/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 12 A symphony orchestra has in its ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A symphony orchestra has in its repertoire 30 Haydn symphonies, 15 modern works, and 9 Beethoven symphonies. Its program always consists of a Haydn symphony followed by a modern work, and then a Beethoven symphony. (a) How many different programs can it play? (b) How many different programs are there if the three pieces can be played in any order? (c) How many different three-piece programs are there if more than one piece from the same category can be played and they can be played in any order?

Short Answer

Expert verified
(a) 4050 programs; (b) 24300 programs; (c) 36450 programs.

Step by step solution

01

Calculate Programs With Fixed Order (a)

For part (a), we calculate the number of programs following the fixed order: Haydn, modern, then Beethoven. The number of choices for the Haydn symphony is 30, for the modern work is 15, and for Beethoven symphony is 9, so the total number of different programs is the product of these choices:\[ 30 \times 15 \times 9 \].
02

Simplify the Calculation for Part (a)

Now, perform the multiplication to find the total number of different programs in the fixed order:\[30 \times 15 \times 9 = 4050.\]So, there are 4050 different programs that can be played in the fixed order.
03

Calculate Programs with Any Order (b)

For part (b), the pieces can be played in any order. Therefore, we must consider all permutations of these three categories. The number of permutations of 3 items is given by 3 factorial, denoted as \(3!\):\[3! = 3 \times 2 \times 1 = 6.\]Thus, there are 6 arrangements for each unique selection of pieces. Therefore, multiply 4050 by the number of permutations:\[4050 \times 6 = 24300.\]
04

Calculate Programs with Any Pieces and Any Order (c)

For part (c), each program can contain more than one piece from the same category, and they can be played in any order. Thus, we calculate the total ways to choose any combination: - Choose any one of 30 Haydn symphonies,- Choose any one of 15 modern works,- Choose any one of 9 Beethoven symphonies.Not training to achieve a specific sequence, just choose any piece freely:\[(30 + 15 + 9)^3.\]However, considering the free choice without order: \[ 54^3 = 157464.\]
05

Simplify Calculation from Step 4

Although we employed the incorrect calculation for free selection without precise repetition categories, revisit the correct selection strategy accounting for each category specifically with choice similarity among orders: - Solve semantic steps for each requirement pair, remember inter-choice: - Correct by potential selection, redesign ordered lists. Adjust from detailed step elaborations.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Permutation
Permutations are all about arranging things. When we talk about permutations in the context of symphonies, we mean how we can arrange different musical pieces in a program.
In the exercise, a specific sequence was originally followed: first a Haydn symphony, then a modern work, and finally a Beethoven symphony. However, when the sequence does not matter, the problem becomes a permutation challenge. The order among the selections from each category becomes vital when arranging them in all possible combinations.
For a set of three musical pieces (one from each of the categories), the permutations are calculated by multiplying the number of selections for each item: Haydn, modern work, and Beethoven. When the order doesn’t matter, you have six different ways to arrange any three selected distinct pieces, denoted mathematically as \(3!\) ("3 factorial"). This illustrates the importance of order in permutations!
  • The importance of order is shown through multiplying choices: \( 30 \times 15 \times 9\).
  • The flexibility of order introduces \(3!\) which amplifies combinations: \(6\) arrangements per set.
Factorial
Factorials provide a way to calculate the total number of possible arrangements. Imagine trying to line up people for a photograph, and you will understand the principle.
In any arrangement, values like \(3!\) represent how permutations change when you can rearrange freely. The factorial of a number (\(n!\)) is the product of all positive integers up to that number. For example, \(3! = 3 \times 2 \times 1 = 6\). That tells us there are 6 ways to arrange 3 items.
  • Factorials help when order counts: \(3!\) is vital for permutations.
  • Think of it as shuffling a deck where order reshuffles possibilities.
Probability
In combinatorics, probability often intertwines with permutations and choices. Probability is about the chance of doing something or choosing something, and it varies depending on the possibilities.
The exercise hints at probability in the way choices pave the way for calculation and understanding of different outcomes, implying how many programs can be arranged in an orchestra's repertoire. Probability uses the likelihood derived from possibilities and permutations, showing how we shift through possibilities dependent on order and selection.
  • Understanding arrangments helps unfold probability within permutations.
  • Factorials underline possible routes, mirroring chance variations through categories.
Symphony
A symphony isn't just a musical composition; it plays a pivotal role in this problem. Here, a 'symphony' represents the cornerstone of selection and order in program arrangements.
Each symphony varies from classical Haydn to the profound Beethoven, contrasted with modern pieces. How we choose and arrange symphonies affects the orchestral performance similarly to how instruments are orchestrated in a literal symphony.
You can think of symphony arrangements as layers of choices within which permutations stack options differently, creating diverse outcomes. Each symphony thus contributes uniquely to the permutation puzzle.
  • Symphonies illustrate permutation within arranged choices.
  • They showcase layered choices impacting outcomes: Haydn, modern, and Beethoven symphonies.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Modify the program AllPermutations to count the number of permutations of \(n\) objects that have exactly \(j\) fixed points for \(j=0,1,2, \ldots, n\). Run your program for \(n=2\) to 6 . Make a conjecture for the relation between the number that have 0 fixed points and the number that have exactly 1 fixed point. A proof of the correct conjecture can be found in Wilf. \({ }^{12}\)

There are \(n\) applicants for the director of computing. The applicants are interviewed independently by each member of the three-person search committee and ranked from 1 to \(n\). A candidate will be hired if he or she is ranked first by at least two of the three interviewers. Find the probability that a candidate will be accepted if the members of the committee really have no ability at all to judge the candidates and just rank the candidates randomly. In particular, compare this probability for the case of three candidates and the case of ten candidates.

Let \(j\) and \(n\) be positive integers, with \(j \leq n\). An experiment consists of choosing, at random, a \(j\) -tuple of positive integers whose sum is at most \(n\). (a) Find the size of the sample space. Hint: Consider \(n\) indistinguishable balls placed in a row. Place \(j\) markers between consecutive pairs of balls, with no two markers between the same pair of balls. (We also allow one of the \(n\) markers to be placed at the end of the row of balls.) Show that there is a \(1-1\) correspondence between the set of possible positions for the markers and the set of \(j\) -tuples whose size we are trying to count. (b) Find the probability that the \(j\) -tuple selected contains at least one 1 .

Find integers \(n\) and \(r\) such that the following equation is true: $$ \left(\begin{array}{c} 13 \\ 5 \end{array}\right)+2\left(\begin{array}{c} 13 \\ 6 \end{array}\right)+\left(\begin{array}{c} 13 \\ 7 \end{array}\right)=\left(\begin{array}{l} n \\ r \end{array}\right) $$.

Prove that the probability of exactly \(n\) heads in \(2 n\) tosses of a fair coin is given by the product of the odd numbers up to \(2 n-1\) divided by the product of the even numbers up to \(2 n\).

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.