91Ó°ÊÓ

We have given the following inequality :-

$a+\frac{3}{4}â‰\yen \frac{7}{10}$

Now to solve this inequality, subtract $\frac{3}{4}$from both sides, then we have :-

$$\begin{gathered} a+\frac{3}{4}-\frac{3}{4}â‰\yen \frac{7}{10}-\frac{3}{4} \\ ⇒aâ‰\yen -\frac{1}{20} \end{gathered}$$

So the solution interval for this inequality is :-

$[\frac{-1}{20},∞)$.

Representation of solution on number line is as following :-

Here we have given the following inequality :-

$8x>72$.

To solve this inequality divide both sides by 8, then we have :-

$$\begin{gathered} \frac{8x}{8}>\frac{72}{8} \\ ⇒x>9 \end{gathered}$$

So the solution interval is $\left(9,∞\right)$.

Representation of solution on number line is as following :-

Now we have following inequality :-

$20>\frac{2}{5}h$.

To solve this inequality multiply both sides by $\frac{5}{2}$, then we have :-

$$\begin{gathered} 20*\frac{5}{2}>\frac{2}{5}h*\frac{5}{2} \\ ⇒50>h \\ orh<50 \end{gathered}$$

Then the solution interval is :-

$\left(-∞,50\right)$.

Representation of solution on number line is as following :-