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91Ó°ÊÓ

Solve compound Inequalities with "and"

-3(x+4)<0and-1(3x-1)≤7

Short Answer

Expert verified

The number that make both Inequalities true is x ≥ - 2

Interval Notation: [-2, ∞ )

Step by step solution

01

Step 1.Given information

-3(x+4)<0and-1(3x-1)≤7

02

Step 2.Solve Each Inequalities and Draw Graph 

-3(x+4)<0⇒-3(x+4)-3>0-3(WhenweMultiplyordividebynegativenumber,inequalitieschanges)⇒x+4>0⇒x+4-4>0-4⇒x>-4

-1(3x-1)≤7⇒-1(3x-1)-1≥7-1⇒3x-1≥-7⇒3x-1+1≥-7+1⇒3x≥-6⇒3x3≥-63⇒x≥-2

03

Step 3.Graph of each solution

Graph of -3(x+4)<0

Graph of-1(3x-1)≤7

Merging both graph

04

Step 4. Interval Notation

The number that make both Inequalities true is x ≥ - 2

Interval Notation: [-2, ∞ )

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