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91Ó°ÊÓ

Solve the system by equations:

x+y−z=02x+4y−2z=63x+6y−3z=9

Short Answer

Expert verified

There are infinitely many number of solutions of given system of equations.

Step by step solution

01

Step 1. Given Information

We are given a system of linear equation,

x+y−z=0-(1)2x+4y−2z=6-(2)3x+6y−3z=9-(3)

02

Step 2. Solving the equations 

Multiplying by 3in second equation and 2in third equation, we get

localid="1644580091504" 3(2x+4y-2z)=3(6)6x+12y-6z=18-(4)

2(3x+6y-3z=2(9)6x+12y-6z=18-(5)

Now, subtracting the fourth and fifth equations, we get

6x-6x+12y-12y-6z+6z=18-180=0

This is true, hence the system has infinitely many solutions.

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