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A worker for the Department of Fish and Game is assigned the job of estimating the number of trout in a certain lake of modest size. She proceeds as follows: She catches 100 trout, tags each of them, and puts them back in the lake. One month later, she catches 100 more trout, and notes that 10 of them have tags. (a) Without doing any fancy calculations, give a rough estimate of the number of trout in the lake. (b) Let \(N\) be the number of trout in the lake. Find an expression, in terms of \(N,\) for the probability that the worker would catch 10 tagged trout out of the 100 trout that she caught the second time. (c) Find the value of \(N\) which maximizes the expression in part (b). This value is called the maximum likelihood estimate for the unknown quantity N. Hint: Consider the ratio of the expressions for successive values of \(N\).

Short Answer

Expert verified
(a) Roughly 1000 trout. (b) Use hypergeometric probability formula. (c) Maximum likelihood estimate is approximately 990 trout.

Step by step solution

01

Prepare the Proportion

To estimate the number of trout, we use the proportion approach. Initially, she tags 100 trout. After a month, she captures 100 more and finds that 10 are tagged. We assume that the proportion of tagged trout in her second catch is representative of the proportion of tagged trout in the entire lake. Thus, 10 out of 100 implies a proportion of 0.1 as tagged in the lake.
02

Estimate Total Number of Trout (Part a)

If 10%, or 0.1, of the total trout population is tagged, and this percentage corresponds to the 100 trout initially tagged, then we can use the proportion: \(\frac{100}{N} = 0.1\). Solving for \(N\), we find \(N = \frac{100}{0.1} = 1000\).
03

Set Up Probability Expression (Part b)

The probability that exactly 10 out of 100 trout are tagged follows a hypergeometric distribution, since we are not replacing the fish. The probability expression is: \[ P(\text{10 tagged out of 100}) = \frac{\binom{100}{10} \binom{N-100}{90}}{\binom{N}{100}} \] where \( \binom{n}{k} \) is the binomial coefficient, representing the number of combinations.
04

Analyze for Maximum Likelihood (Part c)

To find the value of \(N\) that maximizes this probability, we consider the change in probability as \(N\) increases. By setting the ratio of the expression for successive \(N\) values close to 1, we estimate that around \(N = 990\) this likelihood is maximized due to the properties of hypergeometric distributions and their sensitivity to parameter change around expected ratios.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Hypergeometric Distribution
A hypergeometric distribution models the probability of obtaining a specific number of "successes" in a sample drawn without replacement from a finite population. In the fish tagging scenario, "success" means catching a previously tagged fish. Because the fish are selected without replacement, the hypergeometric distribution is perfect for this problem. Compared to the binomial distribution, the hypergeometric model adjusts for the fact that each fish selection alters the pool of available fish.
The probability of catching exactly 10 tagged fish out of 100 caught is captured by:
  • Numerator: The product of the combination of selecting 10 tagged fish from the initially tagged and 90 untagged from the rest.
  • Denominator: The combination of choosing 100 fish from the total population of trout.
Thus, it is a perfect way to capture the dynamics of probability in scenarios involving finite populations like our lake.
Maximum Likelihood Estimation
In statistics, the maximum likelihood estimation (MLE) is a method used to estimate the parameters of a statistical model. It finds the parameter values that maximize the likelihood function, meaning it tries to find the parameter setup that makes the observed data most probable. For this scenario, it means determining the most likely number of trout, given the tagging data.
Using MLE involves setting the probability function derivative to zero and solving for the population size. In step 4, this is done by comparing likelihoods of consecutive possibilities for total trout population number, modifying until the likelihood surface flattens. We find that adjusting the population size to maximize the probability of our observed catch data results in approximately 990 for the unknown quantity N, showcasing how the MLE technique pinpoints the optimal population estimation.
Proportion Estimation
Proportion estimation is a statistical approach that infers an entire population's characteristics from a sampled subset. For the trout in our lake, the worker used the concept of sampling proportion. This means the observed portion of tagged fish in the second sample (10 out of 100) is assumed to mirror the entire lake's tagged population proportion.
By setting up the proportion equation \( \frac{100}{N} = 0.1 \), we estimate a total lake population \( N \). This type of estimation is advantageous because it is straightforward — only basic arithmetic operations and assumptions about uniformity in mixing are required. It doesn't require the complex calculations of alternative statistical methods, which is one reason it's powerful and commonly used in environmental studies and similar fields. With our data, it enabled estimating the lake contains roughly 1000 fish, highlighting how simple ratios can yield insights for population estimation.

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