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91Ó°ÊÓ

Solve compound inequalities with "and"

4(2x-1)≤12and2(x+1)<4

Short Answer

Expert verified

The Number That make both Inequalities true is x < 1

Interval Notation: (-∞,1 )

The Graph of Solution is

Step by step solution

01

Step 1.Given information

4(2x-1)≤12and2(x+1)<4

02

Step 2.Solve each inequalities

4(2x-1)≤12⇒4(2x-1)4≤124⇒2x-1≤3⇒2x-1+1≤3+1⇒2x≤4⇒2x2≤42⇒x≤2and2(x+1)<4⇒2(x+1)2<42⇒x+1<2⇒x+1-1<2-1⇒x<1

03

Step 3.Graph Each Solution

Graph of4(2x-1)≤12

Graph of 2(x+1)<4

04

Step 4. Merge The Graph of each Solution

05

Step 5.Interval Notation

The number that make both inequalities true is

Interval Notation:

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