Q. 243 Michaela has $2.05 in dimes and ... [FREE SOLUTION]

91影视

Intermediate Algebra

OPENSTAX

$Math Studyset 91影视 Explanations$ Math

OER 2017 Edition 路 1346 pages

ISBN: 9780998625720

Chapter 2: Q. 243 (page 164)

Michaela has $2.05 in dimes and nickels in her change purse. She has seven more dimes than nickels. How many coins of each type does she have?

Short Answer

Expert verified

The number of Dimes is = 16

The number of Nickels is = 9

Step by step solution

Step 1. Given Data

Michaela has $2.05 in dimes and nickels in her change purse. She has seven more dimes than nickels.

Step 2. To Find

How many coins of each type does she have?

Step 3. Explanation

Let the number of Nickels is = P

Then the number of Dimes is = P+7

Type	$N u m b e r 脳 V a l u e ($) = T o t a l V a l u e ($)$
Nickels	P	0.05	0.05P
Dimes	P+7	0.1	0.1(P+7)
			$2.05

Step 4. Calculation

after analyzing the table, We see that -

$0.05 P + 0.1 (P + 7) = 2.05$

$0.05 P + 0.1 P + 0.7 = 2.05$

$0.05 P + 0.1 P = 2.05 - 0.7$

$0.15 P = 1.35$

$P = 9$

The number of Nickels is = 9

The number of Dimes is = $(P + 7)$

= $(9 + 7)$

= 16

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91影视

Michaela has $2.05 in dimes and nickels in her change purse. She has seven more dimes than nickels. How many coins of each type does she have?

Short Answer

Step by step solution

Step 1. Given Data

Step 2. To Find

Step 3. Explanation

Step 4. Calculation

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