Chapter 8: Problem 1
For each of these power series, find the radius of convergence \(R\), by using the ratio test. (The sums start at \(n=0\).) (a) \(\sum \frac{x^{n}}{3^{2 n+1}}\) (b) \(\sum n ! x^{n}\) (c) \(\sum n^{2} x^{n}\) (d) \(\sum \frac{x^{n}}{n !}\)
Short Answer
Expert verified
(a) \( R = 9 \), (b) \( R = 0 \), (c) \( R = 1 \), (d) \( R = \infty \)
Step by step solution
01
Identify the General Term for (a)
For \( \sum \frac{x^n}{3^{2n+1}} \), the general term \( a_n \) is \( \frac{x^n}{3^{2n+1}} \).
02
Apply the Ratio Test for (a)
According to the ratio test, the radius of convergence \( R \) is given by \[ \lim_{n \to \infty} \left| \frac{a_{n+1}}{a_n} \right| = \lim_{n \to \infty} \left| \frac{x^{n+1} / 3^{2(n+1)+1}}{x^n / 3^{2n+1}} \right| = \lim_{n \to \infty} \left| \frac{x \cdot 3^{2n+1}}{3^{2n+3}} \right| = \lim_{n \to \infty} \left| \frac{x}{9} \right|. \]This simplifies to \( \left| \frac{x}{9} \right| < 1 \), leading to the radius of convergence \( R = 9 \).
03
Identify the General Term for (b)
For \( \sum n! x^n \), the general term \( a_n \) is \( n! x^n \).
04
Apply the Ratio Test for (b)
For the series \( \lim_{n \to \infty} \left| \frac{(n+1)! x^{n+1}}{n! x^n} \right| = \lim_{n \to \infty} \left| (n+1)x \right| = \infty \text{ for any } x eq 0. \)Thus, the series converges only when \( x = 0 \), so the radius of convergence \( R = 0 \).
05
Identify the General Term for (c)
For \( \sum n^2 x^n \), the general term \( a_n \) is \( n^2 x^n \).
06
Apply the Ratio Test for (c)
Apply the ratio test: \[ \lim_{n \to \infty} \left| \frac{(n+1)^2 x^{n+1}}{n^2 x^n} \right| = \lim_{n \to \infty} \left| \frac{(n+1)^2}{n^2} x \right| = \lim_{n \to \infty} \left| \left(1 + \frac{1}{n}\right)^2 x \right| = \left| x \right|. \]Thus, the radius of convergence \( R = 1 \).
07
Identify the General Term for (d)
For \( \sum \frac{x^n}{n!} \), the general term \( a_n \) is \( \frac{x^n}{n!} \).
08
Apply the Ratio Test for (d)
Apply the ratio test: \[ \lim_{n \to \infty} \left| \frac{x^{n+1} / (n+1)!}{x^n / n!} \right| = \lim_{n \to \infty} \left| \frac{x}{n+1} \right| = 0 \text{ for any } x. \]Since the limit is 0, the series converges for all \( x \), suggesting the radius of convergence \( R = \infty \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Power Series
A power series is an infinite sum of terms in the form of a constant multiplied by a variable raised to a power, typically expressed as
- \( \sum_{n=0}^{\infty} a_n x^n \)
- where each \( a_n \) is a constant coefficient and \( x \) is a variable.
Ratio Test
The ratio test is a powerful tool for determining the convergence of a series, especially useful for power series. This test specifically examines the limit of the ratio of consecutive terms. The ratio test for a series \( \sum a_n \) is determined as follows:
- Calculate \( \lim_{n \to \infty} \left| \frac{a_{n+1}}{a_n} \right| \).
- If this limit is less than 1, the series converges.
- If the limit is greater than 1, or equals infinity, the series diverges.
- If the limit is exactly 1, the test is inconclusive.
General Term Identification
Identifying the general term \( a_n \) in a power series is crucial for applying convergence tests. For instance, given the series \( \sum \frac{x^n}{3^{2n+1}} \), we derive the general term as \( a_n = \frac{x^n}{3^{2n+1}} \). This expression isolates the essential pattern in the series terms, allowing us to examine their behavior as \( n \to \infty \). Accurately identifying \( a_n \) equips us to use tests like the ratio test efficiently, which leads to insights about the series' convergence characteristics.
Convergence Analysis
Convergence analysis determines where a power series converges, allowing mathematicians to fully understand its behavior. When conducting convergence analysis, using the ratio test permits the computation of the radius of convergence, \( R \), which is the number representing the extent around a point at which a series converges. For example, the analysis of \( \sum \frac{x^n}{n!} \) using the ratio test shows that regardless of \( x \), the limit approaches 0, implying convergence for all \( x \).
- This results in an infinite radius of convergence, \( R = \infty \).