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Suppose A is a real symmetric matrix. If the eigenvalues of \(\mathbf{A}\) are only \(0 \mathrm{~s}\) and 1 s then prove that \(A\) is idempotent.

Short Answer

Expert verified
Given only 0s and 1s as eigenvalues aligns with the characteristics of an idempotent matrix, this proves that the real symmetric matrix \( \mathbf{A} \) is idempotent.

Step by step solution

01

Characteristics of an Idempotent Matrix

We start by understanding the characteristics of an idempotent matrix. An idempotent matrix is a matrix which, when squared (i.e., when it is multiplied by itself), results in itself. In other words, if \( \mathbf{A} \) is idempotent, then \( \mathbf{A}^2 = \mathbf{A} \).
02

Characteristics of Eigenvalues

The eigenvalues of a matrix are the roots of the characteristic equation, which is \( \text{det}(\mathbf{A} - \lambda \mathbf{I}) = 0 \). For an idempotent matrix, the eigenvalues will be 0s and 1s only. This is because the idempotent matrix property states that \( \mathbf{A}^2 = \mathbf{A} \), and thus the characteristic equation becomes \( (1 - \lambda)\lambda = 0 \). This equation only has roots at 0 and 1, proving that the eigenvalues for an idempotent matrix are 0s and 1s.
03

Proving the Statement

Given that all the eigenvalues of matrix \( \mathbf{A} \) are 0s and 1s only, this aligns with the characteristics of an idempotent matrix. It is thus proven that the real symmetric matrix \( \mathbf{A} \), with eigenvalues as 0s and 1s, is idempotent.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Eigenvalues
Eigenvalues play an important role in understanding the properties and behaviors of matrices. When you have a matrix \( \mathbf{A} \), its eigenvalues are special numbers that provide valuable insight into its characteristics.
You find eigenvalues by solving the characteristic equation: \( \text{det}(\mathbf{A} - \lambda \mathbf{I}) = 0 \). Here, \( \lambda \) represents the eigenvalues and \( \mathbf{I} \) is the identity matrix. What makes eigenvalues so noteworthy is that they reveal intrinsic traits of matrices, such as invertibility and stability.
In this context, if \( \mathbf{A} \) has eigenvalues of 0s and 1s, it suggests that \( \mathbf{A} \) could be idempotent. This is because idempotent matrices, by definition, only have the eigenvalues 0 or 1. Such matrices hold the property \( \mathbf{A}^2 = \mathbf{A} \). This key finding shows how the concept of eigenvalues assists in affirming or verifying matrix properties.
Symmetric Matrices
A symmetric matrix is one of the most straightforward yet intriguing types of matrices. The defining feature of symmetric matrices is that they are equal to their transpose. What this means is if you were to flip the matrix over its main diagonal, it would look exactly the same. Mathematically, this is represented as \( \mathbf{A} = \mathbf{A}^T \).
Symmetric matrices have some special properties worth noting. For one, they have real eigenvalues. This is crucial because dealing with real numbers is often simpler than dealing with complex ones. Another feature is that symmetric matrices are diagonalizable, which implies they can be transformed into a diagonal matrix without altering its eigenvalues. This transformation is achieved through orthogonal matrices, making working with symmetric matrices an easier task.
In the context of the problem, knowing \( \mathbf{A} \) is symmetric means you benefit from these characteristics. The real, manageable eigenvalues, along with the diagonalization approach, make it easier to confirm that the matrix \( \mathbf{A} \) is indeed idempotent given its eigenvalues of 0s and 1s.
Characteristics of Matrix
Matrices come with a range of characteristics, each speaking to their structural properties and the rules that govern their behavior. Characteristics like being idempotent deeply influence how a matrix is understood and applied in various fields.
An idempotent matrix, a prime focus of our discussion, is described by the defining property \( \mathbf{A}^2 = \mathbf{A} \). This means when you multiply an idempotent matrix by itself, it doesn’t change. This property is striking as it points to stability and certain simplifications in matrix operations. Moreover, such matrices only have eigenvalues of either 0 or 1, reinforcing this stable property.
Recognizing these characteristics is instrumental for problem-solving and proofs. By knowing a matrix is symmetric and analyzing its eigenvalues—if they’re only 0s and 1s, for example—you can deduce more about its nature, such as its idempotency. Overall, understanding these key characteristics aids in the broader application and manipulation of matrices in both theory and practice.

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Most popular questions from this chapter

Let \(X_{1}, X_{2}, X_{3}, X_{4}\) denote a random sample of size 4 from a distribution that is \(N\left(0, \sigma^{2}\right)\). Let \(Y=\sum_{1}^{4} a_{i} X_{i}\), where \(a_{1}, a_{2}, a_{3}\), and \(a_{4}\) are real constants. If \(Y^{2}\) and \(Q=X_{1} X_{2}-X_{3} X_{4}\) are independent, determine \(a_{1}, a_{2}, a_{3}\), and \(a_{4}\).

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Let \(A\) be the real symmetric matrix of a quadratic form \(Q\) in the observations of a random sample of size \(n\) from a distribution that is \(N\left(0, \sigma^{2}\right) .\) Given that \(Q\) and the mean \(\bar{X}\) of the sample are independent, what can be said of the elements of each row (column) of \(\boldsymbol{A}\) ? Hint: Are \(Q\) and \(\bar{X}^{2}\) independent?

For the two-way interaction model, \((9.5 .15)\), show that the following decomposition of sums of squares is true: $$ \begin{aligned} \sum_{i=1}^{a} \sum_{j=1}^{b} \sum_{k=1}^{c}\left(X_{i j k}-\bar{X}_{\ldots}\right)^{2}=& b c \sum_{i=1}^{a}\left(\bar{X}_{i . .}-\bar{X}_{\ldots .}\right)^{2}+a c \sum_{j=1}^{b}\left(\bar{X}_{. j .}-\bar{X}_{\ldots}\right)^{2} \\ &+c \sum_{i=1}^{a} \sum_{j=1}^{b}\left(\bar{X}_{i j .}-\bar{X}_{i . .}-\bar{X}_{. j .}+\bar{X}_{\ldots}\right)^{2} \\ &+\sum_{i=1}^{a} \sum_{j=1}^{b} \sum_{k=1}^{c}\left(X_{i j k}-\bar{X}_{i j .}\right)^{2} \end{aligned} $$ that is, the total sum of squares is decomposed into that due to row differences, that due to column differences, that due to interaction, and that within cells.

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