/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 2 Let \(f_{n}(x)=\sin n x .\) Show... [FREE SOLUTION] | 91Ó°ÊÓ

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Let \(f_{n}(x)=\sin n x .\) Show that \(f_{n}(x)\) does not converge pointwise on \(\mathbb{R}\).

Short Answer

Expert verified
The function \( f_n(x) = \sin(nx) \) does not converge pointwise on \( \mathbb{R} \) because \( \sin(nx) \) oscillates without approaching a single limit for any fixed \( x \).

Step by step solution

01

Understanding Pointwise Convergence

To determine pointwise convergence of \( f_n(x) \), we need to check if for every fixed \( x \in \mathbb{R} \), the sequence \( \{ f_n(x) \} \) converges to a limit as \( n \rightarrow \infty \). Specifically, we want \( \lim_{n \to \infty} \sin(nx) \) to exist for each \( x \).
02

Analyzing the Behavior of \( \sin(nx) \)

The sine function \( \sin(nx) \) oscillates between -1 and 1 for any real number \( n \). Therefore, it is critical to check if a pattern or limit emerges as \( n \) increases. For a fixed \( x \), as \( n \rightarrow \infty \), multiple terms \( nx \) modulo \( 2\pi \) fill the interval \([0, 2\pi]\). This dense filling causes \( \sin(nx) \) to oscillate without settling to a limit.
03

Counterexample for Different \( x \) Values

Let's consider a specific example like \( x = \frac{2\pi}{3} \). Then \( \sin(n\frac{2\pi}{3}) \) results in values that alternate periodically. For instance, \( \sin(n\frac{2\pi}{3}) \) repeats with a cycle of resistance to a fixed limit. Since the result depends on the argument \( n x \), the sine function does not converge to any single value as \( n \rightarrow \infty \). This is true for any irrational multiple of \( \pi \), displaying behavior that defies convergence.
04

Using Density Argument

The set \( \{ nx \mod 2\pi | n \in \mathbb{N} \} \) is dense in the interval \([0, 2\pi]\) when \( x \) is irrational. This density leads to \( \sin(nx) \) attaining all values in \([-1, 1] \) frequently as \( n \) increases. Consequently, the sequence \( \{ \sin(nx) \} \) will not converge for any fixed irrational \( x \), implying that pointwise convergence fails over \( \mathbb{R} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sine Function
The sine function is a fundamental concept in trigonometry, often denoted as \( \sin(x) \). It is a periodic function that oscillates between -1 and 1, and its graph forms a wave-like pattern repeating every \( 2\pi \) units. Because of this periodic nature, the values it takes are predictable and cyclic for integer multiples of \( x \).

- **Understanding the Sine Wave:** The sine wave reaches its maximum value of 1 at \( x = \frac{\pi}{2} + 2k\pi \) and its minimum value of -1 at \( x = \frac{3\pi}{2} + 2k\pi \), where \( k \) is an integer. - **Properties:** It is an odd function, meaning \( \sin(-x) = -\sin(x) \), and it's symmetric about the origin. - **Applications:** This function is integral to modeling phenomena like sound waves, light waves, and tidal waves in physics and engineering.

The sine function's oscillatory nature plays a key role in pointwise convergence as it examines if \( \sin(nx) \) can stabilize to a single value as \( n \) grows indefinitely.
Oscillation
Oscillation refers to how the sine function fluctuates between its minimum and maximum values as \( n \) varies. This behavior is intrinsic to functions like \( \sin(nx) \) in trigonometry. - **Oscillatory Nature:** The sine function is perfectly oscillatory. It neither settles to a constant value nor monotonically increases or decreases.

- **Relevance to Convergence:** If a function oscillates indefinitely as its variable increases, it generally suggests that pointwise convergence does not occur. Every time \( n \) increases, \( nx \mod 2\pi \) changes value, producing a new point on the wave.- **Visualizing Oscillation:** By observing the sine wave's movement, it’s clear that without a stabilizing force or endpoint, the oscillatory pattern disrupts any potential for convergence. For \( \sin(nx) \), this means continuously ranging through values between -1 and 1, absent of any trend towards settling at a single point.

Oscillation is a critical factor explaining why \( \sin(nx) \) fails to converge pointwise across \( \mathbb{R} \). Without settling at a consistent value, the notion of convergence can't be applied.
Irrational Multiples
Irrational multiples introduce unique behaviors in the sine function. Specifically, choosing \( x \) as an irrational multiple of \( \pi \) means that \( nx \) fills the space between \([0, 2\pi]\) densely without repeating. - **Defining Irrational Multiples:** These are numbers that cannot be expressed as a fraction \( \frac{p}{q} \) where \( p \) and \( q \) are integers. For example, \( \pi \times n \) for any irrational \( n \) behaves unpredictably.- **Effects on \( \sin(nx) \):** Using an irrational multiple like \( \sqrt{2} \times \pi \), as \( n \) varies, the argument \( n\sqrt{2}\pi \mod 2\pi \) never forms a repeating sequence. Consequently, \( \sin(nx) \) touches nearly every value within its range consistently and thereby demonstrates no tendency to stabilize.

An irrational \( x \) is key in showing why certain sequences like \( \sin(nx) \) can't achieve pointwise convergence, as the non-repeating sequence prevents the function from approaching any fixed value.
Density Argument
The density argument deals with how the set of numbers \( \{ nx \mod 2\pi | n \in \mathbb{N} \} \) behaves, particularly for irrational values of \( x \). - **Understanding Density:** In mathematics, a set is dense in an interval if it comes arbitrarily close to any point within the interval. For example, the rational numbers are dense in the real numbers.- **Application to \( \sin(nx) \):** For an irrational \( x \), the set \( \{ nx \mod 2\pi \} \) becomes dense in \([0, 2\pi]\), meaning \( nx \) repeatedly reaches very close to every point in \([0, 2\pi]\). As a result, \( \sin(nx) \) spans values between -1 and 1 frequently without settling to any particular one.

This density argument is essential in proving why \( \sin(nx) \) does not converge pointwise: the function persists in encountering every possible value between its maximum and minimum, invalidating the potential for convergence at any given fixed \( x \).

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