Q. 247 Chi has $11.30 in dimes and quar... [FREE SOLUTION]

91影视

Intermediate Algebra

OPENSTAX

$Math Studyset 91影视 Explanations$ Math

OER 2017 Edition 路 1346 pages

ISBN: 9780998625720

Chapter 2: Q. 247 (page 164)

Chi has $11.30 in dimes and quarters. The number of Dimes is three more than three times the number of quarters. How many of each are there?

Short Answer

Expert verified

The number of Quarters is = 20

The number of Dimes is = 63

Step by step solution

Step 1. Given Data

Chi has $11.30 in dimes and quarters. The number of Dimes is three more than three times the number of quarters.

Step 2. To Find

How many of each are there?

Step 3. Explanation

Let The number of Quarters is = P

Then, The number of Dimes is = 3P+3

Type	$N u m b e r 脳 V a l u e ($) = T o t a l V a l u e ($)$
Quarters	P	0.25	0.25P
Dimes	3P+3	0.1	0.1(3P+3)
			$11.30

Step 4. Calculation

after analyzing the table, We see that -

$0.25 P + 0.1 (3 P + 3) = 11.30$

$0.25 P + 0.3 P + 0.3 = 11.30$

$0.55 P = 11.30 - 0.3$

$0.55 P = 11$

$P = 20$

The number of Quarters is = 20

The number of Dimes is = (3P+3)

= $(3 脳 20 + 3)$

= 63

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91影视

Chi has $11.30 in dimes and quarters. The number of Dimes is three more than three times the number of quarters. How many of each are there?

Short Answer

Step by step solution

Step 1. Given Data

Step 2. To Find

Step 3. Explanation

Step 4. Calculation

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