91Ó°ÊÓ

The system of inequality $\left\{\begin{array}{l}4x+y>6\\ 3x-y≤12\end{array}\right.$

To find if the ordered pair $(2,-1)$ is a solution to the system of inequality.

Substitute $(2,-1)$in the inequality,

$4x+y>6$

$4\left(2\right)+(-1)>6$

$8-1>6$

$7>6$ is true.

Substitute $(2,-1)$in the inequality,

$3x-y≤12$

$3\left(2\right)-(-1)≤12$

$6+1≤12$

$7≤12$is true.

The ordered pair $(2,-1)$made both the inequality true.

So the ordered pair $(2,-1)$ is the solution to the syetm of inequality.

The system of inequality $\left\{\begin{array}{l}4x+y>6\\ 3x-y≤12\end{array}\right.$

To find if the ordered pair $(3,-2)$ is the solution to the system of inequality.

Substitute $(3,-2)$in the first inequality,

$4\left(3\right)+(-2)>6$

$12-2>6$

$10>6$ is true.

Substitute $(3,-2)$in the inequality,

$3x-y≤12$

$3\left(3\right)-(-2)≤12$

$9+2≤12$

$11≤12$is true.

An ordered pair $(3,-2)$made both the inequality true.

So the ordered pair $(3,-2)$ is a solution to the system of inequality.