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Let \(Y_{1}

Short Answer

Expert verified
The maximum likelihood estimator for \(\theta\) is \(\hat{\theta} = \frac{y_1 + y_n}{2}\) and for \(\rho\) is \(\hat{\rho} = \frac{y_n - y_1}{2}\). Only \(\hat{\theta}\) is an unbiased estimator, while \(\hat{\rho}\) is biased.

Step by step solution

01

Formulate the likelihood function

First, let's write down the density function for a uniform distribution: \(f(y|\theta, \rho) = \frac{1}{2\rho}, \text{ for } \theta - \rho \leq y \leq \theta + \rho\). The joint density is the product of the individual densities, i.e., \(f(y_1, y_2, ..., y_n | \theta, \rho) = \prod_{i=1}^{n} f(y_i | \theta, \rho)\), noting that \(y_1 = \min(y_i)\) and \(y_n = \max(y_i)\).
02

Solve for maximum likelihood estimates

Next, solve the log-likelihood function for maximum likelihood estimates of \(\theta\) and \(\rho\). Since \(\theta\) lies in the interval of \(y_1\) and \(y_n\), the MLE of \(\theta\) is their average, i.e., \(\hat{\theta} = \frac{y_1 + y_n}{2}\). For \(\rho\), maximize the log-likelihood (after using constraints) to get \(\hat{\rho} = \frac{y_n - y_1}{2}\).
03

Determine if the estimates are unbiased

The estimates are unbiased if the expected values of \(\hat{\theta}\) and \(\hat{\rho}\) are equal to \(\theta\) and \(\rho\) respectively. After evaluating the expected values, one can find that \(E(\hat{\theta}) = \theta\) and \(E(\hat{\rho}) \neq \rho\). Therefore, \(\hat{\theta}\) is an unbiased estimator for \(\theta\), whereas \(\hat{\rho}\) is a biased estimator for \(\rho\).

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