Chapter 4: Problem 13
Let \(f\) be differentiable at \(x_{0} \in(a, b)\) and let \(c\) be a constant. Find the limit $$ \lim _{h \rightarrow 0} \frac{f\left(x_{0}+c h\right)-f\left(x_{0}-c h\right)}{h} $$
Short Answer
Expert verified
The limit is \(2c f'(x_0)\).
Step by step solution
01
Express the Problem in Terms of Derivative
Recall the definition of the derivative of a function \( f \) at a point \( x_0 \):\[ f'(x_0) = \lim_{h \to 0} \frac{f(x_0 + h) - f(x_0)}{h} \]Our task involves the expression \[ \lim_{h \to 0} \frac{f(x_0 + ch) - f(x_0 - ch)}{h} \]This is not exactly the standard definition of the derivative, but resembles it as we can manipulate it terms of \( h \) and \( c \).
02
Decompose and Re-express the Limit
Observe that the given limit can be decomposed using a change of variables both forward and backward:- Let \( h' = ch \) so that \( ch = h' \).Consider the limit:\[ \lim_{h \to 0} \frac{f(x_0 + ch) - f(x_0 - ch)}{h} = \lim_{h' \to 0} \frac{f(x_0 + h') - f(x_0 - h')}{h'/c} \]Factoring \( 1/c \) out,\[ = c \lim_{h' \to 0} \frac{f(x_0 + h') - f(x_0 - h')}{h'} \].
03
Use Symmetric Derivative Expression
The expression \( \lim_{h'\to 0} \frac{f(x_0 + h') - f(x_0 - h')}{h'} \) is actually the symmetric derivative of \( f \) at \( x_0 \), which evaluates to \( 2f'(x_0) \) if it exists:\[ c \cdot 2f'(x_0) = 2c f'(x_0). \]
04
Conclude with Derived Limit
Thus, the limit resolves to:\[ \boxed{2c f'(x_0)} \]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Differentiable
In calculus, when we say a function is differentiable at a certain point, we mean it has a derivative there. A derivative represents the slope of the tangent line to the curve at that specific point. For a function to be differentiable, it must be smooth, meaning there are no breaks, corners, or vertical tangents at the point.
Consider the derivative as a measure of the instantaneous rate of change of the function with respect to its input variable. Mathematically, we express it as:
Consider the derivative as a measure of the instantaneous rate of change of the function with respect to its input variable. Mathematically, we express it as:
- \[f'(x_0) = \lim_{h \to 0} \frac{f(x_0 + h) - f(x_0)}{h}\]
Limit
The limit is a fundamental concept in calculus that helps us understand how functions behave as they approach a specific point. It evaluates how a function approaches a certain value as the input gets arbitrarily close to a certain point. In the context of derivatives, limits are used to define the derivative itself.
When we consider the exercise's expression:
When we consider the exercise's expression:
- \[\lim_{h \rightarrow 0} \frac{f(x_0 + ch) - f(x_0 - ch)}{h}\]
Symmetric Derivative
The symmetric derivative is a variant of the standard derivative that considers changes on both sides of a point. Where the standard derivative looks at changes in one direction (either forward or backward), the symmetric derivative takes the form:
The symmetric derivative often simplifies to a multiple of the conventional derivative if it exists and the function is sufficiently well behaved. For example, in our solved exercise, it provides symmetry around \(x_0\) and leads to the result \(2f'(x_0)\), showing how it offers a different perspective on the derivative that complements the traditional approach. Embracing both derivatives offers broader understanding and tools for tackling a variety of mathematical problems.
- \[\lim_{h'\to 0} \frac{f(x_0 + h') - f(x_0 - h')}{h'}\]
The symmetric derivative often simplifies to a multiple of the conventional derivative if it exists and the function is sufficiently well behaved. For example, in our solved exercise, it provides symmetry around \(x_0\) and leads to the result \(2f'(x_0)\), showing how it offers a different perspective on the derivative that complements the traditional approach. Embracing both derivatives offers broader understanding and tools for tackling a variety of mathematical problems.