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91Ó°ÊÓ

Give a possible sample space \(\Omega\) for each of the following experiments: (a) An election decides between two candidates \(\mathrm{A}\) and \(\mathrm{B}\). (b) A two-sided coin is tossed. (c) A student is asked for the month of the year and the day of the week on which her birthday falls. (d) A student is chosen at random from a class of ten students. (e) You receive a grade in this course.

Short Answer

Expert verified
Sample spaces are lists of all possible outcomes for each experiment.

Step by step solution

01

Define Sample Space for Election

The sample space, denoted as \( \Omega \), for the experiment of an election deciding between two candidates \( \mathrm{A} \) and \( \mathrm{B} \) can be expressed as:\( \Omega = \{ \text{A wins}, \text{B wins} \}. \)
02

Define Sample Space for Coin Toss

For the experiment of tossing a two-sided coin, the sample space \( \Omega \) is:\( \Omega = \{ \text{Heads}, \text{Tails} \}. \)
03

Define Sample Space for Birthday Indication

When a student is asked for the month of the year and the day of the week on which her birthday falls, the sample space \( \Omega \) consists of all possible combinations of months and days of the week. There are 12 months and 7 days in a week, so:\( \Omega = \{(\text{January, Monday}), (\text{January, Tuesday}), \ldots, (\text{December, Sunday})\} \).
04

Define Sample Space for Selecting a Student

If a student is chosen at random from a class of ten students, the sample space \( \Omega \) includes all individual students, represented perhaps by numbers or names: \( \Omega = \{\text{Student 1}, \text{Student 2}, \ldots, \text{Student 10}\} \).
05

Define Sample Space for Receiving a Grade

For receiving a grade in this course, assuming standard grading, the sample space \( \Omega \) might include: \( \Omega = \{ \text{A}, \text{B}, \text{C}, \text{D}, \text{F}\} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability
Probability is a way to measure the likelihood of certain events happening. In other words, it helps us understand the chance of something occurring. The concept of probability is like predicting how likely it is for a specific outcome to take place in a given experiment or event. It's comparable to making an educated guess based on various possible outcomes.

To put it simply, probability ranges from 0 to 1. Here:
  • If an event is impossible, its probability is 0.
  • If an event is certain, its probability is 1.
  • In-between values indicate varying levels of likelihood.
The formula for calculating probability is:\[P(E) = \frac{Number\ of\ Favorable\ Outcomes}{Total\ Number\ of\ Possible\ Outcomes}\]With this formula, you can easily predict the probability of an event such as flipping a coin or winning an election.
Election Outcome
An election outcome is the final result of a voting process where candidates or options are voted upon. In a simple election with two candidates like A and B, the possible outcomes consist of either candidate A winning or candidate B winning. Hence, the sample space for such an election is expressed as \( \Omega = \{\text{A wins}, \text{B wins}\} \).

When discussing election outcomes, it's essential to consider realistic factors such as voting systems, voter turnout, and margins of error. However, in a basic sense, we are interested in who gets the majority of votes. We use the concept of probability to analyze election outcomes;
  • The probability of candidate A winning could be determined by surveys or historical data.
  • Similarly, for candidate B as well.
By understanding the probability associated with each potential outcome, we can better gauge the significance of the election results.
Coin Toss
A coin toss is one of the simplest forms of a probability experiment and is often used as a metaphor for 50/50 events. The sample space for a fair coin toss, where the only possible outcomes are either 'Heads' or 'Tails,' is given as \( \Omega = \{\text{Heads}, \text{Tails}\} \).

Flipping a coin is widely used in various contexts because it's:
  • Easy to understand
  • Simple to perform
  • Perfectly random with fair coins
The nice thing about a coin toss is that it illustrates the concept of equal probability.

The probability of getting heads is:\[P(\text{Heads}) = \frac{1}{2}\]Similarly, the probability of getting tails is also \( \frac{1}{2} \). Because of its simplicity, coin tossing is often used in examples to help introduce probability concepts.
Birthday Problem
The 'birthday problem' is a classic example in probability theory, illustrating how our intuitions about probability can often be wrong. The problem asks how many people need to be in a room before there's a better than even chance that at least two people share a birthday.

Surprisingly, with just 23 people in a room, there's about a 50% chance of a shared birthday. This counterintuitive result comes from calculating the likelihood that no one shares a birthday and subtracting this from 1. Given there are 365 days to choose from, we compute the probability of no shared birthday. For example:
  • The first person has a choice of any 365 days.
  • The second person has 364 choices, and so on.
The probability that no two individuals share the same birthday can be articulated as:\[P(\text{no shared birthday}) = \frac{365}{365} \times \frac{364}{365} \times \frac{363}{365} \ldots\]Understanding the birthday problem helps highlight how multiple events compound, particularly highlighting unexpected probabilities in everyday life.

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Most popular questions from this chapter

A die is loaded in such a way that the probability of each face turning up is proportional to the number of dots on that face. (For example, a six is three times as probable as a two.) What is the probability of getting an even number in one throw?

In a horse race, the odds that Romance will win are listed as 2: 3 and that Downhill will win are 1: 2 . What odds should be given for the event that either Romance or Downhill wins?

The Labouchere system for roulette is played as follows. Write down a list of numbers, usually \(1,2,3,4 .\) Bet the sum of the first and last, \(1+4=5,\) on red. If you win, delete the first and last numbers from your list. If you lose, add the amount that you last bet to the end of your list. Then use the new list and bet the sum of the first and last numbers (if there is only one number, bet that amount). Continue until your list becomes empty. Show that, if this happens, you win the sum, \(1+2+3+4=10\), of your original list. Simulate this system and see if you do always stop and, hence, always win. If so, why is this not a foolproof gambling system?

Estimate, by simulation, the average number of children there would be in a family if all people had children until they had a boy. Do the same if all people had children until they had at least one boy and at least one girl. How many more children would you expect to find under the second scheme than under the first in 100,000 families? (Assume that boys and girls are equally likely.)

Another well-known gambling system is the martingale doubling system. Suppose that you are betting on red to turn up in roulette. Every time you win, bet 1 dollar next time. Every time you lose, double your previous bet. Suppose that you use this system until you have won at least 5 dollars or you have lost more than 100 dollars. Write a program to simulate this and play it a number of times and see how you do. In his book The Newcomes, W. M. Thackeray remarks "You have not played as yet? Do not do so; above all avoid a martingale if you do." 10 Was this good advice?

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