Chapter 14: Problem 2
Let \(f(x)=x|x| .\) Determine \(f^{\prime}\left(0^{+}\right)\) and \(f^{\prime}\left(0^{-}\right) ;\) does \(f^{\prime}(0)\) exist?
Short Answer
Expert verified
Both \( f^{\prime}(0^{+}) \) and \( f^{\prime}(0^{-}) \) are zero, so \( f^{\prime}(0) \) exists and is zero.
Step by step solution
01
Understand the Function
The function is given by \( f(x) = x|x| \). This function is defined as \( f(x) = x^2 \) when \( x \geq 0 \), and \( f(x) = -x^2 \) when \( x < 0 \). We'll use these expressions to find the one-sided derivatives.
02
Find the Right-hand Derivative
The right-hand derivative \( f^{\prime}(0^{+}) \) is the derivative of \( f(x) \) as \( x \) approaches 0 from the positive side. For \( x \geq 0 \), \( f(x) = x^2 \). The derivative is \( f^{\prime}(x) = 2x \). Evaluating this at \( x = 0 \), we get \( f^{\prime}(0^{+}) = 2 \times 0 = 0 \).
03
Find the Left-hand Derivative
The left-hand derivative \( f^{\prime}(0^{-}) \) is the derivative of \( f(x) \) as \( x \) approaches 0 from the negative side. For \( x < 0 \), \( f(x) = -x^2 \). The derivative is \( f^{\prime}(x) = -2x \). Evaluating this at \( x = 0 \), we get \( f^{\prime}(0^{-}) = -2 \times 0 = 0 \).
04
Determine if the Derivative Exists
For \( f^{\prime}(0) \) to exist, both the right-hand derivative \( f^{\prime}(0^{+}) \) and the left-hand derivative \( f^{\prime}(0^{-}) \) must be equal. Since \( f^{\prime}(0^{+}) = 0 \) and \( f^{\prime}(0^{-}) = 0 \), both derivatives are equal, so \( f^{\prime}(0) \) exists and is zero.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Derivative
In calculus, the concept of a derivative is fundamental. It tells us how a function changes at any given point. Think of the derivative as the slope of the tangent line to the graph of the function at a specific point. In simple terms, it measures the rate at which one quantity changes with respect to another. For example, if you know the derivative of a position with respect to time, you know the velocity.
The derivative of a function at a point may be found using the limit definition:
The derivative of a function at a point may be found using the limit definition:
- Given a function \( f(x) \), the derivative \( f'(x) \) is defined as \( f'(x) = \lim_{h \to 0} \frac{f(x+h) - f(x)}{h} \).
Right-hand derivative
The right-hand derivative provides insight into how a function behaves as the input approaches from the right, or positive side. It assumes that we are only interested in values greater than or equal to a particular point. For a function \( f(x) \), the right-hand derivative at \( x = a \) is given by:
In our specific exercise, for the function \( f(x) = x|x| \), we focused on the expression \( f(x) = x^2 \) for \( x \geq 0 \). By evaluating the derivative using this approach, we found that \( f^{\prime}(0^{+}) = 0 \).
- \( f^{\prime}(a^{+}) = \lim_{h \to 0^{+}} \frac{f(a+h) - f(a)}{h} \)
In our specific exercise, for the function \( f(x) = x|x| \), we focused on the expression \( f(x) = x^2 \) for \( x \geq 0 \). By evaluating the derivative using this approach, we found that \( f^{\prime}(0^{+}) = 0 \).
Left-hand derivative
The left-hand derivative helps us understand how a function behaves as the input approaches from the left, or negative side. It examines the behavior of the function for values less than the particular point of interest. The left-hand derivative for a function \( f(x) \) at \( x = a \) is written as:
In the case of the function \( f(x) = x|x| \) when \( x < 0 \), we used the expression \( f(x) = -x^2 \). Calculating the derivative in this region, we found \( f^{\prime}(0^{-}) = 0 \).
- \( f^{\prime}(a^{-}) = \lim_{h \to 0^{-}} \frac{f(a+h) - f(a)}{h} \)
In the case of the function \( f(x) = x|x| \) when \( x < 0 \), we used the expression \( f(x) = -x^2 \). Calculating the derivative in this region, we found \( f^{\prime}(0^{-}) = 0 \).
Differentiability
For a function to be considered differentiable at a specific point, two main criteria must be satisfied:
According to our exercise, for the function \( f(x) = x|x| \), we evaluated the right-hand derivative \( f^{\prime}(0^{+}) \) and the left-hand derivative \( f^{\prime}(0^{-}) \). With both being equal to 0, it confirmed that the derivative \( f^{\prime}(0) \) exists and the function is indeed differentiable at \( x = 0 \). Knowing whether or not a function is differentiable at various points is crucial for more advanced studies and applications in calculus.
- The right-hand and left-hand derivatives at that point must exist.
- They must be equal to each other.
According to our exercise, for the function \( f(x) = x|x| \), we evaluated the right-hand derivative \( f^{\prime}(0^{+}) \) and the left-hand derivative \( f^{\prime}(0^{-}) \). With both being equal to 0, it confirmed that the derivative \( f^{\prime}(0) \) exists and the function is indeed differentiable at \( x = 0 \). Knowing whether or not a function is differentiable at various points is crucial for more advanced studies and applications in calculus.