/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 11 Let \(X_{1}, X_{2}, \ldots, X_{n... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Let \(X_{1}, X_{2}, \ldots, X_{n}\) be a random sample from the Poisson distribution with \(0<\theta \leq 2\). Show that the mle of \(\theta\) is \(\widehat{\theta}=\min \\{\bar{X}, 2\\}\).

Short Answer

Expert verified
$\widehat{\theta}=\min \{\bar{X}, 2\}$

Step by step solution

01

Write down the likelihood function

Recall that if \(X_i\) for \(i=1,2,...,n\) are iid Poisson random variables, the likelihood function is given by \(L(\theta |X)=\prod_{i=1}^{n} e^{-\theta} \frac{\theta^{X_i}} {X_i!}\). Taking the natural logarithm of both sides, we get the log-likelihood function, \(l(\theta |X)= \sum_{i=1}^{n} [-\theta +X_i log(\theta) -log(X_i!)]\). Note that we can omit the last term since it does not depend on \(\theta\).
02

Maximize the log-likelihood function

Differentiate the log-likelihood function w.r.t \(\theta\) to find the maximum. Setting \(l'(\theta)\) equal to zero, the derivative is given by \(-n+\frac{\sum X_i}{\theta} = 0\). Solve this equation for \(\theta\) to get \(\theta = \frac{\sum X_i}{n} = \bar{X}\), where \(\bar{X}\) is the sample mean.
03

Show that the mle is \(\widehat{\theta}=\min \{\bar{X}, 2\}\)

Recall the conditions on \(\theta\), \(0<\theta \leq 2\). If the sample mean \(\bar{X} <= 2\), we can set \(\theta = \bar{X}\) without violating these conditions. However, if the sample mean \(\bar{X} > 2\), we must set \(\theta\) to its maximum allowed value which is 2. This leads to the result that \(\widehat{\theta}=\min \{\bar{X}, 2\}\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

\left\\{X_{i}>\theta_{0}\right\\}\(. (b) Show that the scores test for this model is equival… # Consider Example \)6.3 .4\(. (a) Show that we can write \)S^{*}=2 T-n\(, where \)T=\\#\left\\{X_{i}>\theta_{0}\right\\}\(. (b) Show that the scores test for this model is equivalent to rejecting \)H_{0}\( if \)Tc_{2}\( (c) Show that under \)H_{0}, T\( has the binomial distribution \)b(n, 1 / 2) ;\( hence, determine \)c_{1}\( and \)c_{2}\( so the test has size \)\alpha\(. (d) Determine the power function for the test based on \)T\( as a function of \)\theta$.

Let \(X_{1}, X_{2}, \ldots, X_{n}\) be a random sample from a distribution with pdf \(f(x ; \theta)=\theta \exp \left\\{-|x|^{\theta}\right\\} / 2 \Gamma(1 / \theta),-\infty0 .\) Suppose \(\Omega=\) \(\\{\theta: \theta=1,2\\} .\) Consider the hypotheses \(H_{0}: \theta=2\) (a normal distribution) versus \(H_{1}: \theta=1\) (a double exponential distribution). Show that the likelihood ratio test can be based on the statistic \(W=\sum_{i=1}^{n}\left(X_{i}^{2}-\left|X_{i}\right|\right)\).

Let \(X\) be \(N(0, \theta), 0<\theta<\infty\). (a) Find the Fisher information \(I(\theta)\). (b) If \(X_{1}, X_{2}, \ldots, X_{n}\) is a random sample from this distribution, show that the mle of \(\theta\) is an efficient estimator of \(\theta\). (c) What is the asymptotic distribution of \(\sqrt{n}(\widehat{\theta}-\theta) ?\)

Let \(X_{1}, X_{2}, \ldots, X_{n}\) be a random sample from a Poisson distribution with \(\operatorname{mean} \theta>0\) (a) Show that the likelihood ratio test of \(H_{0}: \theta=\theta_{0}\) versus \(H_{1}: \theta \neq \theta_{0}\) is based upon the statistic \(Y=\sum_{i=1}^{n} X_{i} .\) Obtain the null distribution of \(Y\). (b) For \(\theta_{0}=2\) and \(n=5\), find the significance level of the test that rejects \(H_{0}\) if \(Y \leq 4\) or \(Y \geq 17\)

A machine shop that manufactures toggle levers has both a day and a night shift. A toggle lever is defective if a standard nut cannot be screwed onto the threads. Let \(p_{1}\) and \(p_{2}\) be the proportion of defective levers among those manufactured by the day and night shifts, respectively. We shall test the null hypothesis, \(H_{0}: p_{1}=p_{2}\), against a two-sided alternative hypothesis based on two random samples, each of 1000 levers taken from the production of the respective shifts. Use the test statistic \(Z^{*}\) given in Example \(6.5 .3\). (a) Sketch a standard normal pdf illustrating the critical region having \(\alpha=0.05\). (b) If \(y_{1}=37\) and \(y_{2}=53\) defectives were observed for the day and night shifts, respectively, calculate the value of the test statistic and the approximate \(p\) value (note that this is a two-sided test). Locate the calculated test statistic on your figure in part (a) and state your conclusion. Obtain the approximate \(p\) -value of the test.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.