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Chapter 4: Q 63. (page 387)

In the following exercise, solve the systems of equations by elimination.

4x+3y=220x+15y=10

Short Answer

Expert verified

The given system has infinitely many solutions.

Step by step solution

01

Step 1. Given Information 

The given linear equations are :

4x+3y=220x+15y=10

02

Step 2. Calculating the value of y

To calculate the value of y, we have to eliminate the xterm. For which we will do the following changes in the equation, so that xterm can be easily eliminated.

Multiply the first equation by-5,

localid="1644751669758" -54x+3y=2-20x-15y=-10

now, the equations are,

-20x-15y=-1020x+15y=10

now simply add the equations

-20x-15y=-1020x+15y=100=0

this means that the above equation is satisfied for all the values of yandx.

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Most popular questions from this chapter

A commercial jet can fly 868miles in 2hours with a tailwind but only 792miles in 2hours into a headwind. Find the speed of the jet in still air and the speed of the wind.

The sum of two number is 30. One number is 4less than the other. Find the numbers.

In the following exercises, solve the systems of equations by elimination.

2x+9y=-43x+13y=-7

Without graphing, determine the number of solutions and then classify the system of equations.

(a)y=-2x-44x+2y=9(b)3x+2y=22x+y=1

Solve the system of equations by substitution

2x+y=5x-2y=-15
See all solutions

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