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Let \(Y_{1}

Short Answer

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This problem requires understanding the concept of joint and conditional pdf and the properties of the given distribution. For (a) the solution involves calculating the joint pdf of \(Y_{3}\) and \(Y_{4}\) given the expression for the pdf of the order statistics and using the given pdf and its cdf. For (b) the solution involves finding the marginal pdf for \(Y_{4}\) and calculating the ratio of joint pdf and marginal pdf to get the conditional pdf of \(Y_{3}\) given \(Y_{4} = y_4\). Lastly, for (c) the solution requires calculating the expected value (or average) of \(Y_{3}\) given \(Y_{4}=y_{4}\), based on the conditional pdf from (b).

Step by step solution

01

- Find the joint pdf of \(Y_{3}\) and \(Y_{4}\)

To find the joint pdf of \(Y_{3}\) and \(Y_{4}\), we apply the definition of the joint pdf for order statistics, which is given by: \(f_{Y3, Y4}(y3, y4) = \frac{n!}{(k-1)!(n-k)!(j-1)!(k-j)!(n-m)!(m-j)!} * [F(y_j) - F(y_{j-1})]^{j-1} * [F(y_k) - F(y_j)]^{k-j} * [1 - F(y_k)]^{n-k} * f(y_j) * f(y_k)\). Here, \(f(x) = 2x\) for \(0 < x < 1\) is the pdf and \(F(x) = x^2\) for \(0 < x < 1\) is the corresponding cdf. We substitute \(n=4\), \(k=4\), \(j=3\) into the formula and calculate the values for \(f_{Y3, Y4}(y3, y4)\).
02

- Find the Conditional pdf of \(Y_{3}\) given \(Y_{4}=y_{4}\)

For the conditional pdf we use the result from step 1 and divide the joint pdf by the marginal pdf of \(Y_{4}\), which can be obtained using its definition. Thus, \(f_{Y3| Y4}(y3|y4) = \frac{f_{Y3, Y4}(y3, y4)}{f_{Y4}(y4)}\) . After calculating the marginal pdf and dividing the joint pdf by the marginal pdf, we get the conditional pdf.
03

- Evaluate the conditional expectation \(E\left(Y_{3} \mid y_{4}\right)\)

The conditional expectation \(E(Y_{3}\mid Y_{4}=y_{4})\) is the average value that \(Y_{3}\) will take on given that \(Y_{4}\) has taken on the value \(y_{4}\). This can be computed by taking the integral over the range of \(Y_{3}\): \(E(Y_{3}|Y_{4}=y_{4}) = \int_{-\infty}^{\infty} y3*f_{Y3| Y4}(y3|y4)dy3\). Using the conditional pdf we found in step 2, we calculate the integral (note that the range of \(Y_3\) is from 0 to \(y_4\), given \(Y_4 = y_4\)).

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