Chapter 4: Problem 30
Prove that, if \(G\) is a 3-connected plane graph, then its geometric dual is a simple graph.
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Chapter 4: Problem 30
Prove that, if \(G\) is a 3-connected plane graph, then its geometric dual is a simple graph.
These are the key concepts you need to understand to accurately answer the question.
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(i) Use Euler's formula to prove that, if \(G\) is a connected planar graph of girth 5 with \(n\) vertices and \(m\) edges, then \(m \leq 5 / 3(n-2)\). Deduce that the Petersen graph is non-planar. (ii) Obtain an inequality, generalizing that in part (i), for connected planar graphs of girth \(r\).
Let \(G\) be a simple graph with at least 11 vertices, and let \(\bar{G}\) be its complement. (i) Prove that \(G\) and \(\bar{G}\) cannot both be planar. (In fact, a similar result holds if 11 is replaced by 9 , though this is difficult to prove.) (ii) Find a graph \(G\) with eight vertices for which \(G\) and \(\bar{G}\) are both planar.
Use duality to prove that there exists no plane graph with five faces, each pair of which shares an edge in common.
Which complete graphs and complete bipartite graphs are planar?
(i) Give an example to show that, if \(G\) is a connected plane graph, then any spanning tree in \(G\) corresponds to the complement of a spanning tree in \(G^{*}\). (ii) Prove the result of part (i) in general. (This result will also be needed in Chapter 7.)
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