Chapter 5: Problem 8
Let \(S_{n}^{2}\) denote the variance of a random sample of size \(n\) from a distribution that is \(n\left(\mu, \sigma^{2}\right) .\) Prove that \(n S_{n}^{2} /(n-1)\) converges stochastically to \(\sigma^{2}\).
Short Answer
Expert verified
The scaled sample variance \(\frac{n}{n-1}S_{n}^{2}\) converges stochastically to \(\sigma^{2}\) as \(n \to \infty\).
Step by step solution
01
Definition of Sample Variance
The sample variance \(S_{n}^{2}\) is defined as \(S_{n}^{2} = \frac{1}{n}\sum_{i=1}^{n} (X_i-\mu)^{2}\) where \(X_i\) is the \(i^{th}\) observation and \(\mu\) is the population mean.
02
Calculation of the Expectation of the Scaled Sample Variance
The expected value of the scaled sample variance is \[E[\frac{n}{n-1}S_{n}^{2}] = E[\frac{1}{n-1}\sum_{i=1}^{n}(X_i-\mu)^2]\]Now apply linearity of expectation:= \(\frac{n}{n-1}E[S_{n}^{2}]\) Since \(X_i\) follows a normal distribution, the variance of \(X_i\) is \(\sigma^2\), and \(E[S_{n}^{2}] = \sigma^2\). Therefore,= \(\frac{n}{n-1}\sigma^{2}\)
03
Proof of Stochastic Convergence
A sequence of random variables converges stochastically to a constant if the expected value of the sequence converges to the constant as the sequence's index increases. Here, as \(n \to \infty\), \(\frac{n}{n-1}\) tends to 1, which means \(\frac{n}{n-1}\sigma^{2}\) tends to \(\sigma^{2}\). Therefore, \(\frac{n}{n-1}S_{n}^{2}\) converges stochastically to \(\sigma^{2}\) as \(n \to \infty\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Sample Variance
The sample variance, denoted as \(S_{n}^{2}\), is a measure of how much the individual data points in a sample deviate from the mean value of that sample. It provides insight into the spread or variability within a data set. For a random sample of size \(n\), the sample variance is given by the formula:
\[ S_{n}^{2} = \frac{1}{n}\sum_{i=1}^{n} (X_i - \mu)^{2} \]
Here:
\[ S_{n}^{2} = \frac{1}{n}\sum_{i=1}^{n} (X_i - \mu)^{2} \]
Here:
- \(X_i\) is the \(i^{th}\) observation in the sample.
- \(\mu\) is the population mean.
Expectation
Expectation, also known as the expected value, is fundamental in probability and statistics. It represents the average value or mean of a random variable you would expect to find if you could repeat an experiment infinite times. Mathematically, for a random variable \(X\) with possible values \(x_1, x_2, \ldots, x_n\) and corresponding probabilities \(p(x_1), p(x_2), \ldots, p(x_n)\), the expectation is:
\[ E(X) = \sum_{i} x_i \cdot p(x_i) \]
Expectation has properties that make it particularly useful:
Understanding expectation helps you predict the long-term average outcome of a random process.
\[ E(X) = \sum_{i} x_i \cdot p(x_i) \]
Expectation has properties that make it particularly useful:
- Linearity: \(E(aX + b) = aE(X) + b\).
- If \(X_i\) are independent, \(E(\sum X_i) = \sum E(X_i)\).
Understanding expectation helps you predict the long-term average outcome of a random process.
Normal Distribution
The normal distribution is a probability distribution widely used in statistics. It describes how the values of a variable are distributed. It is characterized by the symmetric bell-shaped curve. The distribution is completely determined by its mean (\(\mu\)) and variance (\(\sigma^2\)). Here are its key features:
The normal distribution is crucial because many natural phenomena and measurement errors tend to follow it.
It also plays a significant role in inferential statistics, where it's used to determine probabilities and make predictions.
- Symmetrical around the mean: The left and the right side of the curve are mirror images.
- Mean, median, and mode all coincide at the peak.
- Follows the empirical rule: approximately 68% of data falls within one standard deviation (\(\sigma\)), 95% within two, and 99.7% within three.
The normal distribution is crucial because many natural phenomena and measurement errors tend to follow it.
It also plays a significant role in inferential statistics, where it's used to determine probabilities and make predictions.
Convergence of Random Variables
Convergence of random variables is a concept in probability theory that describes how a sequence of random variables behaves as the number of terms grows. Stochastic convergence is one type of convergence where a sequence converges to a random variable or constant in probability. Stochastic convergence is defined as follows:
If a sequence of random variables \(X_n\) converges stochastically to \(X\), then for any small \(\epsilon > 0\):
\[ P(|X_n - X| > \epsilon) \to 0 \quad \text{as} \quad n \to \infty \]
In the context of our exercise, the scaled sample variance \(\frac{n}{n-1}S_{n}^{2}\) converges stochastically to \(\sigma^{2}\) as \(n\) increases. This means that with more samples, the value of our sample variance gets closer to the true variance of the population, \(\sigma^{2}\), making our estimation more reliable with larger samples. This concept is fundamental in ensuring the robustness of statistical estimates.
If a sequence of random variables \(X_n\) converges stochastically to \(X\), then for any small \(\epsilon > 0\):
\[ P(|X_n - X| > \epsilon) \to 0 \quad \text{as} \quad n \to \infty \]
In the context of our exercise, the scaled sample variance \(\frac{n}{n-1}S_{n}^{2}\) converges stochastically to \(\sigma^{2}\) as \(n\) increases. This means that with more samples, the value of our sample variance gets closer to the true variance of the population, \(\sigma^{2}\), making our estimation more reliable with larger samples. This concept is fundamental in ensuring the robustness of statistical estimates.