable will take some value in its domain.
  • Key Point: The density function does not give probabilities directly but helps calculate them over intervals.
Unlocking the density function's power involves understanding how it interacts with continuous random variables and transforms theoretical distributions into predictions and expectations about real-world phenomena.
Second Moment
The second moment of a random variable is a statistic that offers insights into the distribution's spread and variability. It is most commonly known for its role in calculating the variance when you consider the expectation of the square of the deviation from the mean. But here, we talk about the raw second moment.

Specifically, the second moment is the expected value of the square of the random variable, written mathematically as \( E[X^2] \). To find this for a continuous random variable with density function \( f_X(x) \), you compute the integral \( \int_{-\infty}^{+\infty} x^2 f_X(x) \, dx \). This integral should be finite for meaningful analysis.
  • Application: Helps in measuring volatility and is foundational for calculating variance.
Overall, the second moment plays a crucial role in understanding how a distribution stretches or compresses around its expected value.
Absolute Moment
The concept of an absolute moment provides a way to assess a random variable's likely deviations from a central point, typically the mean or 0. The first absolute moment, particularly, is an expectation of the absolute value of the random variable and is expressed as \( E[|X|] \).

For continuous random variables, this is calculated using the integral \( \int_{-\infty}^{+\infty} |x| f_X(x) \, dx \). It serves as a measure of the average magnitude of deviations, without concern for their direction. In the context of the problem, the theorem was to show that if the second moment is finite, the first absolute moment is also finite, which we can infer due to the mathematical relationship \( x^2 \geq |x| \) for all \( x \).
  • Benefits: Provides a less variance-sensitive measure of variability.
The absolute moment is important in understanding how values deviate from a central tendency in a scale-invariant manner.
Finite Integrals
Finite integrals are essential in probability and statistics, especially when working with continuous random variables and density functions. When an integral of a function over its entire range is finite, it implies that the function sums up to a finite value over that interval. This is crucial for practical applications in probability, where we often need these integrals to be finite to ensure calculated properties like moments make sense.

In the exercise, the finite nature of the integrals serves as a criterion for the existence of specific statistical properties like moments. Specifically, it demonstrates how if the integral \( \int_{-\infty}^{+\infty} x^2 f_X(x) \, dx \) is finite, then so is \( \int_{-\infty}^{+\infty} |x| f_X(x) \, dx \).
  • Importance: Finite integrals ensure valid statistical measures and model predictions.
Understanding finite integrals helps validate statistical models, ensuring they are mathematically sound and practically applicable.

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Most popular questions from this chapter

A multiple choice exam is given. A problem has four possible answers, and exactly one answer is correct. The student is allowed to choose a subset of the four possible answers as his answer. If his chosen subset contains the correct answer, the student receives three points, but he loses one point for each wrong answer in his chosen subset. Show that if he just guesses a subset uniformly and randomly his expected score is zero.

An urn contains exactly 5000 balls, of which an unknown number \(X\) are white and the rest red, where \(X\) is a random variable with a probability distribution on the integers \(0,1,2, \ldots, 5000\) (a) Suppose we know that \(E(X)=\mu\). Show that this is enough to allow us to calculate the probability that a ball drawn at random from the urn will be white. What is this probability? (b) We draw a ball from the urn, examine its color, replace it, and then draw another. Under what conditions, if any, are the results of the two drawings independent; that is, does \(P(\) white, white \()=P(\text { white })^{2} ?\) (c) Suppose the variance of \(X\) is \(\sigma^{2}\). What is the probability of drawing two white balls in part (b)?

An insurance company has 1,000 policies on men of age \(50 .\) The company estimates that the probability that a man of age 50 dies within a year is .01 . Estimate the number of claims that the company can expect from beneficiaries of these men within a year.

A die is loaded so that the probability of a face coming up is proportional to the number on that face. The die is rolled with outcome \(X\). Find \(V(X)\) and \(D(X)\)

In Las Vegas the roulette wheel has a 0 and a 00 and then the numbers 1 to 36 marked on equal slots; the wheel is spun and a ball stops randomly in one slot. When a player bets 1 dollar on a number, he receives 36 dollars if the ball stops on this number, for a net gain of 35 dollars; otherwise, he loses his dollar bet. Find the expected value for his winnings.

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